JEE Exam  >  JEE Tests  >  Test: JEE Main 35 Year PYQs- Electrostatics - JEE MCQ

Test: JEE Main 35 Year PYQs- Electrostatics - JEE MCQ


Test Description

30 Questions MCQ Test - Test: JEE Main 35 Year PYQs- Electrostatics

Test: JEE Main 35 Year PYQs- Electrostatics for JEE 2024 is part of JEE preparation. The Test: JEE Main 35 Year PYQs- Electrostatics questions and answers have been prepared according to the JEE exam syllabus.The Test: JEE Main 35 Year PYQs- Electrostatics MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: JEE Main 35 Year PYQs- Electrostatics below.
Solutions of Test: JEE Main 35 Year PYQs- Electrostatics questions in English are available as part of our course for JEE & Test: JEE Main 35 Year PYQs- Electrostatics solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: JEE Main 35 Year PYQs- Electrostatics | 56 questions in 110 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
Test: JEE Main 35 Year PYQs- Electrostatics - Question 1

The nuclear charge (Ze) is non-uniformly distributed within a nucleus of radius R. The charge density ρ (r) [charge per unit volume] is dependent only on the radial distance r from the centre of the nucleus as shown in figure The electric field is only along the radial direction.

Q. The electric field at r = R is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 1

When the point of observation is on the surface of sphere then the whole charge inside the sphere (when distributed symmetrically about the centre) behaves as a point charge on the centre. Therefore until the charge distribution is symmetrical about the centre it does not matter what is the ratio a/R. The electric field remains constant and is equal to

Test: JEE Main 35 Year PYQs- Electrostatics - Question 2

The nuclear charge (Ze) is non-uniformly distributed within a nucleus of radius R. The charge density ρ (r) [charge per unit volume] is dependent only on the radial distance r from the centre of the nucleus as shown in figure The electric field is only along the radial direction.

Q. For a = 0, the value of d (maximum value of ρ as shown in the figure) is –

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 2

For a = 0, the graph is as shown. The equation for the graph line is


The charge in the dotted element shown in Fig (2) is dq = ρ × 4πr2dr

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: JEE Main 35 Year PYQs- Electrostatics - Question 3

The nuclear charge (Ze) is non-uniformly distributed within a nucleus of radius R. The charge density ρ (r) [charge per unit volume] is dependent only on the radial distance r from the centre of the nucleus as shown in figure The electric field is only along the radial direction.

Q. The electric field within the nucleus is generally observed to be linearly dependent on r. This implies.

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 3

If the volume charge density is constant then E ∝ r.

Test: JEE Main 35 Year PYQs- Electrostatics - Question 4

Consider an evacuated cylindrical chamber of height h having rigid conducting plates at the ends and an insulating curved surface as shown in the figure. A number of spherical balls made of a light weight and soft material and coated with a conducting material are placed on the bottom plate. The balls have a radius r <<h. Now a high voltage source (HV) is connected across the conducting plates such that the bottom plate is at +V0 and the top plate at –V0. Due to their conducting surface, the balls will get charged, will become equipotential with the plate and are repelled by it. The balls will eventually collide with the top plate, where the coefficient of restitution can be taken to be zero due to the soft nature of the material of the balls. The electric field in the chamber can be considered to be that of a parallel plate capacitor.
Assume that there are no collisions between the balls and the interaction between them is negligible. (Ignore gravity)

Q. Which one of the following statements is correct?

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 4

After colliding the top plate, the ball will gain negative charge and get repelled by the top plate and bounce back to the bottom plate.

Test: JEE Main 35 Year PYQs- Electrostatics - Question 5

Consider an evacuated cylindrical chamber of height h having rigid conducting plates at the ends and an insulating curved surface as shown in the figure. A number of spherical balls made of a light weight and soft material and coated with a conducting material are placed on the bottom plate. The balls have a radius r <<h. Now a high voltage source (HV) is connected across the conducting plates such that the bottom plate is at +V0 and the top plate at –V0. Due to their conducting surface, the balls will get charged, will become equipotential with the plate and are repelled by it. The balls will eventually collide with the top plate, where the coefficient of restitution can be taken to be zero due to the soft nature of the material of the balls. The electric field in the chamber can be considered to be that of a parallel plate capacitor.
Assume that there are no collisions between the balls and the interaction between them is negligible. (Ignore gravity)

