Thermodynamic Potential MCQ Level – 1 - IIT JAM MCQ

From thermodynamic Maxwell equation :


The correct answer is: 

By ideal gas equal,
pV = nRT

Multiplying both the equations,
pVΔS = nRΔQ

∴ For isothermal expansion, ΔT = 0

The correct answer is: pVΔS\nR

Gibb’s free energy, denoted by G, combines enthalpy and entropy into a single value
The free energy is defined as follows
G = H – TS
Since H = U + pV
G = U + pV – TS
The correct answer is:
G = U + pV – TS

Let the entropy S of a thermodynamic system be a function of temperature T and Volume V i.e.
S = f(T, V)
Since dS is perfect differential, we can write

Multiplying by T, we get 
For any substance, the specific heat at constant volume is given by

Using dQ = TdS
Also, from Maxwell’s equation, we have 

The correct answer is: 

H = U + pV
dH = dU + pdV + Vdp
dH = dQ + Vdp
⇒ dH = TdS + Vdp
Take S to be constant

take p to be constant

The correct answer is: 

According to first law of thermodynamics 
dQ = dU + pdV ...(1)
According to second law of thermodynamics

Combined form of (1) and (2)
TdS = dU + pdV
The correct answer is: TdS = dU + pdV

F = U – TS
dF = dU – TdS + SdT
take V to be constant



The correct answer is:  

Condition for a change to occur in any process
dU – TdS ≤ –pdV
d(U – TS + pV) ≤ 0
⇒ d(H – TS) ≤ 0
Since, G = H – TS
We get dG ≤ 0
it means in isothermal, isobaric and reversible process,
dG = 0 or G = constant
The correct answer is: Remains constant but not zero

We know that
dU = TdS – pdV + µdN

take U to be constant and N to be constant
we get 
The correct answer is: 

The enthalpy of a homogeneous system is defined as
H = U + pV
The U term can be interpreted as the energy required to create the system, and the pV terms as the energy that would be required to “make room” for the system if pressure of the environment remained constant.
The correct answer is:
H = U + pV