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Test: Torsion of Shafts - 2 - Civil Engineering (CE) MCQ


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10 Questions MCQ Test - Test: Torsion of Shafts - 2

Test: Torsion of Shafts - 2 for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Test: Torsion of Shafts - 2 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Torsion of Shafts - 2 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Torsion of Shafts - 2 below.
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Test: Torsion of Shafts - 2 - Question 1

A shaft turns at 150 rpm under a torque of 150 Nm. Power transmitted is

Detailed Solution for Test: Torsion of Shafts - 2 - Question 1

Power transmitted is given by, 

= 750πW = 0.75πkw

Test: Torsion of Shafts - 2 - Question 2

The outside diameter of a hollow shaft is twice its inside diameter. The ratio of its torque carrying capacity to that a solid shaft of the same material and the same outside diameter is

Detailed Solution for Test: Torsion of Shafts - 2 - Question 2

The torque carrying capacity Tis given by 

Let outside diameter of hollow and solid shaft = 2d
∴ Inside diameter of hollow shaft =  d

 

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Test: Torsion of Shafts - 2 - Question 3

A round shaft of diameter ‘d and length T fixed at both ends A and B is subjected to a twisting moment T at C, at a distance 114 from A. The torsional stresses in the parts AC and CB will be

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Test: Torsion of Shafts - 2 - Question 4

A solid shaft of diameter D carries a twisting moment that develops maximum shear stress τ. if the shaft is replaced by a hollow one of outside diameter ‘D’ and inside diameter D/2, then the maximum shear stress will be

Detailed Solution for Test: Torsion of Shafts - 2 - Question 4

Test: Torsion of Shafts - 2 - Question 5

In a rectangular shaft subjected to torsion, the maximum shear occurs at

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Test: Torsion of Shafts - 2 - Question 6

The ratio of the moment of resistance of a solid circular shaft of diameter D and a hollow shaft (external diameter D and internal diameter d) is given by

Detailed Solution for Test: Torsion of Shafts - 2 - Question 6

As we know

Test: Torsion of Shafts - 2 - Question 7

If a shaft of diameter d is subjected to a torque Tand a bending moment M, the maximum shear stress is

Test: Torsion of Shafts - 2 - Question 8

The diameter of shaft B is twice that of shaft A Both shafts have the same length and are of the same material, if both are subjected to same torque, then the ratio of the angle of twist of shaft' A to that of shaft B will be

Detailed Solution for Test: Torsion of Shafts - 2 - Question 8

Test: Torsion of Shafts - 2 - Question 9

If a shaft is turning at N r.p.m and the mean torque to which the shaft is subjected is T N-m, the power transmitted by the shaft in kW would be

Detailed Solution for Test: Torsion of Shafts - 2 - Question 9

Test: Torsion of Shafts - 2 - Question 10

A shaft of diameter 'd' and length L is subjected to twisting moment T, shear angle developed in shaft is 0.001 rad. Now the length of the shaft is doubled, but the diameter and torque remain the same what will be the shear angle?

Detailed Solution for Test: Torsion of Shafts - 2 - Question 10

In a shaft subjected to a torque TTT, the angle of twist θ\thetaθ is given by the formula:

θ=TLGJ\theta = \frac{T L}{G J}θ=GJTL​

where:

  • T is the applied torque,
  • L is the length of the shaft,
  • G is the modulus of rigidity of the material,
  • J is the polar moment of inertia, which for a circular shaft of diameter ddd is J=πd432J = \frac{\pi d^4}{32}J=32πd4​.

Since T, G, and d remain constant in both cases, the angle of twist θ\thetaθ is directly proportional to the length LLL.

In the initial case, the angle of twist is given as:

θ=0.001 rad\theta = 0.001 \, \text{rad}θ=0.001rad

When the length LLL is doubled, the new angle of twist θ′\theta'θ′ will be:

θ′=2⋅θ=2⋅0.001=0.002 rad\theta' = 2 \cdot \theta = 2 \cdot 0.001 = 0.002 \, \text{rad}θ′=2⋅θ=2⋅0.001=0.002rad

Thus, the new shear angle developed in the shaft will be 0.002 rad.

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