Olympiad Test: Alphabetical Series - 2 - Free MCQ with solutions

In this series, the third letter is repeated as the first letter of the next segment. The middle letter, A, remains static. The third letters are in alphabetical order beginning with R.

In this series, the letters remain the same: DEF.
The subscript numbers follow this series: 111, 112, 122, 222, 223, 233, 333, ...

The first two letters, PQ, are static. The third letter is in alphabetical order, beginning with R. The number series is in descending order beginning with 5.

The middle letters are static, so concentrate on the first and third letters. The series involves an alphabetical order with a reversal of the letters. The first letters are in alphabetical order: F, G, H, I , J. The second and fourth segments are reversals of the first and third segments. The missing segment begins with a new letter.

The first letters are in alphabetical order with a letter skipped in between each segment: C, E, G, I, K. The second and third letters are repeated; they are also in order with a skipped letter: M, O, Q, S, U.

The second and fourth letters in the series, L and A, are static. The first and third 

There is a gap of four letters between the first and second, the second and third letters of each term, and also between the last letter of a term and the first letter of the next term.

This is an alternating series in alphabetical order. The middle letters follow the order ABCDE. The first and third letters are alphabetical beginning with J. The third letter is repeated as the first letter in each subsequent three-letter segment.

This series consists of a simple alphabetical order with the first two letters of all segments: B, C, D, E, F, G, H, I, J, K. The third letter of each segment is a repetition of the first letter.

The given series may be divided into 2 groups : I. A, B, C, D, E, F, ?, ? and II. N, O, P, ?
Clearly, the given series consists of two terms of I followed by one term of II.
The missing terms in I are G and H while the missing term in II is Q.

The given sequence is a combination of two series: I. 1st, 3rd, 5th, 7th, 9th, 11th terms i.e. A, B, C, D, E, ? II. 2nd, 4th, 6th, 8th, 10th terms i.e. B, D, F, H, ?
Clearly, I consist of consecutive letters while II consists of alternate letters. So, the missing letter in I is F, while that in II is J. So, the missing terms i.e. 10th and 11th terms are J and F respectively.

The number of letters in the terms of the given series increases by one at each step.
The first letter of each term is two steps ahead of the last letter of the preceding term.
However, each term consists of consecutive letters in order.

The given sequence is a combination of two series: I. Y,T, O and II. B, G, ?
I consists of 2nd, 7th and 12th letters from the end of the English alphabet while II consists of 2nd, 7th and 12th letters from the beginning of the English alphabet.
So, the missing letter in II is the 12th letter from the beginning of the English alphabet, which is L.

The series may be divided into groups as shown:
b e d / f ? h / j ? l
Clearly in the first group, the second and third letters are respectively three and two steps ahead of the first letter. A similar pattern would follow in the second and third groups.

There are three series to look for here. The first letters are alphabetical in reverse: Z, Y, X, W, V. The second letters are in alphabetical order beginning with A. The number series is as follows: -1, + 2, -3, + 4......
i.e. 5 – 1 = 4
4 + 2 = 6
6 – 3 = 3
3 + 4 = 7