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Real Numbers : Test 2 - Class 10 MCQ


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10 Questions MCQ Test - Real Numbers : Test 2

Real Numbers : Test 2 for Class 10 2024 is part of Class 10 preparation. The Real Numbers : Test 2 questions and answers have been prepared according to the Class 10 exam syllabus.The Real Numbers : Test 2 MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Real Numbers : Test 2 below.
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Real Numbers : Test 2 - Question 1

The exponent of 2 in the prime factorisation of 144, is

Detailed Solution for Real Numbers : Test 2 - Question 1

The prime factorization of 144 is as follows:

144 = 2 × 2 × 2 × 2 × 3 × 3

⇒ 144 = 24 × 32

We know that the exponent of a number am is m.

∴ The exponent of 2 in the prime factorization of 144 is 4.

Real Numbers : Test 2 - Question 2

The smallest number by which √27 should be multiplied so as to get a rational number is

Detailed Solution for Real Numbers : Test 2 - Question 2

If we multiply √3 we will get a perfect square 9 which is a rational number.

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Real Numbers : Test 2 - Question 3

The least number that is divisible by all numbers from 1 to 10 ( both inclusive ) is

Detailed Solution for Real Numbers : Test 2 - Question 3

Use concept of HCF and LCM.

Real Numbers : Test 2 - Question 4

(n2 - 1) is divisible by 8, if is

Real Numbers : Test 2 - Question 5

The decimal expansion of the rational number [ 33 × 2-2 × 5-1 ] will terminate after

Detailed Solution for Real Numbers : Test 2 - Question 5

2 decimal places

Real Numbers : Test 2 - Question 6

If the LCM of a and 18 is 36 and the HCF of a and 18 is 2, then a =

Detailed Solution for Real Numbers : Test 2 - Question 6

We know that for any two positive integers a and b, HCF (a, b) × LCM (a, b) = a × b.
Here LCM = 36, HCF = 2 and b = 18
Then, 2 × 36 = a × 18
a = (2 × 36) / 18
a = 4
 

Real Numbers : Test 2 - Question 7

If a = 2³× 3, b = 2 × 3 × 5, c = 3n× 5 and LCM (a, b, c) = 2³ × 3² × 5, then n =

Detailed Solution for Real Numbers : Test 2 - Question 7

We know that LCM = Product of the greatest power of each prime factor, involved in the numbers. Since the power of 3 in LCM is 2, 

C = 3²× 5

Real Numbers : Test 2 - Question 8

If the HCF of 65 and 115 is expressible in the form 65m - 117 , the value of m is 

Real Numbers : Test 2 - Question 9

The smallest rational number by which 1/3 should be multiplied so that its decimal expansion

terminates after one place of decimal, is

Detailed Solution for Real Numbers : Test 2 - Question 9

Let x = p/q be a rational number, such that the prime factorization of q is of the form 2n 5m, where n,

m are non-negative integers. Then x has a decimal expansion which terminates.

So 1/3 should be multiplied by 3/10 so that it is in the form of 2n5m.

Real Numbers : Test 2 - Question 10

The LCM and HCF of two rational numbers are equal, then the numbers must be

Detailed Solution for Real Numbers : Test 2 - Question 10

When numbers are equal, LCM and HCF of two rational numbers are equal.

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