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Physics Exam  >  Physics Test  >  GATE Mock Test Series 2027  >  Test: Combined (Thermo + Electronics) - Physics MCQ

GATE Physics Test: Combined (Thermo + Electronics) Free Online Test 2026


MCQ Practice Test & Solutions: Test: Combined (Thermo + Electronics) (55 Questions)

You can prepare effectively for Physics GATE Physics Mock Test Series 2027 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Combined (Thermo + Electronics)". These 55 questions have been designed by the experts with the latest curriculum of Physics 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 110 minutes
  • - Number of Questions: 55

Sign up on EduRev for free to attempt this test and track your preparation progress.

Test: Combined (Thermo + Electronics) - Question 1
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For n-p-n transistor connected as shown in figure VBE = 0.7 volts. Given that reverse saturation current of the .junction at room temperature 3000 K is 10-13 A, the emitter current is

Detailed Solution: Question 1


*Answer can only contain numeric values
Test: Combined (Thermo + Electronics) - Question 2
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In the bistable circuit shown in the figure, the ideal OP- Amp lias saturation levels of ±5 V. The value of R1 (in kΩ) that gives a hysteresis width of 500 mV is______


Detailed Solution: Question 2


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Test: Combined (Thermo + Electronics) - Question 3
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The circuit shown in the figure is 

Detailed Solution: Question 3



Test: Combined (Thermo + Electronics) - Question 4
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Let the magnitude of the gain in the inverting Op-Amp circuit shown be x with switch S1 open. When the switch is closed, the magnitude of gain becomes.

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*Answer can only contain numeric values
Test: Combined (Thermo + Electronics) - Question 5
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Consider the circuit shown in the figure. Assuming  the value of the dc voltage VC2 (in volt) is _____.


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Test: Combined (Thermo + Electronics) - Question 6
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A Weiii bridge oscillator is shown in figure, which of the following statements are true, if f " is the ffeequency of oscillation?

Detailed Solution: Question 6

Test: Combined (Thermo + Electronics) - Question 7
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In a voltage follower op-amp circuit, find the closed loop gain V0/Vs if the open loop gain = 2

Detailed Solution: Question 7



Test: Combined (Thermo + Electronics) - Question 8
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The circuit shown in the figure is best described as a

circuit diagram

Detailed Solution: Question 8

Answer: D. The circuit is a voltage doubler.

During the positive half-cycle the input diode connected to the first capacitor conducts and charges C1 to approximately V_p - V_D, where V_p is the input peak voltage and V_D is the diode forward drop.

During the negative half-cycle the polarity at the input drives the second diode to conduct so that the voltage on C2 is stacked on the voltage of C1, effectively adding the capacitor voltages in series.

Consequently the unloaded output approximates V_out ≈ 2V_p - 2V_D (for ideal diodes, V_out ≈ 2V_p), giving about twice the input peak at the output node.

In practice the achievable output is reduced by the diode drops and by discharge of the capacitors into the load between charging pulses, which produces ripple.

Test: Combined (Thermo + Electronics) - Question 9
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In the shunt regulator shown below, the Vz = 8.2 V and VBE = 0.7 V. The regulated output voltage V0 is

Detailed Solution: Question 9

KVL

Test: Combined (Thermo + Electronics) - Question 10
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Let  denote the Exclusive OR (XOR) operation, Let '1' and '0' denote the binary constants. Consider the following Boolean expression for F over two variables P and Q:

The equivalent expression for F is

Detailed Solution: Question 10


Test: Combined (Thermo + Electronics) - Question 11
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Suppose one Si and one Ge-diodes are connected in parallel and then this combination is connected to a power supply of 5 V together with a series resistance 220 Ω. The value of the current through the Si(I1) and Ge(I2) are
[Given the cut in voltage of Si diode is 0.7 V and Ge diode is 0.3 V]

Detailed Solution: Question 11

Since the cut in voltage of Ge-diode is less than the cut in voltage of Si diode, so first Ge-diode will be on and all current will pass through it and Si diode will never on.

Test: Combined (Thermo + Electronics) - Question 12
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In a certain CE amplifier with emitter resistance and emitter by-pass capacitor, if the by-pass capacitor is removed the voltage gain of the amplifier.

Detailed Solution: Question 12

The re model of CE transistor.


Therefore, gain will decrease if we remove capacitor.

Test: Combined (Thermo + Electronics) - Question 13
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In the given circuit the time constant is larger than the period of the signal and the zener breakdown voltage of zener diode is 6V. A square wave is applied to the input as shown in figure. Which of the following graph represent the nature of the output.

Detailed Solution: Question 13

During positive half cycle diocle will be conducting so output will be zero and capacitor will changed at -10V. During negative half cycle effective input will -20 V. and diode will be reverse biased and input voltage is less than Vth, so zener diode will be behave like voltage regulator. So output will be -6V.

Test: Combined (Thermo + Electronics) - Question 14
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For the Karnaugh map shown in the given figure, the minimum Boolean function is:

Detailed Solution: Question 14

Test: Combined (Thermo + Electronics) - Question 15
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The given circuit will behave like

Detailed Solution: Question 15

Test: Combined (Thermo + Electronics) - Question 16
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If volume and number of particles (F, N) of a thermodynamic system are doubled, which of the following quantities is bound to be doubled?

Detailed Solution: Question 16

Pressure (P), Temperature (T) and Chemical potential (//) are intensive variables whereas entropy (S) is an extensive variable. On increasing the size of a system, extensive variables are bound to increase proportionally whereas intensive variables are not bound to change just because the size of the system has increased.

Test: Combined (Thermo + Electronics) - Question 17
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An ideal bose gas in 5-dimensions has the energy dispersion relation ∈ = Aps. For the Bose gas to undergo Bose-Einstein condensation, which of the following should hold?

Detailed Solution: Question 17

For Bose-Einstein condensation o f an ideal bose gas is d-dimensions with dispersion relation (S > 0 because increasing momentum should not decrease energy), we have

*Answer can only contain numeric values
Test: Combined (Thermo + Electronics) - Question 18
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10 bosons are to be distributed in 3 different energy levels with the 2nd energy level being doubly degenerate and the other two are non-degenerate. The number of ways of achieving this is _____


Detailed Solution: Question 18

3 energy levels with one of them being doubly degenerate effectively means 4 energy levels.
∴ Number of ways of distributing 10 bosons in 4 energy levels

Test: Combined (Thermo + Electronics) - Question 19
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For a gas confined in a box of volume V having total energy E and N number of particles, the number of microstates is  Then the equation of state is

Detailed Solution: Question 19

Test: Combined (Thermo + Electronics) - Question 20
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A real gas expands into vacuum in thermally insulated container. Winch of the following properties of the gas will not change?

Detailed Solution: Question 20

The given case is of adiabatic free expansion. For this, the internal energy of all the gases remains conserved. Moreover, the expression of internal energy of a real gas is given by

∴ 

Since, dV > 0, we have dT < 0. So, the temperature of the real gas will decrease.

*Answer can only contain numeric values
Test: Combined (Thermo + Electronics) - Question 21
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Consider a system of 5 non-interacting distinguishable particles. Each particle can occupy only two energy levels ∈ and 2∈. If the total energy of the system 8∈. Then, the entropy of the system is _____ kB. (answer must be given upto 2 decimal places)


Detailed Solution: Question 21

Let N1 and N2 be the number of particles occupying energy levels ∈ and 2∈ respectively.

*Answer can only contain numeric values
Test: Combined (Thermo + Electronics) - Question 22
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Bulk modulus of a substance is defined as where kT is tlie isothermal compressibility. If instead kT of 1 mole of an ideal gas, we take 5 moles of the same gas, then the ratio of bulk modulus to pressure B:P =_____. (Correct answer must be given upto two place decimal) 


Detailed Solution: Question 22

For ideal gas, we have 

Test: Combined (Thermo + Electronics) - Question 23
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Water has the anomalous property that it contracts on melting. It means that 

Detailed Solution: Question 23

By Clausius - Clapeyron equation

where L = Latent heat of fusion, V2 = Volume of water and V1 = Volume of ice 

It means that with increase in pressure, there is decrease in temperature.
Hence, melting point decreases with increase of pressure.