Q. The aver age current in the steady state registered by the ammeter in the circuit will be

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 5



From (i), (ii) and (iii)

Test: JEE Main 35 Year PYQs- Electrostatics - Question 6

STATEMENT-1 : For practical purposes, the earth is used as a reference at zero potential in electrical circuits. and

STATEMENT-2 : The electrical potential of a sphere of radius R with charge Q uniformly distributed on the surface is given by 

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 6

Both the statements are true and statement-2 is the correct explanation of statement-1

Test: JEE Main 35 Year PYQs- Electrostatics - Question 7

On moving a charge of 20 coulomb by 2 cm, 2 J of work is done, then the potential difference between the points is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 7

Test: JEE Main 35 Year PYQs- Electrostatics - Question 8

If there are n capacitors in parallel connected to V volt source, then the energy stored is equal to

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 8

The equivalent capacitance of n identical capacitors of capacitance C is equal to nC. Energy stored in this capacitor

Test: JEE Main 35 Year PYQs- Electrostatics - Question 9

A charged particle q is placed at the centre O of cube of length L (A B C D E F G H). Another same charge q is placed at a distance L from O. Then the electric flux through ABCD is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 9

Both the charges are identical and placed symmetrically about ABCD. The flux crossing ABCD due to each
charge is   but in opposite directions. Therefore the resultant is zero.

Test: JEE Main 35 Year PYQs- Electrostatics - Question 10

If a charge q is placed at the centre of the line joining two equal charges Q such that the system is in equilibrium then the value of q is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 10

For equilibrium of charge Q

Test: JEE Main 35 Year PYQs- Electrostatics - Question 11

 Capacitance (in F) of a spherical conductor with radius 1 m is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 11

For an isolated sphere, the capacitance is given by

Test: JEE Main 35 Year PYQs- Electrostatics - Question 12

If the electric flux entering and leaving an enclosed surface respectively is φ1 and φ2 , the electric charge inside the surface will be

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 12

The flux entering an en closed sur face is taken as negative and the flux leaving the surface is taken as positive, by convention. Therefore the net flux leaving the enclosed surface = φ21

∴ the charge enclosed in the surface by Gauss’s law is q = ∈021)

Test: JEE Main 35 Year PYQs- Electrostatics - Question 13

A sheet of aluminium foil of negligible thickness is introduced between the plates of a capacitor. The capacitance of the capacitor

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 13

The capacitance of a parallel plate capacitor in which a metal  plate of thickness t is inserted is given by

 

Test: JEE Main 35 Year PYQs- Electrostatics - Question 14

A thin spherical conducting shell of radius R has a charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P a distance R/2 from thecentre of the shell is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 14

Electric potential  due to charge Q placed at the centre of the spherical shell at point P is

Electric potential due to charge q on the surface of the spherical shell at any point inside the shell is

∴ The net electric potential at point P is

Test: JEE Main 35 Year PYQs- Electrostatics - Question 15

The work done in placing a charge of 8 × 10-18 coulomb on a condenser of capacity 100 micro-farad is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 15

The work done is stored as the potential energy. The potential energy stored in a capacitor is given by

Test: JEE Main 35 Year PYQs- Electrostatics - Question 16

Three charges –q1 , +q2 and –q3 are place as shown in the figure. The x - component of the force on –q1 is proportional to

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 16

Force on charge q1 due to q2 is 

Force on charge q1 due to q3 is 

The X - component of the force (Fx)  on

Test: JEE Main 35 Year PYQs- Electrostatics - Question 17

The length of a given cylindrical wire is increased by 100%. Due to the consequent decrease in diameter the change in the resistance of the wire will be

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 17

Rf = n2Ri

Here n = 2 (length becomes twice)

∴ Rf = 4Ri

New reresistance = 400 of Ri

∴ Increase = 300%

Test: JEE Main 35 Year PYQs- Electrostatics - Question 18

Two spherical conductors B and C having equal radii and carrying equal charges on them repel each other with a force F when kept apart at some distance. A third spherical conductor having same radius as that B but uncharged is brought in contact with B, then brought in contact with C and finally removed away from both. The new force of repulsion between B and C is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 18

x is distance between  the spheres. After first operation charge on B is halved i.e Q/2 and charge on third sphere becomes Q/2. Now it is touched to C, charge then equally distributes them selves to make potential same, hence charge on C becomes


