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RS Aggarwal Test: Introduction to Trigonometry - Grade 10 MCQ


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10 Questions MCQ Test - RS Aggarwal Test: Introduction to Trigonometry

RS Aggarwal Test: Introduction to Trigonometry for Grade 10 2024 is part of Grade 10 preparation. The RS Aggarwal Test: Introduction to Trigonometry questions and answers have been prepared according to the Grade 10 exam syllabus.The RS Aggarwal Test: Introduction to Trigonometry MCQs are made for Grade 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RS Aggarwal Test: Introduction to Trigonometry below.
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RS Aggarwal Test: Introduction to Trigonometry - Question 1

The value of 

Detailed Solution for RS Aggarwal Test: Introduction to Trigonometry - Question 1

we know

tan 30= 1/√3
cot60= 1/√3

tan30/cot60= 1/√3 ×√3/1= 1

RS Aggarwal Test: Introduction to Trigonometry - Question 2

If ΔABC is right angled at C, then the value of cos (A + B) is

Detailed Solution for RS Aggarwal Test: Introduction to Trigonometry - Question 2

Δ ABC is right angled at C, A + B + C = 180°
∴ A + B = 180° - 90° = 90° (∵ ∠C = 90°)
cos (A + B) = cos 90° = 0

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RS Aggarwal Test: Introduction to Trigonometry - Question 3

If cos A + cos2 A = 1, then sin2 A + sin4 A is

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RS Aggarwal Test: Introduction to Trigonometry - Question 4

The value of 

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RS Aggarwal Test: Introduction to Trigonometry - Question 5

(1 + tanθ + secθ) (1 + cotθ - cosecθ) is equal to

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= 2
= R.H.S.

RS Aggarwal Test: Introduction to Trigonometry - Question 6

If sin A = 1/2,  then the value of cot A is

Detailed Solution for RS Aggarwal Test: Introduction to Trigonometry - Question 6

sin A = 1/2
so A = 30ο 
cot A = cot30ο = √3 

RS Aggarwal Test: Introduction to Trigonometry - Question 7

Solve:  (Sin 30°+cos 60°)-(sin 60° + cos 30°) is equal to:

Detailed Solution for RS Aggarwal Test: Introduction to Trigonometry - Question 7

Answer: (c) 1-√3

Explanation: sin 30° = ½, sin 60° = √3/2, cos 30° = √3/2 and cos 60° = ½

Putting these values, we get:

(½+½)-(√3/2+√3/2)

= 1 – [(2√3)/2]

= 1 – √3

RS Aggarwal Test: Introduction to Trigonometry - Question 8

Given that sin θ = a/b, then cos θ is equal to

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RS Aggarwal Test: Introduction to Trigonometry - Question 9

If cosec A - cot A = 4/5, then cosec A = 

Detailed Solution for RS Aggarwal Test: Introduction to Trigonometry - Question 9

cosec A - cot A = 4/5  ........(i)
Also cosec2 A - cot2 A = 1
⇒ (cosec A - cot A) (cosec A - cot A) = 1

⇒ cosec A + cot A = 4/5   ......(ii)
From (i) and (ii), cosec A = 41/40

RS Aggarwal Test: Introduction to Trigonometry - Question 10

The value of the expression  is

Detailed Solution for RS Aggarwal Test: Introduction to Trigonometry - Question 10

We know that sin 60 =√3/2 and cos 30 = √3/2.
Therefore , Sin 60/cos 30= (√3/2)/(√3/2) = 1

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