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RRB JE CBT 1 - Full Test 10 - Railways MCQ


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30 Questions MCQ Test - RRB JE CBT 1 - Full Test 10

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RRB JE CBT 1 - Full Test 10 - Question 1

There are five friends F, G, K, O, and P, who got different grades A, B, C, D, E in an examination, where A grade means lowest and E means highest grades. F neither got the highest nor lowest grade. A number of peoples having a higher grade than K and the number of peoples having a lower grade than K are equal. O gets the lowest grade among them. G does not get the highest grade but his grade is better than K.

Who got grade B?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 1

According to the question,

1) O gets the lowest grade among them.

2) Number of peoples having higher grade than K and number of peoples having lower grade than K are equal.


3) G does not get highest grade but his grade is better than K.

4) F neither got highest nor lowest grade.

Which means, F got grade B, and P got grade E.

Thus F got grade B.

RRB JE CBT 1 - Full Test 10 - Question 2

What was the theme of the Challachitram National Film Festival which was held in March 2019?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 2
  • Challachitram National Film Festival was held in March with a special award for entries from the northeastern region.
  • The theme of the festival was 'Our Heritage, Our Pride'.
  • Entries for animation films, short films, and documentaries had been invited for both the competitive and non-competitive sections.
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RRB JE CBT 1 - Full Test 10 - Question 3

In the following question, select the related letters from the given alternatives.
Work : Joule :: Inductance : ?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 3

SI unit of Work is Joule.

Similarly SI unit of Inductance is Henry.

Thus Inductance is related to Henry.

RRB JE CBT 1 - Full Test 10 - Question 4

Three numbers are in A.P. Such that their sum is 18 and the sum of their squares is 158. The greatest number among them is:

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 4

For an odd number of terms of an AP always take the middle term as a and other terms on either side with a common difference d.

Let the three numbers in A.P. be

(a – d), a & (a + d)

Given (a – d) + a + (a + d) = 18 or 3a = 18

∴ a = 6                   …(i)

Further (a – d)2 + a2 + (a + d)2 = 158

⇒ 3a2 + 2d2 = 158

⇒ 2d2 = 158 – 3 × 36

⇒ d2 = 25 or d = ± 5

Then, the numbers are 1, 6, 11.

Thus, the greatest number is 11.

RRB JE CBT 1 - Full Test 10 - Question 5

Conservation of species in their natural habitats is known as ________.

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 5
  • The conservation of species in their natural habitats is known as In situ conservation. It is considered the most appropriate way to conserve biodiversity.
  • The conservation of components of biodiversity outside their natural habitats is known as Ex situ conservation. 
RRB JE CBT 1 - Full Test 10 - Question 6

In the following question, a matrix of certain numbers is given. These numbers follow a certain trend, row wise or column wise. Find out this trend and choose the missing character accordingly.

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 6

Talking about the 1st row, 5th column element is obtained by multiplying 1st column by 3rd column then adding by 4th column and then subtracting it by 2nd column.

18 × 3 + 1 – 5 = 54 + 1 – 5 → 50

Similarly for 3rd row

20 × 4 + 5 – 30 = 80 + 5 – 30 → 55

So for 2nd row,

12 × ? + 2 – 50 = 24

12 × ? = 72

? = 72/12

= 6

Hence, “6” is the correct answer.

RRB JE CBT 1 - Full Test 10 - Question 7

Why do two ice blocks join to form one block when pressed together?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 7

When two ice cubes are pressed together, the surface pressure temporarily decreases the melting point of the top layer of ice. This top layer melts and as soon as the pressure is released, the molten ice (water) freezes back into ice due to the low temperature of surrounding molecules and this effectively forms a kind of water weld between the ice cubes.

RRB JE CBT 1 - Full Test 10 - Question 8

Mr. X went to a mall along with his friend. Pointing towards a car in the parking, he said to his friend, “This car belongs to my maternal grandmother’s son-in-law’s only siblings. My maternal grandmother have two daughters” How is car owner’s brother related to Mr. X?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 8

According to the question,

Case-1

Case-2

Hence from the above arrangements, car owner’s brother is either father or uncle of Mr. X.

