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Periodic Classification of Elements - 1 - Free Assertion & Reason Questions


MCQ Practice Test & Solutions: Assertion & Reason Test: Periodic Classification of Elements - 1 (10 Questions)

You can prepare effectively for Class 10 Class 10 Maharashtra SSC Board All Subjects with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Assertion & Reason Test: Periodic Classification of Elements - 1". These 10 questions have been designed by the experts with the latest curriculum of Class 10 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 10

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Assertion & Reason Test: Periodic Classification of Elements - 1 - Question 1

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion (A): Smaller the size of an atom, greater is the electronegativity.

Reason (R): Electronegativity refers to the tendency of an atom to share electrons with other atoms.

Detailed Solution: Question 1

Electronegativity refers to the tendency of an atom to attract bonding electrons.

Assertion & Reason Test: Periodic Classification of Elements - 1 - Question 2

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion (A): Noble gases are highly reactive.

Reason (R): Noble gases have stable closed shell electronic configuration.

Detailed Solution: Question 2

Inert gases (noble gases) are very less reactive due to stable closed shell electronic configuration like ns2, np6 or ns2.

Assertion & Reason Test: Periodic Classification of Elements - 1 - Question 3

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion (A): Sixth and seventh periods in the periodic table contain 14 elements.

Reason (R): In the periodic table, 14 elements of sixth and seventh periods are known as lanthanoids and actinoids.

Detailed Solution: Question 3

Sixth period contains 32 elements and seventh period is incomplete and like sixth, the period would have 32 elements.

Assertion & Reason Test: Periodic Classification of Elements - 1 - Question 4

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion (A): The atomic and ionic radii generally decrease towards right in a period.

Reason (R): The ionisation enthalpy increases on moving towards the left in a period.

Detailed Solution: Question 4

The ionisation enthalpy increases on moving towards the extreme right element in period and atomic and ionic radii decreases in a period from left to right.

Assertion & Reason Test: Periodic Classification of Elements - 1 - Question 5

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion (A): Be and Al show some similar properties.

Reason (R): The metallic radius of Be is less than the metallic radius of Al.

Detailed Solution: Question 5

Be and Al show diagonal relationship because Be resembles in its properties with Al. Metallic radius of the Be (111 pm) is less than the metallic radius of Al (143 pm). Although smaller size is the reason for the anomalous behaviour of Be, it is not a reason for its diagonal relation with Al.

Assertion & Reason Test: Periodic Classification of Elements - 1 - Question 6

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion (A): In triad, the three elements have the same gaps of atomic masses.

Reason (R): Elements in a triad have similar properties.

Detailed Solution: Question 6

In a triad, the atomic mass of the middle element is the mean of the atomic masses of the first and third elements.

Assertion & Reason Test: Periodic Classification of Elements - 1 - Question 7

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion (A): Mendeleev left the gap under aluminium and silicon and called these Eka-aluminium and Eka-silicon, respectively.

Reason (R): Dobereiner arranged elements on the basis of increasing atomic number.

Detailed Solution: Question 7

Dobereiner arranged elements on the basis of increasing atomic weights.

Assertion & Reason Test: Periodic Classification of Elements - 1 - Question 8

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion (A): According to Mendeleev, periodic properties of elements is a function of their atomic number.

Reason (R): Atomic number is equal to the number of protons.

Detailed Solution: Question 8

According to Mendeleev, periodic properties of elements is a function of their atomic masses.

Assertion & Reason Test: Periodic Classification of Elements - 1 - Question 9

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion (A): Mendeleev arranged elements in horizontal rows and vertical columns.

Reason (R): Mendeleev ignored the order of atomic weight thinking that the atomic measurements might be incorrect.

Detailed Solution: Question 9

Mendeleev arranged elements in horizontal rows and vertical columns. He ignored the order of atomic weight thinking that the atomic measurements might be incorrect and placed the elements with similar properties.

Assertion & Reason Test: Periodic Classification of Elements - 1 - Question 10

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion : Mendeleev left the gap under aluminium and silicon and called these Eka-aluminium and Eka- silicon, respectively.

Reason : Dobereiner arranged elements on the basis of increasing atomic number.

Detailed Solution: Question 10

Dobereiner arranged elements on the basis of increasing atomic weights.

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