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Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - GATE MCQ


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30 Questions MCQ Test - Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I)

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Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 1

The temperature T in a room varies as a function of the outside temperature T0 and the number of persons in the room p, according to the relation T = K (θq p+ T0) , where θ is K are constants. What would be the value of θ given the following data?

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 1

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 2

“The driver applied the __________ as soon as she approached the hotel where she wanted to take a __________.”
The words that best fill the blanks in the above sentence are

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 2

• Brake is a device which is used for stopping or moving a vehicle.
• Break refers to a pause in work or during an activity.

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*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 3

Tower A is 90 m tall and tower B is 140 m tall. They are 100 m apart. A horizontal skywalk connects the floors at 70 m in both the towers. If a taut rope connects the top of tower A to the bottom of tower B, at what distance (in meters) from tower A will the rope intersect the skywalk?


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 3


Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 4

“It is no surprise that every society has had codes of behaviour; however; the nature of these codes is often ________.” The word that best fills the blank in the above sentence is​

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 4

Unpredictable – Contrary word required

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 5

Hema’s age is 5 years more than twice Hari’s age. Suresh’s age is 13 years less than 10 times Hari’s age. If Suresh is 3 times as old as Hema. How old is Hema?

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 5

Using options (a) and (c) cannot be answer.
As Hema’s age is twice of a natural number +5.
(b) and (d) remain.
Let us take Hema’s age as option (d) which is 19.
Hari’s age = 7, and Suresh age = 57 Verifies all condition “answer (d)”
Hema 2 Hari + 5
Suresh 10 Hari -13 = 3 Hema
Solve :
Hari = 7
Hema =19
Suresh = 57

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 6

Consider a sequence of number a1,a2,a3 ..., awhere  for  each integer n > 0. What is the sum of the first 50 terms?

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 6

Sum of series will

All like terms will cancel out and we will be left with

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 7

A fruit seller sold a basket of fruits at 12.5% loss. Had he sold it for Rs. 108 more, he would have made a 10% gain. What is the loss in Rupees incurred by the fruit seller? 

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 7

12.5% x 10% = 108

So loss

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 8

Each of the letters arranged as below represents a unique from 1 to 9. The letters are positioned in the figure such that (A x B x C),(B x G x E) and (D x Ex F ) are equal. Which integer among the following choices cannot be represented by the letters A, B, C, D, E, F or G?

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 8

A x B x C = B x G x E = D x E x F = 72
8 x 9 x 1 = 9 x 2 x 4 x 3 x 4 x 6 = 72
Any of A, B, C, D, E, F , G cannot be 5.

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 9

The price of a wire made of a superalloy material is proportional to the square of its length. The price of 10 m length of the wire is Rs. 1600. What would be the total price (in Rs.) of two wires of lengths 4 m and 6 m?

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 9


Now total cost = 52k  52 x 16 = 832

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 10

What of the following function(s) in an accurate description of the graph for the range(s) indicated?

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 10

Put value and verify

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 11

A solid circular beam with radius of 0.25 m and length of 2 m is subjected to a twisting moment of 20 kNm about the z-axis at the free end, which is the only load acting as shown in the figure. the stress component  txy at Point ‘M’ in the cross-section of the beam at a distance of 1 m from the fixed end is​

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 11


The only non-zero stresses are 
 if θ is 90o then θ = y
But in rest of the planes shear stresses are zero, hence, 

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 12

In a fillet weld, the direct shear stress and bending tensile stress are 50 MPa and 150 MPa, respectively. As per IS 800 : 2007, the equivalent stress (in MPa, up to two decimal places) will be ____________.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 12

Direct bending tensile stress,
fa = 150 MPa
Direct shear stress, q = 50 MPa
According to IS 800 : 2007, clause 10.5.10.1.1
The equivalent stress 

(Hence OK)
Note : The above check for combination of stress need not be done for fillet welds where the sum of normal and shear stresses does not exceed fwd [Clause 10.5.10.1.2. (b)].
Thus,

⇒ 
Thus, the weld is designed for an equivalent stress of 173.21 MPa.

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 13

The percent reduction in the bearing capacity of a strip footing resting on sand under flooding condition (water level at the base of the footing) when compared to the situation where the water level is at a depth much greater than the width of footing, is approximately

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 13

For strip footing on sand (c = 0)

In flooding condition water level rises to base of footing hence IIIrd term unit weight of soil will change and IInd term unit weight will be unaffected.
∴ 
∴   γsub is approximately equal to 0.5 γt
Hence third term reduced and second term will be same thereby percentage reduction will not be 50%.
According to option approach answer should be 25%.
Note : If water table rises to ground level then both γ will reduce to γ hence percentage reduction would be approximately 50%.

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 14

The deformation in concrete due to sustained loading is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 14

Creep is inelastic deformation with time due to sustained loading.

