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Test: Probability- Assertion & Reason Type Questions - Commerce MCQ


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6 Questions MCQ Test - Test: Probability- Assertion & Reason Type Questions

Test: Probability- Assertion & Reason Type Questions for Commerce 2024 is part of Commerce preparation. The Test: Probability- Assertion & Reason Type Questions questions and answers have been prepared according to the Commerce exam syllabus.The Test: Probability- Assertion & Reason Type Questions MCQs are made for Commerce 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Probability- Assertion & Reason Type Questions below.
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Test: Probability- Assertion & Reason Type Questions - Question 1

Direction: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as

Assertion (A) : If A = A1 ∪ A2… ∪ An, where A1… An are mutually exclusive events then

Reason (R) : Given, A = A1 ∪ A2 ... ∪ An

Since A1...An are mutually exclusive P(A) = P(A1) + P(A2)+ ….+P(An)

Test: Probability- Assertion & Reason Type Questions - Question 2

Direction: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as

Assertion (A) : If A ⊂ B and B ⊂ A then, P(A) = P(B).

Reason (R) : If A ⊂ B then

Detailed Solution for Test: Probability- Assertion & Reason Type Questions - Question 2
Assertion (A) is correct.

A ⊂ B and B ⊂ A ⇒ A = B

Hence, P(A) = P(B).

But (R) is wrong.

Therefore,

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Test: Probability- Assertion & Reason Type Questions - Question 3

Direction: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as

Assertion (A) : If A and B are two mutually exclusive events with = 5/6 and P(B) = 1/3. Then is equal to 1/4.

Reason (R) : If A and B are two events such that P(A) = 0.2, P(B) = 0.6 and P(A|B) = 0.2 then the value of

Detailed Solution for Test: Probability- Assertion & Reason Type Questions - Question 3
Assertion (A) is correct.

[since, given A and B are two mutually exclusive events]

Reason (R) is also correct.

For independent events,

= 0.2.

Test: Probability- Assertion & Reason Type Questions - Question 4

Direction: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as

Assertion (A) : The probability of an impossible event is 1.

Reason (R) : If A is a perfect subset of B and P(A) < P(B), then P(B – A) is equal to P(B) – P(A).

Detailed Solution for Test: Probability- Assertion & Reason Type Questions - Question 4
Assertion (A) is wrong.

If the probability of an event is 0, then it is called an impossible event.

But Reason (R) is correct.

From Basic Theorem of Probability, P(B – A) = P(B) – P(A), this is true only if the condition given in the question is true.

Test: Probability- Assertion & Reason Type Questions - Question 5

Direction: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as

Assertion (A) : Let A and B be two events such that the occurrence of A implies occurrence of B, but not vice-versa, then the correct relation between P(A) and P(B) is P(B) ≥ P(A).

Reason (R) : Here, according to the given statement P(B) = P(A ∪ (A ∩ B)

(∵ A ∩ B = A)

= P(A) + P(A ∩ B)

Therefore, P(B) ≥ P(A)

Test: Probability- Assertion & Reason Type Questions - Question 6

Direction: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as

Assertion (A): Let A and B be two events such that P(A) = 1/5 , while P(A or B) = 1/2. Let P(B) = P, then for P = 3/8 , A and B independent.

Reason (R) : For independent events, P(A ∩ B) = P(A) P(B)

P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

= P(A) + P(B) – P(A) P(B)

⇒ P = 3/8.

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