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Practice Test: Civil Engineering (CE)- 9 - Civil Engineering (CE) MCQ


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30 Questions MCQ Test - Practice Test: Civil Engineering (CE)- 9

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Practice Test: Civil Engineering (CE)- 9 - Question 1

A sentence is split into 3 parts in the 3 options given below. If any part of the sentence has an error – grammatical or otherwise, mark that option as your answer. In case there is no error, mark option ‘d’.

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 1

In sentences where the structure is "one of + noun + who" is used, the verb after "who" agrees with the noun used after "one of". In the sentence, the noun is "those writers" which is in plural form. Therefore, it must take a plural verb. This makes the use of "has" incorrect in the sentence. The correct plural verb would be "have". The correct sentence would be:
He is one of those writers who have won acclaim the world over.

Practice Test: Civil Engineering (CE)- 9 - Question 2

What is the number of integral solutions for x3-x2-2x-19=0?

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 2

 Irrespective of the value of ‘x’ (odd or even), x-x- 2x will always be even which means the complete expression x- x- 2x - 19 can NEVER be zero. 

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Practice Test: Civil Engineering (CE)- 9 - Question 3

All 2 digit numbers where both places occupy the same number, in an ascending order with a vertical line separating their pair of next consecutive numbers. This sequence follows with the same condition of 2 digit numbers. Consider 10 as a first two digit number. The number of these vertical lines separating such pairs is ______.

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 3

The pair of such numbers are

11/12; 22/23; 33/34; 44/45; 55/56; 66/67; 77/78; 88/89;

Practice Test: Civil Engineering (CE)- 9 - Question 4

Fill in the missing value

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 4

Middle number is the average of the numbers on both sides.

Average of 6 and 4 is 5

Average of (7+4) and (2+1) is 7

Average of (1+9+2) and (1+2+1) is 8

Average of (4+1) and (2+3) is 5

Therefore, Average of (3) and (3) is 3

Practice Test: Civil Engineering (CE)- 9 - Question 5

If x2-y2= 702, how many ordered pairs of solutions for x and y exist such that x, y are natural numbers

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 5

x2-y2= 702 i.e.(x-y)(x+y)= 702

Factories 702 as 702= 2×3×3×3×13 Since x and y are both natural numbers, (x-y)  and (x+y) should be both even or both should be odd. In order to get possible values of x and y we should write 702 as a product of 2 natural numbers which should be a like i.e. both even or both odd. This is not possible since 702 has only 1 even factor leading to (d) as the answer.

Practice Test: Civil Engineering (CE)- 9 - Question 6

What is the respective ratio between the expenditure made by university on research work and purchase of books for library?

Total expenditure is 60 lakhs.


 

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 6

Expenditure made by university on research work
= 8% of 60 lacs = 8 × 60 lacs/100 = 4.8 lacs
Expenditure made by university on purchase of books for library
= 6% of 60 lacs = 6 × 60 lacs/100 = 3.6 lacs
Hence ratio between the expenditure made by university on research work and purchase of books for library
= 4.8 : 3.6 = 4:3

Practice Test: Civil Engineering (CE)- 9 - Question 7

I have been waiting _____ last year September.

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 7

Option C is the correct answer.

'Since' is used when a specific time is mentioned.

'For' is used to signify the total time period.

Practice Test: Civil Engineering (CE)- 9 - Question 8

Roll numbers given to a select of students are unique 4 digit numbers. One roll number is picked up at random, what is the probability that the chosen number is divisible by 11 or 13 ?

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 8

In the question. We have to count 4 digit numbers which are multiples of 11, 13 and 143 (product of 11 and 13).

The first 4 digit multiple of 11, 13 as well as 143 is 1001 = 11×91= 13×77= 143×7

The last 4 digit multiple of 11 is 9999 =11×909 and that of 13 is 9997 =13×769 and for 143 is 9867 (=143×69)

Number of 4 digit multiple of 11, 13 and 143 are (909-91+1), (769-77+1) and (69-7+1)

i.e. 819,693 and 63 respectively.

The number of 4 digit roll numbers which are divisible by 11 and 13 are 819+693-63=1449 Number of 4 digit numbers are from 1000 to 9999 i.e. 9000.

