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Past Year Questions: Metal Forming - Mechanical Engineering MCQ


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30 Questions MCQ Test - Past Year Questions: Metal Forming

Past Year Questions: Metal Forming for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Past Year Questions: Metal Forming questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Past Year Questions: Metal Forming MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Past Year Questions: Metal Forming below.
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Past Year Questions: Metal Forming - Question 1

A wire of 0.1 mm dia is drawn from a rod of 15 mm diameter dies giving reductions of 20%, 40% and 80% are available. For minimum error in the final size, the number of stages and reduction at each stage respectively would be

[ME 1996]

Detailed Solution for Past Year Questions: Metal Forming - Question 1

d1 = 0.2d0 Given, d0 = 15 mm, we get d1 = 3 mm
Similarly, after 2nd pass, we get d2 = 0.6 mm and after 3rd pass, we get d3 = 0.12 mm For option (b), 1st 3 stages are same as in option (a), in 4th pass we have

⇒ d5 = 0.8 d4 = 0.8 × 0.216 = 0.1728 mm
Ouptput in option (b) is closest to the desired diameter of 0.1 mm.

Past Year Questions: Metal Forming - Question 2

A strip with cross-sectional area 150 mm × 4.5 mm is being rolled with 20% reduction of area using 450 mm diameter rollers. The angle subtended by the deformation zone at the roll centre is (in radians)

[ME 1998]

Detailed Solution for Past Year Questions: Metal Forming - Question 2


From question, we have 20% reduction in crosssectional area
150 × 4.5 × 0.8 = 150 × h
h = 3.6 mm
Δ = 4.5 – 3.6 = 0.9 mm
Given, R = 450/2 = 225 mm

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Past Year Questions: Metal Forming - Question 3

Hot rolling of mild steel is carried out

[ME 2002]

Detailed Solution for Past Year Questions: Metal Forming - Question 3

Hot working is carried out at above Recrystallization temperature.
Hot working > 0.6 Tm
and Recrystallization Temp = 0.5 Tm
Tm = melting point.

Past Year Questions: Metal Forming - Question 4

In a rolling process, sheet of 25 mm thickness is rolled to 20 mm thickness. Roll is of diameter 600 mm and it rotates at 100 rpm. The roll strip contact length will be

[ME 2004]

Detailed Solution for Past Year Questions: Metal Forming - Question 4

Given: t1 = 25 mm,
tf = 20 mm
R = 300 mm, N = 100 r.p.m

Angle subtended by the deformed zone at the roll center,

∴ Roll strip contact length =
θ.R = 0.129 × 300 = 38.72 mm

Past Year Questions: Metal Forming - Question 5

A 4 mm thick sheet is rolled with 300 mm diameter rolls to reduce thickness without any change in its width. The friction coefficient at the work-roll interface is 0.1. The minimum possible thickness of the sheet that can be produced in a- single pass is

[ME 2006]

Detailed Solution for Past Year Questions: Metal Forming - Question 5

Given, Initial thickness of sheet,
ti = 4 mm = 4 × 10–3 m
Diameter of roll,
D = 300 mm = 0.3 m
Frictional coefficient at work-roll interface,
μ = 0.1
Let tf = Final thickness of sheet after rolling
For single pass without slipping minimum possible thickness,

Past Year Questions: Metal Forming - Question 6

The thickness of a metallic sheet is reduced from an initial value of 16 mm to a final value of 10 mm in one single pass rolling with a pair of cylindrical rollers each of diameter of 400 mm. The bite angle in degree will be

[ME 2007]

Detailed Solution for Past Year Questions: Metal Forming - Question 6


tan α = 0.173
∴ Bite angle, α = tan-1 (0.173) = 9.936°

Past Year Questions: Metal Forming - Question 7

The maximum possible draft in cold rolling of sheet increases with the

[ME 2011]

Detailed Solution for Past Year Questions: Metal Forming - Question 7

Past Year Questions: Metal Forming - Question 8

A solid cylinder of diameter 100 mm and height 50 mm is forged between two frictionless flat dies to a height of 25 mm. The percentage change in diameter is

[ME 2012]

Detailed Solution for Past Year Questions: Metal Forming - Question 8

From in compressibility,

Percentage change in diameter

Past Year Questions: Metal Forming - Question 9

In a single pass rolling process using 410 mm diameter steel rollers, a strip of width 140 mm and thickness 8 mm undergoes 10% reduction of thickness. The angle of bite in radians is

[ME 2012]

Detailed Solution for Past Year Questions: Metal Forming - Question 9

ΔH = D (1 - cos α)

Past Year Questions: Metal Forming - Question 10

In a rolling process, the state of stress of the material undergoing deformation is

[ME 2013]

Detailed Solution for Past Year Questions: Metal Forming - Question 10

The material (metals) is subjected to high compressive stress as a resort of friction between the roll and the metal suface.

Past Year Questions: Metal Forming - Question 11

With respect to metal working, match Group A with Group B:
Group A
P.   Defect in extrusion
Q. Defect in rolling
R. Product of skew rolling
S. Product of rolling through cluster mill

Group B
I. alligatoring
II. scab
III.fish tail
IV. seamless tube
V. thin sheet with tight tolerance
VI. semi-finished balls of ball bearing

[ME 2014,Set-2]

Past Year Questions: Metal Forming - Question 12

The cold forming process in which a hardened tool is pressed against a workpiece (when there is relative motion between the tool and the workpiece) to produce a roughened surface with a regular pattern is

[ME 2019,Set-2]

Detailed Solution for Past Year Questions: Metal Forming - Question 12

Knurling: It is a process of impressing a diamond shaped or straight line pattern on the surface by a workpiece by using specially shaped hardened metal wheels to improve its appearance and to provide a better gripping surface.

Past Year Questions: Metal Forming - Question 13

The blank diameter used in thread rolling will be

[PI 1989]

Past Year Questions: Metal Forming - Question 14

Thread rolling is restricted to

[PI 1992]

Detailed Solution for Past Year Questions: Metal Forming - Question 14

Intricate Deformation can take place only in Ductile material.

Past Year Questions: Metal Forming - Question 15

If the elongation factor during rolling of an ingot is 1.22. The minimum number of passes needed to produce a section 250 x 250 mm from an ingot of 750 × 750 mm are

[PI 1992]

Detailed Solution for Past Year Questions: Metal Forming - Question 15


Let n → number of passes

(1 – 22)n = 9 n/n
1.22 = 9
n = 11.04

Past Year Questions: Metal Forming - Question 16

A copper strip of 200 mm width and 300 mm thickness is to be rolled to a thickness of 295 mm. The roll of radius 300 mm rotates at 100 rpm. The average shear strength of the work material is 180 MPa. The roll strip contact length and the roll force are

[PI 2006]

Detailed Solution for Past Year Questions: Metal Forming - Question 16

hi = 300 mm hf = 295 mm
Δh = hi - hf = 5 mm
R = 300 mm, N = 100 rpm.
tavg = 180 MPa
Roll strip contact length

Past Year Questions: Metal Forming - Question 17

The maximum possible percentage reduction in area per pass during wire drawing of an ideal plastic material without friction is of the order of

[PI 2007]

Detailed Solution for Past Year Questions: Metal Forming - Question 17

Past Year Questions: Metal Forming - Question 18

In a rolling process, thickness of a strip is reduced from 4 mm to 3 mm using 300 mm diameter rolls rotating at 100 rpm. The velocity of the strip (in m/sec) at the neutral point is

[PI 2008]

Detailed Solution for Past Year Questions: Metal Forming - Question 18


At Neutral Point, Roll velocity and plate velocity

Past Year Questions: Metal Forming - Question 19

Anisotropy in rolled components is caused by

[PI 2009]

Detailed Solution for Past Year Questions: Metal Forming - Question 19

When a material having different value of property in different Direction, called as anisotropic material.

Past Year Questions: Metal Forming - Question 20

In a rolling process, the roll separating force can be decreased by

[PI 2010]

Detailed Solution for Past Year Questions: Metal Forming - Question 20

As roll diameter decreases for the same reduction the contact length decreases. So less force will be required.

Past Year Questions: Metal Forming - Question 21

The thickness of a plate is reduced from 30 mm to 10 mm by successive cold rolling passes using identical rolls of diameter 600 mm. Assume that there is no change in width. If the coefficient of friction between the rolls and the workpiece is 0.1, the minimum number of passes required is

[PI 2011]

Detailed Solution for Past Year Questions: Metal Forming - Question 21

Past Year Questions: Metal Forming - Question 22

In a single pass rolling process using 410 mm diameter steel rollers, a strip of width 140 mm and thickness 8 mm undergoes 10% reduction of thickness. The angle of bite in radians is

[PI 2012]

Detailed Solution for Past Year Questions: Metal Forming - Question 22


D = 410
R = 205
θ = 0.0624 radians

Past Year Questions: Metal Forming - Question 23

In a rolling process, the state of stress of the material undergoing deformation is

[PI 2013]

Detailed Solution for Past Year Questions: Metal Forming - Question 23

Compression & Shear

Past Year Questions: Metal Forming - Question 24

The true sliding strain for a low carbon Steel bar which is doubled in length by forging is

[ME 1992]

Detailed Solution for Past Year Questions: Metal Forming - Question 24

Past Year Questions: Metal Forming - Question 25

A test specimen is stressed slightly beyond the yield point and then unloaded. Its yield strength

[ME 1995]

Past Year Questions: Metal Forming - Question 26

Ductility of material with work hardening

[ME 2002]

Detailed Solution for Past Year Questions: Metal Forming - Question 26

Because with Deformation, material becomes stronger

Past Year Questions: Metal Forming - Question 27

A 2 mm thick metal sheet is to be bent at an angle of one radian with a bend radius of 100 mm. If the stretch factor is 0.5, the bend allowance is

[ME 2005]

Detailed Solution for Past Year Questions: Metal Forming - Question 27

Bend Allowance = a (R + Kt)
R = Bend inside Radius
K = 0.5 because R > 2t
t = sheet thickness
Bend allowance = 1 × (100 + 0.5 × 2) = 101 mm.

Past Year Questions: Metal Forming - Question 28

In open-die forging, a disc of diameter 200 mm and height 60 mm is compressed without any barreling effect. The final diameter of the disc is 400 mm. The true strain is

[ME 2007]

Detailed Solution for Past Year Questions: Metal Forming - Question 28

Constancy of volume

Past Year Questions: Metal Forming - Question 29

The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't' and diameter of the blanked part is 'd'. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is

[ME 2007]

Detailed Solution for Past Year Questions: Metal Forming - Question 29

Let t be the shear stress
F = t × d × t = 5.0 kN
F1 = r × 1.5 d × 4 × t = .6 × 5 = 3 kN

Past Year Questions: Metal Forming - Question 30

The operation in which oil is permeated into the pores of a powder metallurgy product is known as

[ME 2011]

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