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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Test  >  Network Theory (Electric Circuits)  >  Test: Network Equation (Mesh & Node) - 1 - Electrical Engineering (EE) MCQ

Network Equation (Mesh & Node) - 1 - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Network Equation (Mesh & Node) - 1 (10 Questions)

You can prepare effectively for Electrical Engineering (EE) Network Theory (Electric Circuits) with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Network Equation (Mesh & Node) - 1". These 10 questions have been designed by the experts with the latest curriculum of Electrical Engineering (EE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 30 minutes
  • - Number of Questions: 10

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Test: Network Equation (Mesh & Node) - 1 - Question 1
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v1 = ?

Detailed Solution: Question 1

Applying the nodal analysis

Test: Network Equation (Mesh & Node) - 1 - Question 2
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va = ?

Detailed Solution: Question 2

  1. Define nodes

  • Left node = vL

  • Right node = va

  • Bottom node = ground

  1. KCL at node va

  • Currents entering va: 3 A (top source, left→right) + 1 A (bottom source, up) = 4 A

  • Only path leaving va is through the 2 Ω resistor to the left node: I = (va − vL) / 2

  • Set entering = leaving: (va − vL) / 2 = 4 → va − vL = 8 …… (1)

  1. KCL at left node vL

  • From step (1), 4 A enters vL from the 2 Ω branch

  • 3 A leaves vL to the right through the top source

  • So 1 A must go to ground through the 3 Ω resistor

  • vL / 3 = 1 → vL = 3 V …… (2)

  1. Solve for va

  • From (1) and (2): va = vL + 8 = 3 + 8 = 11 V

Final answer: va = 11 V.

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Test: Network Equation (Mesh & Node) - 1 - Question 3
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v1 = ?

Detailed Solution: Question 3

Test: Network Equation (Mesh & Node) - 1 - Question 4
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va = ?

Detailed Solution: Question 4

Test: Network Equation (Mesh & Node) - 1 - Question 5
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A signal generator having a source resistance of 50 Ω is set to generate a 1 kHz sinewave. Open circuit terminal voltage is 10 V peak-to-peak. Connecting a capacitor across the terminals reduces the voltage to 8 V peak-to-peak. The value of this capacitor is __________ μF. (Round off to 2 decimal places.)

 

Detailed Solution: Question 5

Test: Network Equation (Mesh & Node) - 1 - Question 6
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ib = ?

Detailed Solution: Question 6

Correct Answer :- B

Explanation : Current due to voltage source is:

I' = 10/(64+36) 

= 0.1A.

Current due to current source is:

I = 0.5A.

Current ib = I' + I 

= 0.5+ 0.1

= 0.6A

Test: Network Equation (Mesh & Node) - 1 - Question 7
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Find the power supplied by the dependent voltage source in the circuit given below.

Detailed Solution: Question 7

3loops = 3KVL equations. Solving them gives currents flowing in the circuit. I1 = 5A, I2 = -1.47A, I3 = 0.56A. Power supplied by dependent voltage source = 0.4V1 (I1 - I2).

Test: Network Equation (Mesh & Node) - 1 - Question 8
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i1 = ?

Detailed Solution: Question 8


Test: Network Equation (Mesh & Node) - 1 - Question 9
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i1 = ?

Detailed Solution: Question 9

Test: Network Equation (Mesh & Node) - 1 - Question 10
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i1 = ?

Detailed Solution: Question 10


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About this Electrical Engineering (EE) Practice Test

This test contains 10 MCQs on Network Equation (Mesh & Node) - 1 with detailed solutions for each question. It is part of the Network Theory (Electric Circuits) course on EduRev, designed to align with the current Electrical Engineering (EE) syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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