RRB JE CBT 1 - Full Test 10 - Question 9

Which instrument measures AF(Audio Frequency) signal level and noise?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 9

The Psophometer measures AF(Audio Frequency) signal level and noise.

RRB JE CBT 1 - Full Test 10 - Question 10

Study the following information carefully and answer the given question.

In a certain code language,
“China has appropriated the US” is coded as “sdf pft erw ofr xcs”
“Between the US and China” is coded as “ofr pyu qmx sdf xcs”
“China has copied and improved” is coded as “erw ofr pyu oue ker”

Q. What will be the code for Appropriated?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 10

The given information can be represented as,

Hence, the word ‘appropriated’ is coded as ‘pft’.

RRB JE CBT 1 - Full Test 10 - Question 11

A beaker contains acid and water in the ratio 1 ∶ x. When 300 ml of the previous mixture and 50 ml of water are mixed, the ratio of acid and water becomes 2 ∶ 5. What is the value of x?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 11

Quantity of water in 300 ml of mixture = [x/(x + 1)] × 300

When 50 ml of water is mixed in the mixture, ratio of acid and water becomes 2 ∶ 5

⇒ Quantity of water in in the new mixture = 5/7 × (300 + 50)

⇒ (x/x + 1) × 300 + 50 = 5/7 × (300 + 50)

⇒ (x/x + 1) × 300 = 200

⇒ (x/x + 1) = 2/3

∴ x = 2

RRB JE CBT 1 - Full Test 10 - Question 12

A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.

1171, 1292, ?, 1473, ?, 1586, ?, 1647, 1663

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 12

The pattern followed here is as follows,

1171 + (11)2 = 1171 + 121 = 1292;

1292 + (10)2 = 1292 + 100 = 1392;

1392 + (9)2 = 1392 + 81 = 1473;

1473 + (8)2 = 1473 + 64 = 1537;

1537 + (7)2 = 1537 + 49 = 1586;

1586 + (6)2 = 1586 + 36 = 1622

1622 + (5)2 = 1622 + 25 = 1647;

1647 + (4)2 = 1647 + 16 = 1663

Thus the missing numbers are 1392, 1537, 1622.

RRB JE CBT 1 - Full Test 10 - Question 13

Fine solid particles or liquid droplets suspended in air are called ______.

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 13
  • The aerosol is the suspension of particles in the air & atmosphere.
  • They have both human-made and natural sources.
  • Aerosol particles form during combustion or other industrial processes in factories and car engines, from burning biomass (such as trees and brush) to clear land for agriculture, and even in cooking fires.
RRB JE CBT 1 - Full Test 10 - Question 14

Nature of bond present in the molecule of Nitrogen gas will be

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 14

Covalent bonds are formed by atoms sharing electrons to form bonds that hold the atoms together in a molecule. This type of bond usually formed between two non–metallic elements. Nitrogen, being a non-metal, has 5 electrons is its outer shell. So to make the atom count 8 in order to get stabilized, 2 nitrogen atom would share 3 atoms each with each another, thus forming 3 pairs. These bonds which are then formed are known triple covalent bond.

RRB JE CBT 1 - Full Test 10 - Question 15

A number, when divided by 16, leaves a remainder 4. When the square of the number is divided by 16, what will be the remainder?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 15

Let the number be = 16k + 4 (where k is positive integer.)

Square of the number = (16k + 4)2 = 256k2 + 16 + 128k

Now, we have to find the remainder when the above number is divided by 16.

We will see the reminder of each term when it is divided by 4.

Since 256k2 and 128k will give the remainder 0 and 16 will give the remainder 0 when divided by 4.

So the required remainder = 0 + 0 + 0 = 0

RRB JE CBT 1 - Full Test 10 - Question 16

Determine the largest 4-digit number which is a perfect square.

