Problem Solving- 1 - Free MCQ Practice Test with solutions, SSC CGL GI

We know that Alice has 'a' chocolates. Alan has 2a+2 chocolates from the given statement in the question. Nadia has double the chocolates as Alan has, so she has 4a+4 chocolates.

Adding these, we get 4a+4+2a+2+a = 7a +6 . So ,Option (d) is correct.

We note that the final ratio must be 3:2 for milk and water respectively. Now, according to given scenario in the question, we have eight liters of solution with 4 liters milk and 4 liters water, which makes it 2:2. In order to make it 3:2, we add 2 liters milk. This would make a total of 6 liters milk and 4 liters water i.e. 6:4 which can be simplified to 3:2.

The solution of the series is as follows.

50 – 5 = 45
45 – 5 = 40
40 – 5 = 35
35 – 5 = 30
30 – 5 25

Hence, the correct answer is 25.

The solution of the series is as follows.

4096 / 4 = 1024
1024 / 4 = 256
256 / 4 = 64
64 / 4 = 16
16 / 4 = 4

Hence, the correct answer is 64.

Given Statement: H < A < T = G > U ≥ V ≥ B 

T > B = True (as T = G > U ≥ V ≥ B)
G > H = True (as H < A < T = G)
If we analyse the given statements, then we get the answer both conclusion I and II follows. 

Given Statement: B = K  ≥ H = T > U ≤ I

H > I = False (as H = T > U ≤ I)
H ≤ I = False (as H = T > U ≤ I)
Hence, Either conclusion I or II follows. 

67 + 9 = 76 

Similarly, 42 + 9 = 51,

Hence, 51 will replace the question mark.

Given Statement:

1. O < L > P > M ≤ N ≤ B 
2. L = K, M ≥ R 
3. K > M = True (as L = K, so L replaced by K then K > P > M)
4. O = M = False (as O < L > P > M)

III. R < B = False (as M ≥ R then R ≤ M ≤ N ≤ B gives either R < B or R = B) 

IV. R = B = False (as M ≥ R then R ≤ M ≤ N ≤ B gives either R < B or R = B) 
Hence, Only conclusion I and Either Conclusion III or IV follow. 

71 – 29 = 42

Similar, 98 – 29 = 69

Hence, 69 will replace the question mark.