Test: Combined (Thermo + Electronics) - Question 24
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Below a certain temperature θ, the molecular specific heat of a certain gas is 5/2 kB. As the temperature is raised above θ , the specific heat becomes 7/2 kB. Which of the following can be the gas in this experiment?

Detailed Solution: Question 24

The specific heat of a diatomic molecule looks like

This jump of CV from  comes from vibrational degrees of freedom.
Hence, the gas to be nitrogen.

Test: Combined (Thermo + Electronics) - Question 25
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For a 2nd order phase transition, which of the following remains continuous?

Detailed Solution: Question 25

For a 2nd order phase transition, the quantities which involves second order derivative of free energy are discontinuous whereas the quantities which involves first order derivative of free energy are continuous .Now, we have



As   are 2nd order derivatives of free energy A, they are discontinuous. Moreover, entropy is continuous across 2nd order phase transition.

Test: Combined (Thermo + Electronics) - Question 26
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In the Op-Amp circuit shown, assume that the diode current follows the equation   The relationship between 

Detailed Solution: Question 26

Logarithmic Amplifies 
Case-1


Test: Combined (Thermo + Electronics) - Question 27
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A regulated power supply, shown in figure below, lias an unregulated input (UR) of 15 volts and generates a regulated ouput. Use the component values shown in the figure.

The power dissipation across the transistor Q1 shown in the figure is

Detailed Solution: Question 27


Test: Combined (Thermo + Electronics) - Question 28
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The output voltage of the regulated power supply shown in figure is

Detailed Solution: Question 28

*Answer can only contain numeric values
Test: Combined (Thermo + Electronics) - Question 29
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In the circuit shown, assume that diodes D1 and D2 are ideal. The input voltage is 50 sin ωt Volts. In the steady-state condition, what is the average voltage Vab (in Volts) across the 0.5 μF capacitor?

circuit diagram


Detailed Solution: Question 29

The input voltage is given as

v(t) = 50 sin ωt

Hence, the peak voltage is

Vp = 50 V

The given circuit is a voltage doubler formed using two ideal diodes and two capacitors.

During one half cycle, diode D1 conducts and the 1 µF capacitor charges to approximately Vp = 50 V. During the next half cycle, this charged capacitor adds its voltage to the input voltage, making the voltage applied to diode D2 nearly 2Vp. Diode D2 then conducts and charges the 0.5 µF capacitor to this value.

In steady state, since the diodes are ideal and there is no discharge path, the 0.5 µF capacitor retains this voltage.

Therefore,

Vab = 2Vp = 2 × 50 = 100 V

Final Answer

Vab = 100 V

*Answer can only contain numeric values
Test: Combined (Thermo + Electronics) - Question 30
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The figure shows a half-wave rectifier. The diode D is ideal. The average steady state current (in Amperes) through the diode is approximately______

half-wave rectifier circuit


Detailed Solution: Question 30

B. 0.1 A

In steady state the net charge change of the capacitor over one full period is zero; therefore the average diode current over a period equals the average resistor current over the same period.

The period is T = 1/f = 1/50 = 0.02 s. The time constant is τ = RC = 100 × 4×10-3 = 0.4 s, which is much larger than T, so the capacitor voltage has very small ripple and remains approximately at the input peak.

The peak input voltage is 10 V, so the average output (load) voltage ≈ 10 V. Hence the average diode current ≈ 10 V / 100 Ω = 0.1 A.

Therefore the average steady-state current through the diode is approximately 0.1 A (option B).

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This test contains 55 MCQs on Combined (Thermo + Electronics) with detailed solutions for each question. It is part of the GATE Physics Mock Test Series 2027 course on EduRev, designed to align with the current Physics syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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