Olympiad Test: Pattern - 1 - Class 7 MCQ

7 ×  5 + 6 = 41
8 × 7 + 5 = 61
6 × 7 + 9 = 51

The sequence is increasing by 5 each time. So, adding 5 to the last number in the sequence gives 20 + 5 = 25.

84 ÷ 7 + 42 ÷ 2 = 12 + 21 = 33
117 ÷ 13 + 96 ÷ 16 = 9 + 6 = 15
153 ÷ 17 + 63 ÷ 3 = 9 + 21 = 30 

The sequence is increasing by 8 each time. So, adding 8 to the last number in the sequence gives 32 + 8 = 40.

Each number in the sequence is obtained by doubling the previous number and subtracting 1. So, 15 * 2 - 1 = 30 + 1 = 31.

Each letter is followed by its position in the alphabet. A is the 1st letter, B is the 2nd letter, C is the 3rd letter, and D is the 4th letter. So  E is 5th. 

(13 – 5)² + (7 – 3)² = 64 + 16 = 80
(23 – 17)² + (8 – 1)² = 36 + 49 = 85
(25 – 12)² + (5 – 2)² = 169 + 9 = 178

The sequence is decreasing by 3 each time. So, subtracting 3 from the last number in the sequence gives 17 - 3 = 14.

√16 + √144 + √81+ √49 = 4 + 12 + 9 + 7 
= 32
√36 + √121 + √9+ √25  = 6 + 11 + 3 + 5 
= 25
√81 + √441 + √4+ √121 = 9 + 21 + 2 + 11 
= 43 

(√81 + √169 ) − ( √49+ √16 )
= (9 + 13) – (7 + 4) = 11
(√144 + √324 ) − ( √196 + √9 )
= (12 + 18) – (14 + 3) = 13
(√36 + √441) − ( √25+ √81)
= (6 + 21) – (5 + 9) = 13