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Civil Engineering (CE) Exam  >  Civil Engineering (CE) Tests  >  Test: Shear Force & Bending Moment - 2 - Civil Engineering (CE) MCQ

Test: Shear Force & Bending Moment - 2 - Civil Engineering (CE) MCQ


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10 Questions MCQ Test - Test: Shear Force & Bending Moment - 2

Test: Shear Force & Bending Moment - 2 for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Test: Shear Force & Bending Moment - 2 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Shear Force & Bending Moment - 2 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Shear Force & Bending Moment - 2 below.
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Test: Shear Force & Bending Moment - 2 - Question 1
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Bending moment distribution in a beam is shown in the figure beiow.

The shear force diagram will be given by

Detailed Solution for Test: Shear Force & Bending Moment - 2 - Question 1

It is a fixed beam carrying concentrated load at mid span. The shear force diagram will be given by (a).

Test: Shear Force & Bending Moment - 2 - Question 2
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A simply supported beam is loaded as shown in the figure. The maximum shear force in the beam will be

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The reactions at the supports A and B respectively are

The SF diagram will be

The maximum shear force = 2 W.

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Test: Shear Force & Bending Moment - 2 - Question 3
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The shape of the bending moment diagram for a cantilever beam carrying a uniformly distributed load over its length is

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Mx = -wx2/2 which is parabolic in nature.

Test: Shear Force & Bending Moment - 2 - Question 4
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A simply supported beam is subjected to a distributed loading as shown in the diagram given

What is the maximum shear force in the beam? 
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Test: Shear Force & Bending Moment - 2 - Question 5
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The point of contraflexure is a point where
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At the point of contraflexure, bending moment changes sign.

Test: Shear Force & Bending Moment - 2 - Question 6
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The ratio of reactions RA and RB of the simply supported beam (as shown) is
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Test: Shear Force & Bending Moment - 2 - Question 7
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The bending moment in a simple supported beam can be calculated with the help of influence line drawn for the following types of load
Test: Shear Force & Bending Moment - 2 - Question 8
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In a simply supported beam of length ‘L’ with a triangular load varying from zero at one end to the maximum value at the other end, the maximum, bending moment is
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we get,

Test: Shear Force & Bending Moment - 2 - Question 9
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For a simply supported beam of length L , the bending moment M is described as M = a (x - x3/L2), 0 ≤ x < L  where a is a constant. The shear force will be zero at
Detailed Solution for Test: Shear Force & Bending Moment - 2 - Question 9

Shear force,

if S = 0
⇒ x = L/√3

Test: Shear Force & Bending Moment - 2 - Question 10
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Match List-I (Type 0f .be4 rp.with type of loading) with List-ll ( Maximum BM formula) and select the correct answer using the codes given beiowthe lists:
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