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 15

The speed-density relationship for a road section is shown in the figure.
 

​The shape of the flow-density relationship is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 15

Unto point where speed is constant we have 

q = K × Constant 

i.e. flow density relation is linear and there after speed-density relation is linear there by giving a parabolic relation between flow-density (q = kV).

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 16

A steel column of ISHB 350 @ 72.4 kg/m is subjected to a factored axial compressive load of 2000 kN. The load is transferred to a concrete pedestal of grade M20 through a square base plate. Consider bearing of concrete as 0.45 fck , where fck is the characteristic strength of concrete. Using limit state method and neglecting the self weight of base plate and steel column, the length of a side of the base plate to be provided is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 16

Area required for base plate

So, side of base plate  
= 471.4 mm
= 47.14 mm
Since, provided area must be more than required so answer should be 48 cm.

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 17

For routing of flood in a given channel using the Muskingum method, two of the routing coefficients are estimated as 
C0 =−0.25 and C1 = 0.55. The value of the third coefficient C2 would be _________.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 17

In Muskingum flood routing method 
C0 + C1 + C2 = 1
⇒ 

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 18

A column of height h with a rectangular cross-section of size a x 2a has a buckling load of P. If the cross-section is changed to 0.5a x 3a and its height changed to 1.5 h, the buckling load of the redesigned column will be 

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 18

For column, 

For new column,  

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 19

Bernoulli’s equation is applicable for

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 20

The frequency distribution of the compressive strength of 20 concrete cube specimen is given in the table.

If μ is the mean strength of the specimens and σ is the standard deviation, the number of specimens (out of 20) with compressive strength less than m μ − 3σ is _________.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 20

Average strength,

Now,  μ − 3σ = 26.575 - 3 x 3.7 = 15.48
Thus, no specimen is having compressive strength less than μ − 3σ

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 21

The width of a square footing and the diameter of a circular footing are equal. If both the footings are placed on the surface of sandy soil, the ratio of the ultimate bearing capacity of circular footing to that of square footing will be

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 21

Footing placed on surface 
∴ D= 0
For square footing, 

For circular footing,

For sandy soil, C = 0

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 22

In a shrinkage limit test, the volume and mass of a dry soil pat are found to be  50 cm3 and 88 g. respectively. The specific gravity of the soil solids is 2.71 and the density of water is 1 g/cc. The shrinkage limit (in % up to two decimal places) is___________.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 22

Dry soil mass = 88 gm
Volume of dry soil = 50 cc
Dry density of soil mass,

∴ Shrinkage limit, 

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 23

A core cutter of 130 mm height has inner and outer diameters of 100 mm and 106 mm respectively. The area ratio of the core cutter (in %, up to two decimal places) is ______________.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 23

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 24

Two rectangular under-reinforced concrete beam sections X and Y are similar in all aspects except that the longitudinal compression reinforcement in section Y is 10% more. Which one of the following is the correct statement?

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 24


Due to presence of more compression steel in section Y, NA of section of Y is above than as of X. It means Y is more under-reinforced than X so ductility of Y is more. Since compression steel of Y is more so flexure resistance of X is less than as of Y.

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 25

At the point x = 0, the function f ( x ) = x3 has

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 25

f(x) = x3 at x= 0

At x = 0, the function y =x3 has neither minima nor maxima.

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 26

A well-designed signalized intersection is one in which the

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 27

A flow field is given by Value of the zcomponent of the angular velocity (in radians per unit time, up to two decimal places) at the point (0, -1, 1) is ________.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 27


At point 

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 28

A bitumen sample has been graded as VG30 as per IS : 73-2013. The ‘30’ in the grade means that​

Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 29

The Le Chatelier apparatus is used to determine

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 29

Le Chatelier Apparatus is used to determine the soundness of cement as per IS code 4031 (part 3); this cement testing procedure is called Le Chatelier test for determining the unsoundness properties of cement due t presence of “free lime”.

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 30

A city generates 40 ´ 106 kg of municipal solid waste (MSW) per year, out of which only 10% is recovered/recycled and the rest goes to landfill. The landfill has a single lift of 3 m height and is compacted to a density of 550 kg/m3. If 80% of the landfill is assumed to be MSW, the landfill area (in m2, up to one decimal place) required would be __________.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2018 Paper: (Session I) - Question 30

Total weight generated by city = 40 x106 kg/year Weight of MSW going into landfill
= 0.9 x 40 x 106 kg/year
= 36 x 106 kg/year
Compacted density = 550 kg/m3
Compacted volume of MSW
Total landfill volume = Volume of MSW + Volume of cover
Given, Volume of MSW = 0.8 x Total landfill volume ∴ Volume of cover = 0.2 x Total landfill volume
∴ Total landfill volume  
m3 /year = 81818.18175 m3 /year
Height of landfill = 3 m
∴ Area of landfill 
= 27272.7 m /year

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