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NTSE Test: Introduction To Trigonometry - Grade 10 MCQ


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10 Questions MCQ Test - NTSE Test: Introduction To Trigonometry

NTSE Test: Introduction To Trigonometry for Grade 10 2024 is part of Grade 10 preparation. The NTSE Test: Introduction To Trigonometry questions and answers have been prepared according to the Grade 10 exam syllabus.The NTSE Test: Introduction To Trigonometry MCQs are made for Grade 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NTSE Test: Introduction To Trigonometry below.
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NTSE Test: Introduction To Trigonometry - Question 1

The value of (sin 30° + cos 30°) - (sin 60° + cos 60°) is

Detailed Solution for NTSE Test: Introduction To Trigonometry - Question 1

sin 30° = 1/2,
cos 30°=√3/2,
sin 60°=√3/2,
cos 60°=1/2,
By putting the value of sin 30°, cos 30°, sin 60° and cos 60° in equation

We get=
(sin30°+cos30°)-(sin60°+cos60°)=(1/2+√3/2)-(√3/2+1/2)
=0

NTSE Test: Introduction To Trigonometry - Question 2

Ratios of sides of a right triangle with respect to its acute angles are known as

Detailed Solution for NTSE Test: Introduction To Trigonometry - Question 2

The ratios of sides of a right-angled triangle with respect to any of its acute angles are known as the trigonometric ratios of that particular angle.

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NTSE Test: Introduction To Trigonometry - Question 3

The value of (sin 45° + cos 45°) is

Detailed Solution for NTSE Test: Introduction To Trigonometry - Question 3

sin 45° + cos 45°

Hence, the answer is = √2

NTSE Test: Introduction To Trigonometry - Question 4

If tan θ = a/b then the value of 

Detailed Solution for NTSE Test: Introduction To Trigonometry - Question 4

Let,angle= θ
(asinθ + bcosθ)/(asinθ - bcosθ)
Dividing both numerator and denominator from cosθ
We get,
atanθ +b/atanθ - b
= ( a.a/b + b) /(a.a/b - b) =(a²/b +b)/(a²/b - b)
=(a² + b²/a²- b²) 

NTSE Test: Introduction To Trigonometry - Question 5

If 6cotθ + 2cosecθ = cotθ + 5cosecθ, then cosθ is

Detailed Solution for NTSE Test: Introduction To Trigonometry - Question 5

6cot+2cosec=cot+5cosec
6cot-cot=5cosec-2cosec
5cot=3cosec
5cos/sin=3/sin
cos=3/5

NTSE Test: Introduction To Trigonometry - Question 6

Match the Columns:

Detailed Solution for NTSE Test: Introduction To Trigonometry - Question 6

Correct Answer :- b

Explanation : If θ is one of the acute angles in a triangle, then the sine of theta is the ratio of the opposite side to the hypotenuse, the cosine is the ratio of the adjacent side to the hypotenuse, and the tangent is the ratio of the opposite side to the adjacent side.

NTSE Test: Introduction To Trigonometry - Question 7

9 sec2 A - 9tan2 A is equal to

Detailed Solution for NTSE Test: Introduction To Trigonometry - Question 7

9 sec2 A - 9 tan2 A
= 9( sec2 A - tan2 A)
= 9 × 1
= 9

NTSE Test: Introduction To Trigonometry - Question 8

The value of sin2 30° - cos2 30° is

Detailed Solution for NTSE Test: Introduction To Trigonometry - Question 8

Solution :- sin^2 30° − cos^2 30°

= (1/2)2 −((3)1/2/2)2

= 1/4 - 3/4

= -1/2

NTSE Test: Introduction To Trigonometry - Question 9

If tan A = 3/2, then the value of cos A is

Detailed Solution for NTSE Test: Introduction To Trigonometry - Question 9

Tanθ = Perpendicular / Base
We are given that TanA = 3/2
On comparing
Perpendicular = 3
Base = 2
To fing hypotenuse
Hypotenuse2 = Perpendicular2 + Base2
Hypotenuse2 = 32 + 22
Hypotenuse = 
Hypotenuse = 3.6

Cosθ = Base / Hypotenuse
CosA = 2 / 3.6
Hence the value of Cos A is 2/3.6=2/√13

NTSE Test: Introduction To Trigonometry - Question 10

If 3 cot θ = 2, then the value of tan θ

Detailed Solution for NTSE Test: Introduction To Trigonometry - Question 10

3 cot θ = 2 ⇒ cot θ = 2/3 ⇒ tan θ = 3/2 

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