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Test: RCC- 2 - SSC JE MCQ


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12 Questions MCQ Test - Test: RCC- 2

Test: RCC- 2 for SSC JE 2024 is part of SSC JE preparation. The Test: RCC- 2 questions and answers have been prepared according to the SSC JE exam syllabus.The Test: RCC- 2 MCQs are made for SSC JE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: RCC- 2 below.
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Test: RCC- 2 - Question 1

If the permissible compressive and tensile stresses in a single reinforced beam are 50 kg/cm2 and 1400 kg/cm2 respectively and the modular ratio is 18, the percentage of the steel required for an economic section, is

Detailed Solution for Test: RCC- 2 - Question 1

Taking Moment of area of tension and compression zone for a singly reinforced beam:

Where,

Xc = critical depth or economic depth of neutral axis

m = modular ratio

Ast = area of steel required for balanced section

 

m = 18

c = 50 kg/cm2

t = 1400 kg/cm2


Test: RCC- 2 - Question 2

Though the effective depth of a T-beam is the distance between the top compression edge to the centre of the tensile reinforcement, for heavy loads it is taken as:

Detailed Solution for Test: RCC- 2 - Question 2

For all cases, Effective depth of the beam cross-section is to be taken as:

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Test: RCC- 2 - Question 3

If the diameter of main reinforcement in a slab is 16 mm, the concrete cover to main bar according to IS 456:2000 is:

Detailed Solution for Test: RCC- 2 - Question 3

According to IS 456: 2000, minimum nominal cover to all bars in the slab is 20mm. According to new code, nominal cover does not depend upon the diameter of bar used.

Test: RCC- 2 - Question 4

The working stress method of design of RC members is known as:-

Detailed Solution for Test: RCC- 2 - Question 4

Working stress method: working stress method is based on elastic theory. Concrete and steel are assumed to act together elastically and follow hook’s law. This method follows a deterministic approach as it assumes that the loads, factor of safety and permissible stresses are accurately known. In this method material strengths are not fully utilised in designing the member.

Limit state method: This method follows a non-deterministic approach as it adopts probable loads and probable strengths of materials as per actual or based on experience or observations depending upon the situations. Material strengths are fully utilised in designing the member.

Test: RCC- 2 - Question 5

The time in minutes, for the member to reach the limit state of structural inadequacy in a standard fire test is known as:

Detailed Solution for Test: RCC- 2 - Question 5

As per Bureau of Indian standards,

Period of structural adequacy under fire: The time (t), in minutes, for the member to reach the limit state of structural inadequacy in a standard fire test.

Test: RCC- 2 - Question 6

The load factors for live and dead load are taken respectively as:

Test: RCC- 2 - Question 7

The clear distance from the free end of the cantilever to the lateral restraint shall not exceed

Detailed Solution for Test: RCC- 2 - Question 7

As per IS 456:2000, slenderness limit for lateral stability of beam shall be:

Test: RCC- 2 - Question 8

The Design ultimate load on the short axially loaded column is computed by which of the following equation?

where,

fck = Characterstics strength of concrete

fy = characterstic strength of steel

Ac = Area of concrete in column cross-section

Asc = Area of steel in column in compression

Detailed Solution for Test: RCC- 2 - Question 8

As per IS 456 : 2000 In the Design of compression members the ultimate load on the short axially loaded column is:

Pu = 0.4fck Ac + 0.67fy Asc

where,

fck = Characterstics strength of concrete

fy = characterstic strength of steel

Ac = Area of concrete in column cross-section

Asc = Area of steel in column in compression

Test: RCC- 2 - Question 9

In a rear counterfort retaining wall, the main reinforcement is provided on the

Detailed Solution for Test: RCC- 2 - Question 9

Counterforts are firmly attached to the face slab as well as the base slab. The earth pressure acting on the face slab is transferred to the counterfort which deflects as vertical cantilever. The back of rear counterfort comes under tension and the front face is under compression. So the inclined (back) face of the rear counterfort should be provided with main reinforcement.

Test: RCC- 2 - Question 10

Deep beams are designed for

Detailed Solution for Test: RCC- 2 - Question 10

Deep beams are structural elements loaded as simple beams in which a significant amount of the load is carried to the supports by a compression force combining the load and the reaction. As a result, the strain distribution is no longer considered linear, and the shear deformations become significant when compared to pure flexure.

In view of ample shear strength, deep beams are primarily recommended as transfer girders. These members transfer loads through-loading face to supports in the transverse direction. The deep horizontal members predominantly fail in shear rather than flexure. These beams are characterized with small span-to-depth ratio. Pile caps, corbel, brackets, foundation walls and off-shore structures are few examples of RC deep beams.

According to IS 456-2000 a beam shall be deemed to be a deep beam when the ratio of effective span-to-overall depth, l/D is less than:

1) 2.0, for simply supported beam; and

2) 2.5, for a continuous beam.

Though different codes define deep beams in different clear span-to-depth ratios, as a general rule deep beams are recognized by their relatively small span-to-depth ratio.

Hence, Deep beams are designed for bending moment and checked for shear.

Test: RCC- 2 - Question 11

A doubly reinforced concrete beam has effective cover d’ to the centre of compression reinforcement. ‘xu’ is the depth of neutral axis, and d is the effective depth to the centre of tension reinforcement. What is the maximum strain in concrete at the level of compression reinforcement?

Detailed Solution for Test: RCC- 2 - Question 11

Test: RCC- 2 - Question 12

A reinforced concrete slab is 128 mm thick. The maximum size of reinforcement bar that can be used is:

Detailed Solution for Test: RCC- 2 - Question 12

IS 456:2000 limits the maximum diameter of reinforcing bars to 1/8th of the total thickness of the slab.

Dmax = 128/8 = 16 mm; Hence use 16 mm diameter bars.

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