OP–amp Nat Level – 1 - Physics MCQ

National semiconductor LH0063C has a slew rate of 6000V/µs. Generally, the practical op-amp is available with slew rate from 0.1V/µs to well above 1000V/µs.

The input offset current is the different of input bias currents i.e.

The correct answer is: 700

0.7 volts is the minimum voltage required to make the PN junction of a real silicon transistor in forward biased. This 0.7 volt potential difference makes the PN junction between base and emitter terminal in forward biased.

A bipolar junction transistor (BJT) contains 2 PN junctions. If the transistor is NPN type then it contains a P-type semiconductor sandwiched between two N-type semiconductor. If the transistor is PNP type then it contains a N-type semiconductor sandwiched between two P-type semiconductor. In both the cases there are two PN junctions.

gain bandwidth product = frequency at which gain is unity
= 5 MHz
= 5000000 Hz
The correct answer is: 5000000

The correct answer is: 92

The output voltage of inverting amplifier is Vout = (-Rf/Rin)Vin. By keeping 1 inverting amplifier and three no of sources (V1, V2, V3) in series corresponding input resistors(R1, R2, R3), we can get this equation.

So 1-8= -7

This is a non-inverting Op-Amp configuration. Therefore, the closed loop voltage gain is
= 22.3
The correct answer is: 22.3

The output goes from the lower to the upper limit. Since, this response is not ideal, the limit are taken at the 90% points, as indicated. So the upper limit is + 9Vand the lower limit is - 9V. The slew rate is 

= 18 V/μs
The correct answer is: 18