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 16

As,

100 × 100 = 10000

So, the square of any three-digit number is of 5 digit or more

⇒ 99 × 99 = 9801

So, 9801 is the largest 4-digit perfect square

RRB JE CBT 1 - Full Test 10 - Question 17

Find the missing image in the series?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 17

Here the vertical arrows changes direction in every next step, whereas the inclined lines forms mirror image in each step. The bidirectional arrow rotates 90 degree in clockwise direction in each step.

Hence, the above image will be the next image of the given series.

RRB JE CBT 1 - Full Test 10 - Question 18

If the side of a cube increases by 10%, then what is the percentage increase in the volume of the cube?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 18

Let, side of cube at first = x

∴ Volume of the cube at first = x3

∴ side of the cube now = x + x × 10/100 = 1.1x

∴ Volume of the cube now = (1.1x)3 = 1.1331x

∴ percentage increase in the volume of the cube,


⇒ 0.331 × 100%

⇒ 33.1%

RRB JE CBT 1 - Full Test 10 - Question 19

Central Institute for Cotton Research(CICR) is headquartered in _________.

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 19

CICR is headquartered in Nagpur, Maharashtra. It was established in April 1976. On March 15 scientists from the organisation has developed what is reported to be the shortest-duration cotton variety in the world. Requiring only 100-120 days for maturity, the new variety could emerge as the solution to the problems of dryland cotton farmers in regions like Vidarbha and Telangana.

RRB JE CBT 1 - Full Test 10 - Question 20

An equal sum is invested in two different schemes. One scheme gives simple interest and the other gives compound interest. The sum of interest obtained after 2 years from both the schemes is Rs. 5369. If both schemes have 13% per annum interest rate, then what is the total sum?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 20

Net percentage of SI in 2 years = 13 + 13 = 26%

Net percentage of CI in 2 years = 13 + 13 + (13 × 13)/100 = 27.69%

According to question

CI + SI = 26 + 27.69 = 53.69

⇒ 53.69 unit = Rs. 5369

⇒ 100 unit = 5369/53.69 × 100 = Rs. 10,000

∵ An equal sum is invested in two different schemes

⇒ Total sum = 2 × 10,000 = Rs. 20,000

RRB JE CBT 1 - Full Test 10 - Question 21

What is the least common multiple of (7/5) and (9/25)?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 21

LCM of fractions = LCM of numerators/HCF of denominators

LCM of Numerators = LCM of 7 and 9 = 63

HCF of Denominators = HCF of 5 and 25 = 5

∴ LCM of (7/5) and (9/25) = 63/5

RRB JE CBT 1 - Full Test 10 - Question 22

Who was awarded the ‘Oscat’ by People for the Ethical Treatment of Animals (PETA) in February 2019?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 22
  • Bradley Cooper was awarded the ‘Oscat’ by People for the Ethical Treatment of Animals (PETA).
  • The animal rights organisation awarded the best director award to Cooper for his enlightened decision to cast his own canine companion in ‘A Star Is Born’.
  • PETA is an American animal rights organisation based in Norfolk, Virginia, and led by Ingrid Newkirk, its international president.
RRB JE CBT 1 - Full Test 10 - Question 23

If x + y + z = 6 and xy + zx + zy = 10, then find the value of x3 + y3 + z3 – 3xyz. 

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 23

We know that,

(x + y + z)2 = x2 + y2 + z2 + 2(xy + yz + zx)

Now, substituting the value we have,

⇒ 62 = x2 + y2 + z2 + 2(10)

⇒ 36 = x2 + y2 + z2 + 20

⇒ x2 + y2 + z2 = 16

We know that,

a3 + b3 + c3 = (a + b + c)(a2 + b2 + c2 – ab – bc – ac) + 3abc

So,

⇒ x3 + y3 + z3 – 3xyz = (x + y + z){x2 + y2 + z2 – (xy + yz + zx)}

Now, substituting the values we have,

⇒ x3 + y3 + z3 – 3xyz = 6 × (16 – 10) = 6 × 6 = 36

RRB JE CBT 1 - Full Test 10 - Question 24

In the following question, two statements are given each followed by two conclusions I and II. You have to consider the statements to be true even if they seem to be at variance from commonly known facts. You have to decide which of the given conclusions, if any, follows from the given statements.