Probability of selection the required roll number = 

Practice Test: Civil Engineering (CE)- 9 - Question 9

In the solution of the following set of linear equations by Gauss elimination using partial pivoting

5x + y + 2z = 34; 4y – 3z = 12; and

10x - 2y + z = – 4

the pivots for elimination of x and y are

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 9

5x + y + 2Z = 34
4y - 3z = 12
10x - 2y + z = -4
5, 0, 10
1st Pivoting
10x - 2y + z = -4.......eq1
4y - 3z = 12..............eq2
5x + y + 2z = 34.......eq3
eq3 - (eq1)/2,
10x - 2y + z = -4
4y - 3z = 12
2y + 3Z/2 = 36
4, 2
Hence, Pivot elements are x=10 & y=4

Practice Test: Civil Engineering (CE)- 9 - Question 10

Chose the correct expression for f(x) given in the graph.

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 10

Substituting the coordinates of the straight line
we get the correct option as C which is  

Practice Test: Civil Engineering (CE)- 9 - Question 11

List 1 contains quality parameters of water and List 2 contains reagents required for computation. Choose the correct option.

List 1

P. Bacterial concentration
Q. COD
R. Dissolved Oxygen
S. Chlorine

List 2

1) Silver Nitrate
2) Lactose Broth
3) Sodium Thiosulphate
4) Alkali Iodide Azide 

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 11

For bacterial concentration in water MPN test is used in which lactose broth is used, In DO test alkali iodide azide is used to get accurate value of dissolved oxygen , in chlorine determination silver nitrate is used as titrating agent and in COD sodium thiosulphate is used as titrating agent.

Practice Test: Civil Engineering (CE)- 9 - Question 12

The divergence of the vector field  is 

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 12

Practice Test: Civil Engineering (CE)- 9 - Question 13

A rectangular channel had a positive surge of velocity 10 m/s moving down the channel. If depth of flow and velocity after the passing of the surge are 4.0 m and 5.0 m/s respectively, the velocity before the passage of the surge is _____m/s.

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 13

Let Vw = Velocity of surge wave

Superimpose a velocity Vw to the left to simulate steady flow as in figure

Given, y2 = 4.0 m, V2 = 5 m/s and Vw = 10 m/s

By the continuity equation,

⇒ y1 (V- V1 )= y2 (V- V2 )

⇒ y1 (10 - V1 )= 4(10 - 5)

Practice Test: Civil Engineering (CE)- 9 - Question 14

A double cover butt riveted joint is used to connect two flat plates of 250 mm width and 16 mm thickness as shown in figure. There are sixteen power driven rivets of 22 mm diameter at a pitch of 50 mm in both direction on either side of the plate. Two cover plates of 10 mm thickness are used. The capacity of the joint in tension (in kN) with permissible bearing and shearing stresses as 300 MPa and 100 MPa respectively, is

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 14

Strength of one rivet in double shear

Strength of the riveted joint in double shear

= 16 x 86.75 = 1388 kN

Strength of one rivet in bearing = d'×t×σb

=(22+1.5)×16×300×10-3

=112.8 kN

Strength of rivet joint in bearing

=16 x 112.8 = 1804.8 kN

Strength of plate in tearing = (250-4 x 23.5) x 16 x 150 x10-3

= 374.4 kN

Thus, the strength of joint will be governed by tearing and it will be equal to 374.4 kN.

Practice Test: Civil Engineering (CE)- 9 - Question 15

A hydraulically efficient trapezoidal channel section has a uniform flow depth of 2m. The bed width (expressed in m) of the channel is

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 15

Practice Test: Civil Engineering (CE)- 9 - Question 16

In a floating body I = Moment of inertia of water line area about the longitudinal axis, ⩝= Volume of displaced fluid, B = Centre of pressure, G = Centre of gravity and M = Metacentre. For stable equilibrium of this body

Practice Test: Civil Engineering (CE)- 9 - Question 17

For a beam ABCD having three spans each of lengths 2 m, the rotation θB and θC are

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 17




Equilibrium of joint C,

Practice Test: Civil Engineering (CE)- 9 - Question 18

Three uniform rods OA, OB and OC having the same length l, cross sectional area A and of the same material remaining in the same vertical plane support a load W at O as shown in figure. The magnitude of forces in the members OA, OB and OC respectively are

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 18

Let the compressive force in each of the members OB and OC be P.

Let the tension in OA be R.

Resolving the forces at O vertically, we have

R + 2P cos 600  = W

∴ P = W -R

∴  stain energy stored by the frame

R is determined from the condition of minimum strain energy i.e. by the condition,

Practice Test: Civil Engineering (CE)- 9 - Question 19

The cylinder and tube as shown in figure contains oil of specific gravity 0.85. For a gauge reading of 2.5 kg (f)/cm2, the total weight (in kN) of the piston and the slab placed on it is

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 19

Let W be the total weight of the piston and the slab.