Test: JEE Main 35 Year PYQs- Electrostatics - Question 19

A charge particle ‘q’ is shot towards another charged particle ‘Q’ which is fixed, with a speed  ‘v’. It approaches ‘Q’ upto a closest distance r and then returns. If q were given  a speed of ‘2v’ the closest distances of approach would be

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 19

Test: JEE Main 35 Year PYQs- Electrostatics - Question 20

Four charges equal to -Q are placed at the four corners of a square and a charge q is at its centre. If the system is in equilibrium the value of q is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 20

Net  field at A should be zero



Test: JEE Main 35 Year PYQs- Electrostatics - Question 21

A charged oil drop is suspended in a uniform field of 3×104 v/m so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge = 9.9×10–15 kg and g = 10 m/s2)

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 21

At equilibrium, electric force on drop balances weight of drop.

Test: JEE Main 35 Year PYQs- Electrostatics - Question 22

Two point charges + 8q and – 2q are located at x = 0 and x = L respectively. The location of a point on the x axis at which the net electric field due to these two point charges is zero is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 22

Test: JEE Main 35 Year PYQs- Electrostatics - Question 23

Two thin wire rings each having a radius R are placed at a distance d apart with their axes coinciding. The charges on the two rings are +q and -q. The potential difference between the centres of the two rings is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 23



Test: JEE Main 35 Year PYQs- Electrostatics - Question 24

A parallel plate capacitor is made by stacking n equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is ‘C’ then the resultant capacitance is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 24

As n plates are joined, it means (n – 1) capacitor  joined in parallel.

∴ resultant capacitance = (n – 1) C

Test: JEE Main 35 Year PYQs- Electrostatics - Question 25

A charged ball B hangs from a silk thread S, which makes an angle θ with a large charged conducting sheet P, as shown in the figure. The surface charge  density σ of the sheet is proportional to

 

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 25


Test: JEE Main 35 Year PYQs- Electrostatics - Question 26

A fully char ged capacitor has a capacitan ce ‘C’. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity ‘s’ and mass ‘m’. If the temperature of the block is raised by ‘ DT ’, the potential difference ‘V’ across the capacitance is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 26

Applying conservation of energy,

Test: JEE Main 35 Year PYQs- Electrostatics - Question 27

An electric dipole is placed at an angle of 30° to a nonuniform electric field. The dipole will experience

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 27

The electric field will be different at the location of the two charges. Therefore the two forces will be unequal.
This will result in a force as well as torque.

Test: JEE Main 35 Year PYQs- Electrostatics - Question 28

Two insulating plates are both uniformly charged in such a way that the potential difference between them is V2 – V1 = 20 V. (i.e., plate 2 is at a higher potential). The plates are separated by d = 0.1 m and can be treated as infinitely large. An electron is released from rest on the inner surface of plate 1. What is its speed when it hits plate 2? (e = 1.6 × 10–19 C, me = 9.11 × 10–31 kg)

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 28

= 2.65 ×106 m / s

Test: JEE Main 35 Year PYQs- Electrostatics - Question 29

Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance of 5 cm and are uniformly charged. If the spheres are connected by a conducting wire then in equilibrium condition, the ratio of the magnitude of the electric fields at the surfaces of spheres A and B is

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 29

After connection, V1  = V2


The ratio of electric fields

Since the distance between the spheres is large as compared to their diameters, the induced effects may be ignored.

Test: JEE Main 35 Year PYQs- Electrostatics - Question 30

An electric charge 10–3 μ C is placed at the origin (0, 0) of X – Y co-ordinate system. Two points A and B are situated at  and (2, 0) respectively. The potential difference between the points A and B will be

Detailed Solution for Test: JEE Main 35 Year PYQs- Electrostatics - Question 30

The distance of point   from the origin,

The distance of point B(2, 0) from the origin,

∴ Potential difference between the points A and B is zero.

View more questions
Information about Test: JEE Main 35 Year PYQs- Electrostatics Page
In this test you can find the Exam questions for Test: JEE Main 35 Year PYQs- Electrostatics solved & explained in the simplest way possible. Besides giving Questions and answers for Test: JEE Main 35 Year PYQs- Electrostatics, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE