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MCQ Practice Test & Solutions: Test: Principal Stress & Strain - 2 (10 Questions)

You can prepare effectively for Civil Engineering (CE) GATE Civil Engineering (CE) 2027 Mock Test Series with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Principal Stress & Strain - 2". These 10 questions have been designed by the experts with the latest curriculum of Civil Engineering (CE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 30 minutes
  • - Number of Questions: 10

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Test: Principal Stress & Strain - 2 - Question 1

If the principal stresses at point in a strained body are p1 and p2 ( p1 > p2), then th e resu lta n t stress on a plane carrying the maximum shear stress is equal to

Detailed Solution: Question 1

Plane of maximum shear is at 45°

Test: Principal Stress & Strain - 2 - Question 2

If ∈1 and ∈2 ( ∈1 > ∈2) are the m axim um and minimum strains in the neighbourhood of a point in a stressed material of Young’s modulus E and Poisson’s ratio p, then the maximum principal stress will be given by

Detailed Solution: Question 2

Test: Principal Stress & Strain - 2 - Question 3

On the element shown below in the figure, the stress in MPa are

The radius of Mohr’s circle V and principal stresses σ1, and σ2 are in (MPa) respectively

Detailed Solution: Question 3


⇒ σ1,2 = 70 ± 50
∴ σ1 = 120 MPa
and σ2 = 20 MPa
and, radius of Mohr's circle

Test: Principal Stress & Strain - 2 - Question 4

The radius of Mohr’s circle gives the value of

Test: Principal Stress & Strain - 2 - Question 5

 A body is subjected to two normal strains of magnitude ∈x = 0.003 and ∈y = 0.002. The shearing strain on a plane inclined at 30° with ∈x is

Detailed Solution: Question 5

Shearing strain 
= (∈x - ∈y) sin2θ
= (0.003 - 0.002)sin60°
= √3/2 x 10-3

Test: Principal Stress & Strain - 2 - Question 6

Which one of the following Mohr’s circles represents the state of pure shear?

Test: Principal Stress & Strain - 2 - Question 7

 A bar is subjected to a uniaxial tensile stress ‘σ’. The tangential stress on a plane inclined at θ to the bar would be

Detailed Solution: Question 7

Normal sress = σ cos2 θ
Tangential Stress = σ sin θ cos θ

= σ sin 2θ/2

Test: Principal Stress & Strain - 2 - Question 8

Which of the following formulae is used to calculate tangential stress, when a member is subjected to stress in mutually perpendicular axis and accompanied by shear stress?

Test: Principal Stress & Strain - 2 - Question 9

Normal stresses of equal magnitude a, but of opposite signs, act at a point of a strained material in perpendicular direction. What is the magnitude of the stress on a plane inclined at 45° to the applied stresses?

Detailed Solution: Question 9


Here, σx = σy = -σ and θ = 45°
∴ σθ = 0

Test: Principal Stress & Strain - 2 - Question 10

Two planes xyand yz are passing through a point in a strained material. The normal and shear stresses on xy plane are +80 MPa, -30 MPa respectively and normal and shear stresses on plane yz are +30 MPa and +30 MPa respectively. What is the angle between the planes?

Detailed Solution: Question 10


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