Electrical Engineering (EE) > Test: Basic Laws- 2

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Detailed Solution for Test: Basic Laws- 2 - Question 1

Test: Basic Laws- 2 - Question 2

**Match List I with List-II and select the correct answer using the code given below the lists:**

Detailed Solution for Test: Basic Laws- 2 - Question 2

Test: Basic Laws- 2 - Question 3

The value of current I in the circuit shown below for V = 2 volt is

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Test: Basic Laws- 2 - Question 5

The value of voltage source to be connected across the terminals X and Y so that drop across the 10 Ω resistor is 45 V is

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Test: Basic Laws- 2 - Question 6

In a voltage divider circuit as shown below with two resistances R_{1} and R_{2}, the voltage drop V_{1} is twice the drop V_{2} across R_{2}. The value of R_{1}, and R_{2} will be

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Test: Basic Laws- 2 - Question 7

A delta connected load is shown in figure below. The equivalent star connection has a value of R in Ω is

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Test: Basic Laws- 2 - Question 8

The voltage drop across the 2 Ω resistor for the circuit shown below is

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Test: Basic Laws- 2 - Question 9

For the circuit shown below, the sum of the unknown currents I_{1}, I_{2}, l_{3} and I_{4} is

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Test: Basic Laws- 2 - Question 10

In the delta equivalent of the given star connected circuit is equal to

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Test: Basic Laws- 2 - Question 11

Four resistances 80 Ω, 50 Ω, 25 Ω and R are connected in parallel. Current through 25 Ω resistance is 4 A. The total current of the supply is 10 A. The value of R will be

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Test: Basic Laws- 2 - Question 12

For the circuit shown below, the equivalent resistance will be

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Test: Basic Laws- 2 - Question 13

Three resistors of R Ω each are connected to form a triangle. The resistance between any two terminals will be

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Test: Basic Laws- 2 - Question 14

A network has 10 nodes and 17 branches. The number of different node pair voltage would be

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