Statement I: Medicines today have become an integral part of everyone’s life.
Statement II: People undergo medicinal treatment at any age.

Conclusion I: Lifestyle has made us easy going and less caring for health.
Conclusion II: Medicines have become a compulsory part of one’s life

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 24

Statement I: Medicines today have become an integral part of everyone’s life.

Statement II. People undergo medicinal treatment at any age.

Conclusion I:

Lifestyle has made us easy going and less caring for health → It does not follow from any of the given statements.

Conclusion II:

Medicines have become a compulsory part of one’s life → 'Integral' does not mean 'compulsory', hence conclusion 2 does not follow.

Hence neither of the conclusions follow. 

RRB JE CBT 1 - Full Test 10 - Question 25

In the following question, select the related letters from the given alternatives.
JFTNC : OAYIH :: LSHVM : ?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 25

In JFTNC : OAYIH,

Similarly for LSHVM,

Thus LSHVM is related to QNMQR.

RRB JE CBT 1 - Full Test 10 - Question 26

Which one of the following is not a major component of biotic environment?

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 26

Biotic components comprise of living things that contribute in the formation of an ecosystem. These include animals, humans, plants, microorganisms etc.

Abiotic components include non-living parts of the ecosystem such as light, water, air, soil etc.

RRB JE CBT 1 - Full Test 10 - Question 27

Directions: In the question a statement is given, followed by two arguments, I and II. You have to consider the statement to be true even if it seems to be at variance from commonly known facts. You have to decide which of the given arguments, if any, is a strong argument.

Statement: Should street lights be switched off after midnight?

Argument I: No, statistics show that crime and accidents will increase if the street lights are switched off.
Argument II: Yes, since fewer vehicles ply after midnight, expensive electricity will be wasted.

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 27

The correct answer is option 1. Only argument I is strong. 

The first argument states that if lights are switched off after midnight, then it can result in increased crime and accidents, thus it is a strong argument as it has a direct impact on life of people.

Argument II, in comparison with argument I, is weaker as there are other ways to save electricity, such as switching to more efficient sources, managing the usage of electricity, etc. Switching off streetlights after midnight will increase the risk to human lives which cannot be allowed. Thus, argument II is not strong.

RRB JE CBT 1 - Full Test 10 - Question 28

In the following question, select the odd numbers from the given alternatives.

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 28

3709, 5147, and 2671 all are prime numbers whereas 3171 is not.

Thus 3171 is the odd number.

RRB JE CBT 1 - Full Test 10 - Question 29

Avogadro’s Law shows a relationship between ________.

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 29

Avogadro’s Law states that at constant temperature and pressure, all equal volume of gases will have an equal number of molecules" which means 'V' is directly proportional to the 'Number of molecules'.

RRB JE CBT 1 - Full Test 10 - Question 30

In the following question, by using which mathematical operators will the expression become correct?

130 _ 15 _ 20 _ 10_ 2 = 45

Detailed Solution for RRB JE CBT 1 - Full Test 10 - Question 30

Following the BODMAS rule,

1) ×, ÷, +, - → 130 × 15 ÷ 20 + 10 - 2 = 105.5 ≠ 45

2) ÷, ×, +, - → 130 ÷ 15 × 20 + 10 - 2 = 181.33 ≠ 45

3) +, -, ×, ÷ → 130 + 15 - 20 × 10 ÷ 2 = 45

4) -, ÷, ×, + → 130 - 15 ÷ 20 × 10 + 2 = 124.5 ≠ 45

Hence, “+, -, ×, ÷” is the correct answer.

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