Since pressure below the piston = Pressure at the same level in the vertical tube

*Answer can only contain numeric values
Practice Test: Civil Engineering (CE)- 9 - Question 20

If  then the value  where V is the closed region bonded by x = 0, y = 0, z = 0 and 2x + 2y + z = 4, is _____.


Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 20

Practice Test: Civil Engineering (CE)- 9 - Question 21

In the pre-tensioning method, which of the following statements are correct?

1) The tension in the concrete is induced directly by external force
2) Tension is induced in the tendons before concreting
3) Concrete continues to be in tension after pre-stressing 

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 21

In pretension, tension is induced in the tendons before concreting.Once the concrete sets and hardens, tendons are cut and prestress is transferred to concrete. Hence after application of prestressing, concrete is in compression.

Practice Test: Civil Engineering (CE)- 9 - Question 22

A steel bar of 4 m length and uniform cross-sectional area of 1200 mm2 is suspended vertically and loaded as shown in figure. The elongation of the bar will be [Take, E = 2.05 × 103  N/mm2]

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 22

RA  = 40+60+80=180 kN
Force P1 on portion AB = 180 kN (tensile)
Force P2 on portion BC = 180-40 = 140 kN (tensile)
Force P3 on portion CD = 80 kN ( tensile)

Practice Test: Civil Engineering (CE)- 9 - Question 23

From the particle-size distribution curve, the diameter of particle size corresponding to 10% finer, 30% finer and 60% finer are 0.16mm, 0.18 mm and 0.28mm respectively. Determine the three parameters namely D10, Cu & Cc required to classify the granular soils

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 23

The three soil parameters are the Effective size of the particle, Uniformity Coefficient and Coefficient of Curvature.

The Particle size corresponding to 10% finer is Effective size. i.e. D10 = 0.16 mm

Uniformity Coefficient, 

Coefficient of Curvature 

Practice Test: Civil Engineering (CE)- 9 - Question 24

The flexibility matrix of the following structure is a scalar multiple of

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 24

Flexibility Matrix, 

Unit force in direction 1,

Practice Test: Civil Engineering (CE)- 9 - Question 25

In a two dimensional stress analysis, the state of stress at a point is as shown below,

The magnitude of ' ' is

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 25

Using Mohr’s circle

Practice Test: Civil Engineering (CE)- 9 - Question 26

If the angularity number is 16, find the specific gravity of aggregates if their weight in a cylinder of volume 3000 cc is 4070 gm.

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 26

Angularity number= 67-% Solid Volume

Solid Volume= 51%= 0.51 ×3000= 1530 cc

Practice Test: Civil Engineering (CE)- 9 - Question 27

A 2.0 diameter circular culvert is flowing half full and the flow is in critical state. The flow (in m3/s) in the culvert barrel is

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 27

For critical flow condition,

For a circular conduit flowing half full,

Practice Test: Civil Engineering (CE)- 9 - Question 28

The greatest among the numbers 

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 28

Practice Test: Civil Engineering (CE)- 9 - Question 29

Water flows at a steady and uniform depth of 2m in an open channel of rectangular cross section having base width of 4m and laid at a slope of 1 in 10000. If it is desired to obtain critical flow in the channel by providing a hump in the bed. Take Manning’s coefficient = 0.01. Calculate the height of hump (in meters) required for the critical flow

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 29

Area A = 4 ×2 = 8, Perimeter P = 4 + 4 = 8

R = (A/P) = 1 m

Discharge per unit width q = 8/4 = 2

We know that the minimum specific energy corresponds to the point of critical depth and is given by 1.5 times the critical depth

Critical depth = (q2/g)(1/3) = 0.74 m

Minimum specific energy is 1.5 × 0.74 = 1.11 m

Specific energy should be same at all points (neglecting hydraulic losses)

So, E = Eminimum + h (this energy is at position of hump)

E = y + v2/(2*g) = 2.05

h = 2.05 – 1.11 = 0.94 m

Practice Test: Civil Engineering (CE)- 9 - Question 30

An orifice having a diameter of 10cm discharging water and the venacontracta formed has a diameter of 9cm. If the coefficient of velocity is 0.96, then what is the coefficient of discharge?

Detailed Solution for Practice Test: Civil Engineering (CE)- 9 - Question 30

We know that
Cd = Cc × Cv
Cd = coefficient of discharge
Cc = coefficient of contraction
Cv = coefficient of velocity
Now, Cc = area of venacontracta /area of orifice

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