RS Aggarwal Test: Probability - Class 10 Maths Free MCQs with solutions

To determine which of the following cannot be a probability:

- A: 1/3 is a valid probability as it falls between 0 and 1.
- B: 0.1 is also a valid probability, representing 10% likelihood.
- C: 3% can be converted to a decimal (0.03), making it a valid probability.
- D: 17/16 is greater than 1, violating the probability rule (must be between 0 and 1).

Therefore, D: 17/16 cannot be the probability of an event.

Total number of outcomes =52

we have only 1 ace of hearts , so the number of favourable outcomes of E ,

where E is card not an ace of hearts = 51.

Solution:

Probability of an event is a measure that quantifies the likelihood of the event occurring. It must satisfy the following conditions:

• The probability must be between 0 and 1, inclusive. That is, 0 ≤ P(event) ≤ 1.
• A probability of 0 means the event will never occur.
• A probability of 1 means the event is certain to occur.

Now, let's analyze each option:

• A. 1/4 = 0.25, which lies between 0 and 1, so it can be a probability.
• B. 0 is the probability of an impossible event, so it is valid.
• C. The option shows -1/2 or -0.5 (as seen in the image), which is less than 0. Probability cannot be negative, so this cannot be a probability.
• D. 0.8 lies between 0 and 1, so it is a valid probability.

Therefore, the correct answer is option C.

 Probability facts.

The possible outcomes when rolling a die are 1, 2, 3, 4, 5, and 6.

An odd number less than 3 is:

• 1

Therefore, there is:

• One favourable outcome
• Out of six possible outcomes

This results in a probability of:

1/6

It is given that

Total number of eggs = 400

Probability of getting a bad egg P(E) = 0.035

Consider x as the number of bad eggs

The formula to find the probability is

P(E) = Number of bad eggs/ Total number of eggs

Substituting the values

0.035 = x/400

By further calculation

35/1000 = x/400

x = 35/1000 x 400

x = 140/10

x = 14

Therefore, the number of bad eggs in the lot is 14.

To find the probability of getting a head, we divide the number of heads by the total number of tosses. The calculation is as follows:

• P = Number of heads / Total number of tosses
• P = 640 / 1000
• P = 0.64

Two coin tossed
Total sample space = {HH, HT, TH, TT}
At most one head means 0 or 1 head
Sample space for getting atmost one head = {TT, TH, HT}
P(s) = 3/4 

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• A standard deck of cards contains 52 cards.
• There are two red suits: hearts and diamonds.
• Each suit has 3 face cards (Jack, Queen, and King).
• Therefore, there are 6 red face cards in total.