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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - JEE MCQ


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30 Questions MCQ Test - Revisal Problems (Past 13 Year) JEE Main (P Block Elements)

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 1

Direction (Q. Nos. 1-30) This section contains 30 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

Q. 

The true statement for  is

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 1

The azide ion () has 16 electrons (five from each N and one from the charge on the ion). It is isoelectronic with N2O.
It has linear structure called pseudo halide ion not pseudo halogen

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 2

One mole of each H3PO2, H3PO3 and H3PO4 will neutralise x moles of NaOH. y moles of Ca(OH)2 and z moles of AI(OH)3. Here x, y, z ratio is

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 2

H3PO2, H3PO3 and H3PO4 are monobasic, dibasic and tribasic acids respectively.

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 3

When heated which metal nitrate would give the respective metal, oxide NO2 and O2?

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 4

Which shape correctly describes the stated molecule?

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 4

NF3 is sp3-hybridised and have trigonal pyramidal shape.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 5

P4O10 in cold and hot water produce respectively

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 5

It readily dissolves in cold water forming metaphosphoric acid.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 6

Among A,B,C, paramagnetic substance(s) is/are

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 6



Both nitric oxide (NO) and nitrogen dioxide (NO2) are paramagnetic in nature due to the presence of odd number of electron(s) in outer shell. 

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 7

Ammonium dichromate on heating 'X’ gas is liberated. The same gas is liberated by heating

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 8

Which has more covalent bonds?

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 9

When sulphuric acid reacts with PCI5, sulphuryl chloride is formed as the final product. This shows that sulphuric acid is

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 10

S—S bond is present in

I. H2S2O6
II. H2S2O8
III. H2S2O7
IV. H2 S2 O5 

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 10

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 11

Which one of the following cannot act as an oxidising agent?

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 11

In this sulphur has lowest oxidation state. It acts as reducing agent not oxidising agent.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 12

The V -shape of SO2 is due to the presence

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 12

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 13

the number of species having two lone pairs of electrons on the central atom according to VSEPR theory is

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 13

hybridised with square planar shape.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 14

Liquid oxygen and liquid nitrogen are allowed to flow between the poles of an electromagnet. Choose the correct observation

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 14

In O2 molecule, the antibonding  orbitals are singly occupied. Hence, it is paramagnetic in nature.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 15

Among the species,  the order of first ionisation energy is 

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 15

Effective nuclear charge increases in the same order hence, it becomes difficult to remove electron.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 16

The anion forms an oxyacid of chlorine has the same number of pπ- dπ bonds as that of SO3 (gas), oxidation state of chlorine and the structure of anion is

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 16

SO3 has one pπ-pπ and two pπ - dπ bonds. Among chlorine oxyacids, the anion that has two pπ-dπ bonds is chlorate ion i.e.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 17

The products formed when slaked lime reacts with chlorine on heating

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 18

Which one among  have planar shape ?

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 19

Which of the following molecules has a measurable dipole moment?

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BrF3 has ‘T’ shape while others have symmetrical shapes.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 20

When Cl2 gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 21

The geometry of the central atom in  is

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 21

 with 4 bond pair and one lone pair.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 22

If A represents the central atom, in which molecule F-A-F angle is the smallest?

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 23

In the preparation of fluorine, electrolysis of molten KHF2 is preferred than molten fluorspar. The reason is

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 23

Fluorine is prepared by electrolysis of fused KHF2, made as a mixture of KF(s)andHF(g)

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 24

XeF6 on complete hydrolysis yields ‘X’. The molecular formula of X and its geometry respectively are

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 24


XeO3 is a colourless explosive solid and has a pyramidal molecular structure.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 25

The ratio of the heat capacities  for one mole of a gas is 1.6. The gas is

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 26

Which pair have identical shapes ? 

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 26

Both have linear shape.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 27

Which classification is correct?

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Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 28

Which of the following is the life saving mixture of asthma patient?

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 28

The mixture of 80% helium and 20% oxygen is used to arrest breathing in asthma and other respiratory diseases because helium is light and is less soluble in blood under high pressure.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 29

Match the shape to the formula, Which pairing is incorrect?

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 29

XeO3 is pyramidal with sp3-hybridisation and others are correct key.

Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 30

The amount of Na2S2O3.5H2O required to completely reduce 100 mL of 0.25 N iodine solution is

Detailed Solution for Revisal Problems (Past 13 Year) JEE Main (P Block Elements) - Question 30

Milliequivaients of hypo = milliequivalents of iodine = 100 x 0.25
Gram equivalents of hypo = 0.025
Number of moles of hypo = number of milliequivalents of hypo = 0.025
Weight of hypo = 0.025 x 248 = 6.2 g

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