Test: Displacement & Velocity - 2 - JEE MCQ

It is given that,
The length of the train is 150 meters.
The length of the bridge is 850 meters.
Since while crossing a bridge, the distance travelled by the train is the sum of the length of the bridge and the length of the train.
So the distance travelled by the train is = 150m+850m
=1000m
Also given that the train is moving with a uniform velocity of 45km/h.
The formula for velocity is given by
Velocity = Displacement/Time.
The train is moving with a uniform velocity of 45km/h means the train is moving 45km in 1 hour.
The relation between km/hour and m/sec is
1km/hour = 

• Displacement of the particle will be zero because it comes back to its starting point.
• 

Because displacement will either be equal or less than distance. It can never be greater than distance.

Let two boys meet at point C after time 't' from the starting.

Then 
AC = vt  and BC = v₁t


By solving we get

Average Speed =
Total Distance Travelled / Total Time Taken

A man walks from his home to market with a speed of 5 km/h.
Distance = 2.5 km
Time = Distance / Time
= 2.5 / 5 = 1/2 hr
He returns back with speed of 7.5 km/h in rest of time of 10 minutes.
Distance = 

So, Average Speed 

 

As the total distance is divided into two equal parts therefore distance averaged speed

The distance and displacement of moving object will have the same magnitude when the object moves along a straight line in the same fixed direction.