Measurement of Length, Mass and Capacity - 2 - Free MCQ Practice Test

• 1 bucket = 4 jugs

• 2 jugs = 3 litres

• If 2 jugs = 3 litres, then:
  Another 2 jugs will also be 3 litres.

• So, 4 jugs = 3 litres + 3 litres = 6 litres.
  Therefore, 1 bucket = 6 litres.

• The container has 4 buckets.
  Each bucket is 6 litres, so:
  4 buckets = 6 litres × 4 = 24 litres.

Perimeter of the quadrilateral = a + b + c + d
Perimeter of the quadrilateral = 4.6 + 8.4 + 7.3 + 4.7 = 25

First 60 g cost = Rs. 12.50

Weight = 310 g

Remaining weight after first 60 g:

310 − 60 = 250 g

Each additional 50 g (or part thereof) costs Rs. 2.50

250 g ÷ 50 g = 5 slabs

Cost for extra slabs = 5 × 2.50 = Rs. 12.50

Total postage = 12.50 + 12.50 = Rs. 25

Let the amount of water in Tank B = x litres
Then Tank A = 6x litres

After transferring some water (say t litres) from A to B:

• Tank A will have: 6x – t
• Tank B will have: x + t

We want both tanks to have 70 litres:
So,
6x – t = 70 …(1)
x + t = 70 …(2)

Add both equations:
(6x – t) + (x + t) = 70 + 70
7x = 140
x = 20

So, Tank B originally had 20 L
Tank A originally had 6 × 20 = 120 L

Now find how much to transfer:
From equation (2):
x + t = 70
20 + t = 70
t = 50 litres

Correct answer: (A) 50 litres

Saving per kg calculation:

• Rajesh bought 13 kg of peanuts.
• He saved Rs. 195 using a store coupon.
• To find the saving per kg, divide the total saving by the total weight:

Calculation:

• Saving per kg = Rs. 195 ÷ 13 kg
• This equals Rs. 15 per kg.

Therefore, Rajesh saved Rs. 15 per kg of peanuts.

Balls required will be 6

5 for balancing the triangle and one for the other. 

  If the beaker is 3/7 full, then the remaining part to fill it = 

We are told that this remaining 4/7 corresponds to 20 litres.

So the full capacity is: 

Length of 5 smaller pieces = 
∴ cloth left with tailor = meters

=15600sec.

28 m is larger becuase 1m = 1000 cm

Thus 28 m = 2800 cm which is greater than 2750cm