Probability - Olympiad Level MCQ, Class 9 Mathematics - Class 9 MCQ

In first six natural numbers, we have three prime numbers 2,3,5

so P(E) = 3/6 = 1/2

Multiple of 3 on a die = 3, 6

∴  P (a multiple of 3) = 2/6 = 1/3.

We have 5 numbers i.e 2,3,4,5,6 greater than 1 in a fair die.

so P(E) = 5/6

Between 1 and 6, we have 4 numbers 2,3,4,5.

So P(E)= 4/6 = 2/3

among 1,2,3,4,5,6 we have three odd numbers

so P(E) = 3/6 = 1/2

in a fair coin we have one head and one tail

so P(E) = 1/2

Yes it is right because it is probability to come head tail , tail head ,tail tail , head head. That's why it is probability of coming 1/4 of head head .

When Two coins are tossed simultaneously, all the probability of getting any results are:

TT , HH , HT , TH. = 4

【 Here, T is Tail & H is Head 】

So, the probability of getting no head when two coins are tossed simultaneously are;

Probability = Favourable Outcomes ÷ Total Outcomes

TT ÷ TT + HH + HT + TH = Probability

=> 1/4 = Probability

 So, the probability of getting no head = 1/4

When  tossing two coins simultaneously then the possible of outcomes are: (HH) or (HT) or (TH)  or (TT) respectively; where H is denoted for head and T is denoted for tail.

Therefore, total numbers of outcome are 22 = 4.

Probability of getting at least 1 head.

Let E be event of getting at least 1 head.

Then, E = {(HH , HT, TH}

Therefore, n(E) = 3.

Therefore, P(getting at least 1 head) = P(E) = n(E)/n(S) = 3/4.

A complete pack has 4 jack.

so P(E) = 4/52 = 1/13

There are 12 face cards in the deck of 52 cards.

so the probability of getting a face card is 12÷52 = 3/13

We have two cards of number 10 of black suit. 

P(E) = 2/52 = 1/26

Total Red Cards = 26

Total King cards = 4

Total red and King cards = 28 because two king cards are already included in red cards

therefore probabilty = 28/52

= 7/13

ANSWER :- c

Solution :- For any event A, the probability that A will occur is a number between 0 and 1,

inclusive:

0≤P(A)≤1

For a sure event Probability of event is 1

3/5 = 0.6<1

25% =  25/100

 =0.25<1

0.3<1

But 1.5>1

Hence option A is not possible