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Olympiad Test: Rational Numbers - 2 - Class 8 MCQ


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10 Questions MCQ Test - Olympiad Test: Rational Numbers - 2

Olympiad Test: Rational Numbers - 2 for Class 8 2024 is part of Class 8 preparation. The Olympiad Test: Rational Numbers - 2 questions and answers have been prepared according to the Class 8 exam syllabus.The Olympiad Test: Rational Numbers - 2 MCQs are made for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Rational Numbers - 2 below.
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Olympiad Test: Rational Numbers - 2 - Question 1

How many rational numbers lie between 1/5 and 1/3?

Olympiad Test: Rational Numbers - 2 - Question 2

If x is a non-zero rational number, then what is the value of x°?

Detailed Solution for Olympiad Test: Rational Numbers - 2 - Question 2

Explanation: Any non-zero number raised to the power of 0 is always 1. Therefore,

when x is a non-zero rational number.

 

 

 

 

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Olympiad Test: Rational Numbers - 2 - Question 3

Which number is largest among 

Olympiad Test: Rational Numbers - 2 - Question 4

Which number is smallest among 

Detailed Solution for Olympiad Test: Rational Numbers - 2 - Question 4

LCM of 12, 6, 18, 24 = 72

Olympiad Test: Rational Numbers - 2 - Question 5

Closure property of rational number will be value in:

Detailed Solution for Olympiad Test: Rational Numbers - 2 - Question 5

Closure property of rational numbers is satisfied for addition, subtraction and multiplication.
Closure property : The sum of two rational numbers will be a rational of addition for rational number. 

Olympiad Test: Rational Numbers - 2 - Question 6

The difference between two numbers is 22 and their product is 240, what is the difference between their reciprocals ?

Detailed Solution for Olympiad Test: Rational Numbers - 2 - Question 6

p – q = 22, pq = 240.

Olympiad Test: Rational Numbers - 2 - Question 7

The value of (5/4) – (8/3) is:

Detailed Solution for Olympiad Test: Rational Numbers - 2 - Question 7

Explanation: 5/4 – 8/3

Making the denominator equal:

[(5/4) x (3/3)] – [(8/3) x (4/4)]

= (15/12) – (32/12)

= (15 – 32)/12

= -17/12

Olympiad Test: Rational Numbers - 2 - Question 8

If a : b = 1:2, then  =

Detailed Solution for Olympiad Test: Rational Numbers - 2 - Question 8


                  = 9/2

Olympiad Test: Rational Numbers - 2 - Question 9

The sum of two numbers ‘p’ and ‘q’ is 16 and their product is 48, then, 

Detailed Solution for Olympiad Test: Rational Numbers - 2 - Question 9


= 8.24 x 10-5 

Olympiad Test: Rational Numbers - 2 - Question 10

The sum of two numbers is 24 and their difference is 10, then,  number, y = 2nd number].

Detailed Solution for Olympiad Test: Rational Numbers - 2 - Question 10

Solution :- x + y = 24

The difference between x and y is 10. In other words, x minus y equals 10 and can be written as equation B:

x - y = 10

Now solve equation B for x to get the revised equation B:

x - y = 10

x = 10 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 24

10 + y + y = 24

10 + 2y = 24

2y = 14

y = 7

Now we know y is 7. Which means that we can substitute y for 7 in equation A and solve for x:

x + y = 24

x + 7 = 24

x = 17

So x/y = 17/7

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