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NEET Exam  >  NEET Test  >  Organic Chemistry  >  Assertion & Reason Test: Organic Chemistry - Some basic Principles & Techniques - NEET MCQ

Organic Chemistry - Some basic Principles & Techniques Free Assertion Reason


MCQ Practice Test & Solutions: Assertion & Reason Test: Organic Chemistry - Some basic Principles & Techniques (6 Questions)

You can prepare effectively for NEET Organic Chemistry for NEET with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Assertion & Reason Test: Organic Chemistry - Some basic Principles & Techniques". These 6 questions have been designed by the experts with the latest curriculum of NEET 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 12 minutes
  • - Number of Questions: 6

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Assertion & Reason Test: Organic Chemistry - Some basic Principles & Techniques - Question 1
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Direction: In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.

Assertion (A) : Simple distillation can help in separating a mixture of propan-1-ol (boiling point 97°C) and propanone (boiling point 56°C).

Reason (R) : Liquids with a difference of more than 20°C in their boiling points can be separated by simple distillation.

Detailed Solution: Question 1

Simple distillation technique is used for separating components that have a difference of more than 20∘C in their boiling points. Thus, the statement 'simple distillation can help in separating a mixture of propan-1-ol (boiling point 97∘C) and propanone (boiling point 56∘C)' is correct. Thus, the assertion is correct.

Assertion & Reason Test: Organic Chemistry - Some basic Principles & Techniques - Question 2
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Direction: In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.

Assertion (A): Energy of resonance hybrid is equal to the average of energies of all canonical forms.

Reason (R): Resonance hybrid cannot be presented by a single structure.

Detailed Solution: Question 2

Canonical structures always have more energy than resonance hybrid. Resonance hybrids are always more stable than any of the canonical structures. The delocalization of electrons lowers the orbitals energy and gives stability.

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Assertion & Reason Test: Organic Chemistry - Some basic Principles & Techniques - Question 3
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Direction: In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.

Assertion (A): Pent-1-ene and pent-2-ene are position isomers.

Reason (R): Position isomers differ in the position of functional group or substituent.

Detailed Solution: Question 3

Both A and R are correct and R is the correct explanation of A. When two or more compounds differ in the position of substituent atom or functional group on the carbon skeleton then it is position isomerism. Double bond is a functional group whose position varies.

Assertion & Reason Test: Organic Chemistry - Some basic Principles & Techniques - Question 4
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Assertion (A): Sulphur present in an organic compound can be estimated quantitatively by Carius method.
Reason (R): Sulphur is separated easily from other atoms in the molecule and gets precipitated as light-yellow solid.

Detailed Solution: Question 4

The correct option is D

Both A and R are correct and R is the correct explanation of A.

Analysing the assertion :

Sulphur present in an organic compound can be estimated quantitatively by carius method. Yes, it is a correct statement.

Hence, the assertion is correct.

Analysing the reason :

In this method, a known mass of an organic compound is heated in a carius tube with sodium peroxide or fuming nitric acid. Sulphur present in the compound is oxidised to sulphuric acid. The sulphuric acid so formed is then precipitated as barium sulphate having colour white or light yellow on addition of excess of barium chloride. The precipitate is filtered, washed, dried and weighed. The percentage of sulphur can be calculated from the mass of barium sulphate. So, the reason is correct.

Hence, both assertion and reason are correct and reason is the correct explanation of assertion.

So, option (A) is the correct answer.

Assertion & Reason Test: Organic Chemistry - Some basic Principles & Techniques - Question 5
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Direction: In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.

Assertion (A): Components of a mixture of red and blue inks can be separated by distributing the components between stationary and mobile phases in paper chromatography.

Reason (R): The colored components of inks migrate at different rates because paper selectively retains different components according to the difference in their partition between the two phases.

Detailed Solution: Question 5

In paper chromatography, a chromatography paper is used. It contains water in it, which acts as the stationary phase. A strip of chromatography paper spotted at the base with ink is suspended in a suitable solvent. Solvent acts as the mobile phase.

The solvent rises up the paper by capillary action and flows over the spot. The paper selectively retains different components according to their differing partition in two phases.

Hence, components of ink will megrate at different rates and are separated.

Assertion & Reason Test: Organic Chemistry - Some basic Principles & Techniques - Question 6
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Direction: In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.

Assertion (A): All the carbon atoms in H2C=C=CH2 are sp2 hybridized

Reason (R): In this molecule, all the carbon atoms are attached to each other by double bonds.

Detailed Solution: Question 6

Hybridization of C can be calculated by counting p bonds and σ bonds present on C atom. If C has 3σ bonds, it is sp2 hybridized. If C has 2σ bonds, it is sp hybridized.

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About this NEET Practice Test

This test contains 6 MCQs on Assertion & Reason Test: Organic Chemistry - Some basic Principles & Techniques with detailed solutions for each question. It is part of the Organic Chemistry for NEET course on EduRev, designed to align with the current NEET syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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