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RS Aggarwal Test: Coordinate Geometry - Class 10 MCQ


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10 Questions MCQ Test - RS Aggarwal Test: Coordinate Geometry

RS Aggarwal Test: Coordinate Geometry for Class 10 2024 is part of Class 10 preparation. The RS Aggarwal Test: Coordinate Geometry questions and answers have been prepared according to the Class 10 exam syllabus.The RS Aggarwal Test: Coordinate Geometry MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RS Aggarwal Test: Coordinate Geometry below.
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RS Aggarwal Test: Coordinate Geometry - Question 1

The mid-point of the line segment joining the points A (-2, 8) and B (-6, -4) is

Detailed Solution for RS Aggarwal Test: Coordinate Geometry - Question 1

mid point(x,y)=(-2+-6)/2,(8+-4)/2=(-4,2)

RS Aggarwal Test: Coordinate Geometry - Question 2

The coordinates of the point which is equidistant from the three vertices of the ΔAOB as shown in the figure is

Detailed Solution for RS Aggarwal Test: Coordinate Geometry - Question 2

∵ AOB is a right triangle.
∴ Mid-point of AB is equidistant from A, O and B. 

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RS Aggarwal Test: Coordinate Geometry - Question 3

The distance of the point P (2, 3) from the x-axis is

Detailed Solution for RS Aggarwal Test: Coordinate Geometry - Question 3

To find the distance of point P(2, 3) from the x-axis:

- The distance from a point (x, y) to the x-axis is the absolute value of the y-coordinate.
- For point P(2, 3), the y-coordinate is 3.
- Therefore, the distance of point P from the x-axis is 3.
- Hence, the correct answer is B: 3.

RS Aggarwal Test: Coordinate Geometry - Question 4

If   is the mid-point of the line segment joining the points Q (-6, 5) and E (-2, 3), then the value of a is

Detailed Solution for RS Aggarwal Test: Coordinate Geometry - Question 4



So, a/3 = -4 ⇒ a = -12

RS Aggarwal Test: Coordinate Geometry - Question 5

The distance of the point P (-6, 8) from the origin is

RS Aggarwal Test: Coordinate Geometry - Question 6

The points (k + 1, 1), (2k + 1, 3) and (2k + 2, 2k) are collinear if

Detailed Solution for RS Aggarwal Test: Coordinate Geometry - Question 6

∵ Points are collinear.
∴ (k + 1) (3 - 2k) + (2k, + 1) (2k - 1) + (2k + 2) (1 - 3) = 0
⇒ 3k+3 - 2k2 - 2k + 4k- 1 - 4k - 4 = 0 ⇒ 2k2 - 3k - 2 = 0
⇒ 2k- 4k + k - 2 = 0
⇒ 2k(k - 2) + 1(k - 2) = 0
⇒ (2k + 1) (k - 2) = 0

RS Aggarwal Test: Coordinate Geometry - Question 7

The point A (-5, 6) is at a distance of

RS Aggarwal Test: Coordinate Geometry - Question 8

The coordinates of the point which is equidistant from the three vertices of the triangle shown in the given Fig. 6.6 are

RS Aggarwal Test: Coordinate Geometry - Question 9

The area of a triangle with vertices A (3, 0), B (7, 0) and C (8, 4) is

RS Aggarwal Test: Coordinate Geometry - Question 10

The points which lies on the perpendicular bisector of the line segment joining the points A (-2, -5), B (2, 5) is 

Detailed Solution for RS Aggarwal Test: Coordinate Geometry - Question 10

 


     
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