JEE Exam  >  JEE Tests  >  QUIZ 1:Current Electricity(#freetestseries) - JEE MCQ

QUIZ 1:Current Electricity(#freetestseries) - JEE MCQ


Test Description

15 Questions MCQ Test - QUIZ 1:Current Electricity(#freetestseries)

QUIZ 1:Current Electricity(#freetestseries) for JEE 2024 is part of JEE preparation. The QUIZ 1:Current Electricity(#freetestseries) questions and answers have been prepared according to the JEE exam syllabus.The QUIZ 1:Current Electricity(#freetestseries) MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for QUIZ 1:Current Electricity(#freetestseries) below.
Solutions of QUIZ 1:Current Electricity(#freetestseries) questions in English are available as part of our course for JEE & QUIZ 1:Current Electricity(#freetestseries) solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt QUIZ 1:Current Electricity(#freetestseries) | 15 questions in 20 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
QUIZ 1:Current Electricity(#freetestseries) - Question 1

The n rows each containing m cells in series are joined in parallel. Maximum current is taken from this combination across an external resistance of 3Ω resistance. If the total number of cells used are 24 and internal resistance of each cell is 0.5 Ω then

QUIZ 1:Current Electricity(#freetestseries) - Question 2

 Two wires each of radius of cross section r but of different materials are connected together end to end (i.e. in series). If the densities of charge carriers in the two wires are in the ratio 1:4, the drift velocity of electrons in the two wires will be in the ratio

1 Crore+ students have signed up on EduRev. Have you? Download the App
QUIZ 1:Current Electricity(#freetestseries) - Question 3

The plot represents the flow  of current through a wire at  three different times. The  ratio of charges flowing  through the wire at different  times is (see figure) 

Detailed Solution for QUIZ 1:Current Electricity(#freetestseries) - Question 3

[c] Charge = area under the current-time graph 

q1=2×1=2,q2=1×2=2,and 

q3=12×2×2=2

 q1:q2:q3=2:2:2=1:1:1

          

QUIZ 1:Current Electricity(#freetestseries) - Question 4

Find the equivalent resistance between A and B. Each resistor has same resistance R. 

Detailed Solution for QUIZ 1:Current Electricity(#freetestseries) - Question 4

 The current in CO,OE,DO, and OF will be same, so these branches will not touch each other at O. 

QUIZ 1:Current Electricity(#freetestseries) - Question 5

Find the equivalent resistance. across the terminals of source of e.m.f. 24 V for the circuit shown in figure 

QUIZ 1:Current Electricity(#freetestseries) - Question 6

In the part of a circuit shown in figure, the potential  difference (VG−VH)between points G and H will be 

QUIZ 1:Current Electricity(#freetestseries) - Question 7

The length of a given cylindrical wire is increased by 100% Due to the consequent decrease in diameter, the change in the resistance of the wire will be

QUIZ 1:Current Electricity(#freetestseries) - Question 8

When 5 V potential difference is applied across a wire of length 0.1 m, the drift speed of electrons is 2.5×10-4ms-1 If the electron density in the wire is 8×1028m-3s, the resistivity of the material is close to

QUIZ 1:Current Electricity(#freetestseries) - Question 9

 Two capacitors C1 and C2 (C1>C2) are charged separately to same potential. Now they are allowed to discharge through similar resistors. Initial rate of discharging will be

Detailed Solution for QUIZ 1:Current Electricity(#freetestseries) - Question 9

Initial rate of discharging means initial current, which is equal to V/R, where V is initial potential. Here V and R are the same for both.

QUIZ 1:Current Electricity(#freetestseries) - Question 10

For a cell, a graph is plotted between the potential Difference V across the terminals of the cell and the current I drawn from the cell (see figure). The emf and the internal resistance of the cell are E and r respectively. Then 

Detailed Solution for QUIZ 1:Current Electricity(#freetestseries) - Question 10

V=E-ir. When i=0, the potential reading is 2 V. hence emf is 2V. When V=0, i=5A. This gives 

r=0.4Ω

QUIZ 1:Current Electricity(#freetestseries) - Question 11

The effective resistance between points P and Q of the electrical circuit shown in the figure is 

Detailed Solution for QUIZ 1:Current Electricity(#freetestseries) - Question 11

 

In a circuit, any circuit element placed between points at the same potential can be removed, without affecting the rest of the circuit, here, by symmetry, points A, B and C are at same potential, for any potential difference between P and Q.  The circuit can therefore be reduced as shown below  Effective resistance 

Req=2Rr/R+r.

QUIZ 1:Current Electricity(#freetestseries) - Question 12

Two conductors AB and CD are connected between two parallel resistors in such a way that no current flows through them. Then a wire is connected between E and F. 

Detailed Solution for QUIZ 1:Current Electricity(#freetestseries) - Question 12

As there is no current through, AB, all the points of AB are at the samepotential, say V1 for the same reason all the points of CD are at the same potential, say V2, but V1>V2 because current is flowing from A to C or B to D. therefore, 

VE>VF

. This is why on connecting E and F by a wire, current will flow from E to F. Hence choice (2) is correct.

*Answer can only contain numeric values
QUIZ 1:Current Electricity(#freetestseries) - Question 13

 The potential difference across 8 ohm resistance is 48 volt as shown in the figure. What is the value of potential difference (in V) across A" and Y points? 


*Answer can only contain numeric values
QUIZ 1:Current Electricity(#freetestseries) - Question 14

In order to quadruple the resistance of a uniform wire, a part of its length was uniformly stretched till the final length of the entire wire was 1.5 times the original length, the part of the wire was fraction equal to ______. 


*Answer can only contain numeric values
QUIZ 1:Current Electricity(#freetestseries) - Question 15

 A battery of internal resistance 4Ω is connected to the network of resistances as shown. In order to give the maximum power to the network, the value of equivalent resistance (inΩ.) should be ______ R. 


Information about QUIZ 1:Current Electricity(#freetestseries) Page
In this test you can find the Exam questions for QUIZ 1:Current Electricity(#freetestseries) solved & explained in the simplest way possible. Besides giving Questions and answers for QUIZ 1:Current Electricity(#freetestseries), EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE