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Case Based Questions: Periodic Classification of Elements - Class 10 MCQ


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20 Questions MCQ Test - Case Based Questions: Periodic Classification of Elements

Case Based Questions: Periodic Classification of Elements for Class 10 2024 is part of Class 10 preparation. The Case Based Questions: Periodic Classification of Elements questions and answers have been prepared according to the Class 10 exam syllabus.The Case Based Questions: Periodic Classification of Elements MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Case Based Questions: Periodic Classification of Elements below.
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Case Based Questions: Periodic Classification of Elements - Question 1
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From the following part of the periodic table, answer the question :

Which is the most reactive metal ?

Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 1

Most reactive metal is Z because size of atom increases down a group and effective nuclear charge decreases. The attraction of the nucleus to valence electrons also decreases. So, the tendency of losing electrons increases. Hence reactivity increases.

Case Based Questions: Periodic Classification of Elements - Question 2
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From the following part of the periodic table, answer the question :

Which other element is likely to present in the group in which fluorine is present:

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Case Based Questions: Periodic Classification of Elements - Question 3
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From the following part of the periodic table, answer the question :

Name the family of fluorine Q, R, T:

Case Based Questions: Periodic Classification of Elements - Question 4
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From the following part of the periodic table, answer the question :

Name the element P placed below Carbon in group 14:
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 4
The carbon group is a periodic table group consisting of carbon (C), silicon (Si), germanium (Ge), tin (Sn), lead (Pb), and flerovium (Fl). It lies within the p-block.

In modern IUPAC notation, it is called group 14. In the field of semiconductor physics, it is still universally called group IV.

Case Based Questions: Periodic Classification of Elements - Question 5
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From the following part of the periodic table, answer the question :

Which of the following elements belongs to group 2?
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 5
The Alkaline Earth Metals. Group 2A (or IIA) of the periodic table are the alkaline earth metals: beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra).
Case Based Questions: Periodic Classification of Elements - Question 6
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Atoms of eight elements A, B, C, D, E, F, G and H have the same number of electronic shells but are different in their outermost shells. It was found that elements A and G combine to form an ionic compound which can also be extracted from sea water. Oxides of the elements A and B are basic in nature while those of E and F are acidic. The oxide of elements D is almost neutral.

Q. Which of the following is likely to be halogen?
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 6

Explanation:


Given Information:



  • Atoms of eight elements A, B, C, D, E, F, G, and H have the same number of electronic shells but are different in their outermost shells.

  • Elements A and G combine to form an ionic compound that can be extracted from sea water.

  • Oxides of elements A and B are basic.

  • Oxides of elements E and F are acidic.

  • Oxide of element D is almost neutral.


Analysis:



  • Halogens are elements from Group 17 of the periodic table, which includes elements like fluorine, chlorine, bromine, iodine, and astatine.

  • Halogens have 7 electrons in their outermost shell.

  • From the given information, elements A and G combine to form an ionic compound. This suggests that one of these elements has to be a halogen, as halogens readily form ionic compounds with other elements.

  • Since element A combines with G to form an ionic compound, it is not likely to be a halogen because its oxide is basic and halogen oxides are usually acidic.

  • Therefore, element G is more likely to be a halogen.


Answer: The element G is likely to be a halogen.

Case Based Questions: Periodic Classification of Elements - Question 7
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Atoms of eight elements A, B, C, D, E, F, G and H have the same number of electronic shells but are different in their outermost shells. It was found that elements A and G combine to form an ionic compound which can also be extracted from sea water. Oxides of the elements A and B are basic in nature while those of E and F are acidic. The oxide of elements D is almost neutral.

Q. Which one of the following will have the largest atomic radii?
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 7

Key points:
- Atoms of elements A, B, C, D, E, F, G, and H have the same number of electronic shells.
- Elements A and G combine to form an ionic compound and can be extracted from sea water.
- Oxides of elements A and B are basic in nature.
- Oxides of elements E and F are acidic.
- The oxide of element D is almost neutral.
Analysis:
- The largest atomic radii are usually found at the bottom of a group (vertical column) in the periodic table.
- Elements A and G combine to form an ionic compound, indicating that they belong to the same group in the periodic table.
- Since element A has the largest atomic radii, it is likely to be located at the bottom of its group.
Answer:
- The element with the largest atomic radii is A.
Case Based Questions: Periodic Classification of Elements - Question 8
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Atoms of eight elements A, B, C, D, E, F, G and H have the same number of electronic shells but are different in their outermost shells. It was found that elements A and G combine to form an ionic compound which can also be extracted from sea water. Oxides of the elements A and B are basic in nature while those of E and F are acidic. The oxide of elements D is almost neutral.

Q. Which one of the following elements is likely to be a noble gas?
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 8

To determine which element is likely to be a noble gas, we need to analyze the given information:
1. Elements A and G combine to form an ionic compound:
- Noble gases are chemically inert and do not readily form compounds. Therefore, element A is unlikely to be a noble gas.
2. Oxides of elements A and B are basic in nature:
- Noble gases do not form oxides. Therefore, element B is unlikely to be a noble gas.
3. Oxides of elements E and F are acidic:
- Noble gases do not form acidic oxides. Therefore, element F is unlikely to be a noble gas.
4. The oxide of element D is almost neutral:
- Noble gases do not form oxides. Therefore, element D is unlikely to be a noble gas.
Based on the above analysis, the most likely option for a noble gas is element H. Noble gases have a full outermost shell, making them chemically stable and unreactive. Therefore, element H is the correct answer.
Answer: B: H
Case Based Questions: Periodic Classification of Elements - Question 9
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Read the passage and answer the question from :

Atoms of eight elements A, B, C, D, E, F, G and H have the same number of electronic shells but are different in their outermost shells. It was found that elements A and G combine to form an ionic compound which can also be extracted from sea water. Oxides of the elements A and B are basic in nature while those of E and F are acidic. The oxide of elements D is almost neutral.

Q. To which period the listed elements belong?
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 9
The elements belong to the third period of the periodic table, and have the same number of electron shells but different numbers of electrons in their outermost shells. The number of valence electrons in these elements increases from 1 to 8, on moving from left to right in this period.
Case Based Questions: Periodic Classification of Elements - Question 10
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Read the passage and answer the question from :

Atoms of eight elements A, B, C, D, E, F, G and H have the same number of electronic shells but are different in their outermost shells. It was found that elements A and G combine to form an ionic compound which can also be extracted from sea water. Oxides of the elements A and B are basic in nature while those of E and F are acidic. The oxide of elements D is almost neutral.

Q. Which two elements amongst these are likely to be the non–metals ?
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 10

To identify the two non-metals among the given elements, we need to analyze the information provided in the passage.
1. Atoms with the same number of electronic shells:
- Elements A, B, C, D, E, F, G, and H have the same number of electronic shells.
2. Ionic compound extracted from sea water:
- Elements A and G combine to form an ionic compound that can also be extracted from sea water.
3. Basic and acidic nature of oxides:
- Oxides of elements A and B are basic in nature.
- Oxides of elements E and F are acidic.
- Oxide of element D is almost neutral.
Based on the given information, we can conclude:
- Elements A and G combine to form an ionic compound, indicating they are likely to be metals.
- Oxides of elements A and B are basic, suggesting they are likely to be metals.
- Oxides of elements E and F are acidic, indicating they are likely to be non-metals.
- Oxide of element D is almost neutral, which does not provide conclusive evidence for it being a metal or non-metal.
Therefore, the two elements likely to be non-metals are:
C: E and F
Case Based Questions: Periodic Classification of Elements - Question 11
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Using the given part of the periodic table, answer the question :

Which of these elements have the smallest atomic size?
Case Based Questions: Periodic Classification of Elements - Question 12
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Using the given part of the periodic table, answer the question :

Q. The number of period that the modern periodic table has
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 12
A period is a horizontal row of the periodic table. There are seven periods in the periodic table, with each one beginning at the far left.
Case Based Questions: Periodic Classification of Elements - Question 13
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Using the given part of the periodic table, answer the question :

Write valency of element E.
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 13
The valency of element E is 2 because it requires 2 more electrons to complete its stable gas configuration.
Case Based Questions: Periodic Classification of Elements - Question 14
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Using the given part of the periodic table, answer the question :

Which of them will have largest atomic radii:
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 14
Atomic radii decrease across a period , so A will have largest atomic radius.
Case Based Questions: Periodic Classification of Elements - Question 15
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Using the given part of the periodic table, answer the question :

Q. Identify the elements which have similar chemical properties as the element X.
Case Based Questions: Periodic Classification of Elements - Question 16
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Mendeleev was a Russian chemist, who contributed the most for the development of periodic table of elements wherein the elements were arranged on the basis of their fundamental property, the atomic mass and also on the similarity of chemical properties. Only 63 elements were known at his time. He arranged the 63 elements in the increasing order of their atomic masses and found that there was a periodic recurrence of elements with similar physical and chemical properties. He observed that elements with similar properties fall in the same vertical column. These vertical columns are called groups and horizontal rows of elements are called periods. Mendeleev predicted the existence of certain elements not known at that time and named two of them as Eka-silicon and Eka-aluminium.

Q. Mendeleev arranged the periodic table on the basis of their fundamental property:
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 16
In Mendeleev’s periodic table, elements were arranged on the basis of the fundamental property, atomic mass, and chemical properties.
Case Based Questions: Periodic Classification of Elements - Question 17
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Read the passage and answer the questions :

Mendeleev was a Russian chemist, who contributed the most for the development of periodic table of elements wherein the elements were arranged on the basis of their fundamental property, the atomic mass and also on the similarity of chemical properties. Only 63 elements were known at his time. He arranged the 63 elements in the increasing order of their atomic masses and found that there was a periodic recurrence of elements with similar physical and chemical properties. He observed that elements with similar properties fall in the same vertical column. These vertical columns are called groups and horizontal rows of elements are called periods. Mendeleev predicted the existence of certain elements not known at that time and named two of them as Eka-silicon and Eka-aluminium.

Q. Mendeleev’s periodic table has :
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 17
Mendeleev divided his periodic table in eight groups and seven periods.

Groups from I to VII are meant for normal elements and group VIII is for transition elements.

Groups from I to VII have been divided in two sub groups, while group VIII is meant for three elements.

Periods from 4th to 7th have been divided in two series: 1st series and 2nd series.

Case Based Questions: Periodic Classification of Elements - Question 18
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Read the passage and answer the questions :

Mendeleev was a Russian chemist, who contributed the most for the development of periodic table of elements wherein the elements were arranged on the basis of their fundamental property, the atomic mass and also on the similarity of chemical properties. Only 63 elements were known at his time. He arranged the 63 elements in the increasing order of their atomic masses and found that there was a periodic recurrence of elements with similar physical and chemical properties. He observed that elements with similar properties fall in the same vertical column. These vertical columns are called groups and horizontal rows of elements are called periods. Mendeleev predicted the existence of certain elements not known at that time and named two of them as Eka-silicon and Eka-aluminium.

Q. Eka aluminium and eka silicon were later replaced respectively as :
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 18
The four predicted elements lighter than the rare earth elements, eka-boron, eka-aluminium, eka-manganese, and eka-silicon, proved to be good predictors of the properties of scandium, gallium, technetium and germanium respectively, which each fill the spot in the periodic table assigned by Mendeleev. Mendeleev named these unknown elements using the terms eka, dvi & tri (1,2 & 3 from the ancient Indian language of Sanskrit).
Case Based Questions: Periodic Classification of Elements - Question 19
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Read the passage and answer the questions :

Mendeleev was a Russian chemist, who contributed the most for the development of periodic table of elements wherein the elements were arranged on the basis of their fundamental property, the atomic mass and also on the similarity of chemical properties. Only 63 elements were known at his time. He arranged the 63 elements in the increasing order of their atomic masses and found that there was a periodic recurrence of elements with similar physical and chemical properties. He observed that elements with similar properties fall in the same vertical column. These vertical columns are called groups and horizontal rows of elements are called periods. Mendeleev predicted the existence of certain elements not known at that time and named two of them as Eka-silicon and Eka-aluminium.

Q. How do we classify these newly discovered elements (eka-aluminium and eka-silicon)?
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 19
Classification of Newly Discovered Elements:
- The newly discovered elements, Eka-aluminium and Eka-silicon, can be classified as metalloids.
Explanation:
- Classification of elements is based on their physical and chemical properties.
- Mendeleev arranged the elements in the periodic table based on their atomic mass and similarity of chemical properties.
- Eka-aluminium and Eka-silicon were predicted by Mendeleev and were not known at that time.
- Based on their position and properties in the periodic table, these elements can be classified as metalloids.
- Metalloids are elements that have properties intermediate between metals and nonmetals.
- They exhibit characteristics of both metals and nonmetals, such as conductivity and varying degrees of reactivity.
- Eka-aluminium and Eka-silicon would have properties similar to those of their respective groups in the periodic table, which consist of other metalloids.
- Therefore, the newly discovered elements, Eka-aluminium and Eka-silicon, are classified as metalloids.
Case Based Questions: Periodic Classification of Elements - Question 20
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Read the passage and answer the questions :

Mendeleev was a Russian chemist, who contributed the most for the development of periodic table of elements wherein the elements were arranged on the basis of their fundamental property, the atomic mass and also on the similarity of chemical properties. Only 63 elements were known at his time. He arranged the 63 elements in the increasing order of their atomic masses and found that there was a periodic recurrence of elements with similar physical and chemical properties. He observed that elements with similar properties fall in the same vertical column. These vertical columns are called groups and horizontal rows of elements are called periods. Mendeleev predicted the existence of certain elements not known at that time and named two of them as Eka-silicon and Eka-aluminium.

Q. The elements eka aluminium and eka silicon discovered by Mendeleev later found place in the periodic table. Both of these elements belong to :
Detailed Solution for Case Based Questions: Periodic Classification of Elements - Question 20

Introduction:
Mendeleev, a Russian chemist, made significant contributions to the development of the periodic table of elements. He arranged the elements based on their atomic mass and chemical properties, leading to the discovery of the periodic recurrence of elements with similar characteristics.
Key Points:
1. Only 63 elements were known during Mendeleev's time.
2. Mendeleev arranged these 63 elements in increasing order of their atomic masses.
3. He observed a periodic recurrence of elements with similar physical and chemical properties.
4. Elements with similar properties were found to fall in the same vertical column, known as groups.
5. Horizontal rows of elements were called periods.
6. Mendeleev predicted the existence of certain elements that were not known at that time.
7. He named two of these predicted elements as Eka-silicon and Eka-aluminium.
Answer:
The elements Eka-aluminium and Eka-silicon, which were predicted by Mendeleev, later found their place in the periodic table. Both of these elements belong to Period 4.
Explanation:
1. Eka-aluminium (now known as Gallium) and Eka-silicon (now known as Germanium) were predicted by Mendeleev.
2. These elements were later discovered and confirmed to possess properties that aligned with Mendeleev's predictions.
3. Gallium (Eka-aluminium) is located in Period 4 of the periodic table.
4. Germanium (Eka-silicon) is also found in Period 4 of the periodic table.
5. Hence, the correct answer is D: Period 4.
Conclusion:
Mendeleev's contribution to the development of the periodic table was significant. His arrangement of elements based on atomic mass and chemical properties led to the discovery of elements with similar characteristics. The elements he predicted, Eka-aluminium and Eka-silicon, later found their place in the periodic table in Period 4.
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