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MCQ : Work And Energy - 2 - Class 9 MCQ


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15 Questions MCQ Test - MCQ : Work And Energy - 2

MCQ : Work And Energy - 2 for Class 9 2024 is part of Class 9 preparation. The MCQ : Work And Energy - 2 questions and answers have been prepared according to the Class 9 exam syllabus.The MCQ : Work And Energy - 2 MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ : Work And Energy - 2 below.
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MCQ : Work And Energy - 2 - Question 1

On tripling the speed of motion of a body, the change in K.E. is:

Detailed Solution for MCQ : Work And Energy - 2 - Question 1

When the speed of a body is tripled, the change in kinetic energy (K.E.) can be calculated as follows:

MCQ : Work And Energy - 2 - Question 2

The moon revolves around the earth due to the gravitational force (F) of the earth on the moon. The work done by the gravitational force is (r = radius of the circular orbit of moon):

Detailed Solution for MCQ : Work And Energy - 2 - Question 2
  • The work done by the moon when it revolves around the earth is zero because here displacement of the moon and gravitational force of earth are perpendicular to each other.
  • Work done (W) = F x d x cosƟ. In the case of the revolution of the moon around the earth, Ɵ is 90°. Thus, W = F x d x cos90° = F x d x 0 = 0.
  • So, the work done by the moon when it revolves around the earth is Zero.
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MCQ : Work And Energy - 2 - Question 3

A body is moved through a distance of 3 m in the following different ways. In which case is the maximum work done?

Detailed Solution for MCQ : Work And Energy - 2 - Question 3

Work done = Mgh
Work will be maximum when the change in height is maximum, thus when it is lifted vertically upward.

MCQ : Work And Energy - 2 - Question 4

Two bodies of equal weight are kept at heights of h and 1.5 h, respectively. The ratio of their potential energies is:

Detailed Solution for MCQ : Work And Energy - 2 - Question 4

Potential energy is mathematically defined as, P.E = mgh
Potential energy of body 1 = P.E1 = mgh1 
Potential energy of body 2 = P.E2 = mgh2 
Since weight of two bodies are equal, therefore, P.E1 / P. E2 =  h / 1.5 h = 2:3 

MCQ : Work And Energy - 2 - Question 5

If a force of F newton moves a body with constant speed v, the power delivered by it is:

Detailed Solution for MCQ : Work And Energy - 2 - Question 5

Given: Velocity = v & Force = F
We know that work done is equal to the product of force and displacement.
W = F*d
Dividing by t on both sides then we get:
W/t = F*d/t
d/t = v ( Speed = Distance/ Time)
W/t = P (Power)
Therefore, P = F*v

MCQ : Work And Energy - 2 - Question 6

In the SI system, the unit of potential energy is:

Detailed Solution for MCQ : Work And Energy - 2 - Question 6

Potential energy is energy stored in matter. Joule is the SI unit of energy.

MCQ : Work And Energy - 2 - Question 7

A mass ‘m’ falls from a height ‘h’ any point on its path the total energy is:

Detailed Solution for MCQ : Work And Energy - 2 - Question 7
  • Energy at start will be = Potential Energy = mgh
  • According to the law of conservation of energy, it's total energy will be the same at all points i.e. = mgh.
MCQ : Work And Energy - 2 - Question 8

Newton-metre is the unit of:

Detailed Solution for MCQ : Work And Energy - 2 - Question 8

Work = Force * Displacement (N-m)

MCQ : Work And Energy - 2 - Question 9

If the bulbs of 60 W and 40 W are connected in series to a 220 V source the bulb which glows brighter is:

Detailed Solution for MCQ : Work And Energy - 2 - Question 9
  • Two bulbs of 40 W and 60 W are connected in series to an external potential difference. 
  •  When two bulbs are connected in series, the current I will be the same. But the resistance varies. Higher the resistance brighter the glowing. 
  • P = V2 / R
    ⇒ P, R are inversely proportional to each other. 
    Hence, P40 < P60
    ⇒ R40 > R60
  • So, the resistance of 40 W bulb is higher than the 60 W bulb. So 40 W bulb will dissipate more power and glow brighter.
MCQ : Work And Energy - 2 - Question 10

A porter with a suitcase on his head is climbing up a flight of stairs with a uniform speed. The work done by the ‘weight of the suitcase’ on the suitcase is:

Detailed Solution for MCQ : Work And Energy - 2 - Question 10

Force and displacement are in the same direction. 
So, the work done is positive.

MCQ : Work And Energy - 2 - Question 11

A boy holds a mass on his stretched hand. Then:

Detailed Solution for MCQ : Work And Energy - 2 - Question 11
  • When a boy holds a mass in his stretched hand without moving it, the work done against gravity is zero.
  • Work is defined as the force applied on an object multiplied by the distance over which the force is applied.
  • Since the mass is held stationary, there is no displacement and hence no work is done against gravity.
  • However, muscular energy is used to hold the mass in place, as muscles need to exert force to counteract gravity.
MCQ : Work And Energy - 2 - Question 12

Two bodies of unequal masses are dropped from a cliff. At any instant, they have equal:

Detailed Solution for MCQ : Work And Energy - 2 - Question 12

They will have the same acceleration due to gravity because it is independent of mass. 

MCQ : Work And Energy - 2 - Question 13

Two masses m and 2m are dropped from a certain height ‘h’. Then on reaching the ground:

Detailed Solution for MCQ : Work And Energy - 2 - Question 13
  • Since the free-falling acceleration is not dependent on mass, the final velocities of both masses are the same.
    The kinetic energy = KE = mv2/2
  • Hence, the kinetic energy of the heavier mass will be more.
MCQ : Work And Energy - 2 - Question 14

In the case of negative work, the angle between the force and displacement is:

Detailed Solution for MCQ : Work And Energy - 2 - Question 14
  • Work done by any force is the product of the component of the force in the direction of displacement and the magnitude of displacement.
    W = F.d = Fd cosθ
  • When  W =−ve, it means cosθ = −ve
    Therefore, θ = 180º
MCQ : Work And Energy - 2 - Question 15

One unit of electricity is consumed by,
A: P = 40 W bulb used for t = 25 hours
B: P = 20 W bulb used for t = 50 hours
Both A and B are true as, energy E in kWh is best related as:

Detailed Solution for MCQ : Work And Energy - 2 - Question 15
  • In the given question, P is given in Watt and we have to calculate E in kWh. So,  we have to convert watt into kW. For this, we divide Pt by 1000.
  • Therefore, E = Pt / 1000  is the correct answer.
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