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MAH-CET MBA Mock Test- 2 - CAT MCQ


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30 Questions MCQ Test - MAH-CET MBA Mock Test- 2

MAH-CET MBA Mock Test- 2 for CAT 2024 is part of CAT preparation. The MAH-CET MBA Mock Test- 2 questions and answers have been prepared according to the CAT exam syllabus.The MAH-CET MBA Mock Test- 2 MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MAH-CET MBA Mock Test- 2 below.
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MAH-CET MBA Mock Test- 2 - Question 1
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Comprehension:

You are presented with a paragraph with options (1), (2), (3), (4) and (5). Read the paragraph carefully and identify which of the given options correctly explains the paragraph or correctly summarizes it, if none of the options correctly explains it mark (5) as your answer.

Question:

Fossils found deep in South Africa's Rising Star cave complex in 2013 have been dated by several expert teams with their findings suggesting the hominids, called Homo naledi, may have lived alongside Homo sapiens. It had earlier been thought that the hominids were millions of years old. A team of 20 scientists from laboratories and institutions around the world, including in South Africa and Australia, established the age of the fossils which suggests that Homo naledi may well have lived at the same time as humans. The focus of the team's research has been South Africa's barely accessible Rising Star Cave system, part of the Cradle of Humankind World Heritage Site, about 50 kilometers northwest of Johannesburg. The area has been an incredibly rich source of artifacts.

Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 1
Option 1 cannot be the summary as it entails that fossils found belonged to Homo sapiens which is incorrect, option 2 also renders wrong information - Rising Star Cave system is not being mentioned as an area which has been a rich source of artifacts, Option 3 suggests that it was already presumed that Homo sapiens lived with Homo naledi which is incorrect as per the paragraph. Option 4 is the correct choice.
MAH-CET MBA Mock Test- 2 - Question 2
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Comprehension:

You are presented with a paragraph with options (1), (2), (3), (4) and (5). Read the paragraph carefully and identify which of the given options correctly explains the paragraph or correctly summarizes it, if none of the options correctly explains it mark (5) as your answer.

Question:

Under normal market conditions, for customers debt funds have nearly the same liquidity as term deposits with banks. However, given illiquid bond markets, they can have serious liquidity problems. The banking system has access to a liquidity window run by the regulator that allows it to tide over any short-term liquidity challenge, including, at its extreme, a bank run. Currently, no such strong liquidity support exists for credit funds. There is the collateralized lending and borrowing operation (CBLO) run by Clearing Corporation of India but with rapidly growing credit funds, this window is grossly inadequate. So we should consider providing liquidity adjustment facility (LAF) access to credit funds too. This would ensure that in the event of a "fund run" there is enough access to liquidity for funds.

Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 2
Option 1 suggests a new liquidity window which is incorrect as per the paragraph (which suggests LAF only), option 2 mentions that credit funds have nowhere to go when liquidity problem arises which is incorrect (they have CBLO but it is inadequate), option 3 suggests that CBLO is inadequate for banks also which is incorrect, option 4 takes only one scenario - bank run - for both banks and credit funds, which is incorrect. Hence option 5 is the correct choice.
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MAH-CET MBA Mock Test- 2 - Question 3
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Comprehension:

You are presented with a paragraph with options (1), (2), (3), (4) and (5). Read the paragraph carefully and identify which of the given options correctly explains the paragraph or correctly summarizes it, if none of the options correctly explains it mark (5) as your answer.

Question:

Rational choice theory assumes that all people try to actively maximize their advantage in any situation and therefore consistently try to minimize their losses. The theory is based on the idea that all humans base their decisions on rational calculations, act with rationality when choosing, and aim to increase either pleasure or profit. Rational choice theory also stipulates that all complex social phenomena are driven by individual human actions. Therefore, if an economist wants to explain social change or the actions of social institutions, he needs to look at the rational decisions of the individuals that make up the whole.

Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 3
Option 1 does not mention that individuals take rational decisions, option 2 incorrectly states that only those individual actions which are rationally motivated make up a social phenomenon but the paragraph says all individuals make rational choices only so there are no irrational choices as per the theory, option 3 also incorrectly states that rational choices only make up those social phenomena which are motivated by profit, option 4 is the correct choice (prudent and logical decisions are rational decisions).
MAH-CET MBA Mock Test- 2 - Question 4
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Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

Who among the following was 2 years old?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 4

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

L was 2 years old.

MAH-CET MBA Mock Test- 2 - Question 5
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Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

Who among the following was seated opposite to the one who was 8 years old?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 5

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

F was seated opposite to C who was 8 years old.

MAH-CET MBA Mock Test- 2 - Question 6
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Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

Who among the following was the youngest?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 6

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

A was the youngest child.

MAH-CET MBA Mock Test- 2 - Question 7
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Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

In which of the following groups was the 3rd person neighbouring the 1st and the 2nd person?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 7

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

G was neighbouring J and A.

MAH-CET MBA Mock Test- 2 - Question 8
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Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

Four of the following bear a similar relationship and hence form a group, who among the following is not a part of that group?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 8

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

Apart from I others were seated at the corners.

MAH-CET MBA Mock Test- 2 - Question 9
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Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

What was the difference between the age of D and C?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 9

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

D was 12 years old and C was 8 years old.

MAH-CET MBA Mock Test- 2 - Question 10
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Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

What was the position of L with respect to the one who was 4 years old?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 10

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

L was to the immediate right of J who was 4 years old.

MAH-CET MBA Mock Test- 2 - Question 11
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Comprehension:

Directions: Twelve children A, B, C, D, E, F, G, H, I, J, K and L were seated around a square table facing the centre. They were aged 1-12 not necessarily in the same order. No two children were of the same age. There was one child at each of the corner and 2 children were seated at each of the sides.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old

• K was to the immediate right of E and he was aged twice as that of E's age

• K and J were seated at a gap of 3 persons

• J was aged 4 times as that of A

• A was seated opposite to D

• D was 6 years elder to G who was to the immediate left of J

• J was opposite to the person who was 11 years old

• B was 2nd to the left of the one who was 3 years old

• The one who was 7 years old was seated opposite to C who was not the youngest

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner

• K and H were born in consecutive years

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old

• B was 9 years old and G was not seated beside the child who was aged 10.

• B was not neighbouring the child who was 8 years old.

Question:

How many persons were younger than the person who was seated opposite to H?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 11

• K was to the immediate right of E and he was aged twice as that of E's age.

• K and J were seated at a gap of 3 persons.

• G was to the immediate left of J.

• J as opposite to the person who was 11 years old.

• K and the one who was 1 year old was seated at a gap of 1 and neither of them was at the corner. Thus, the child between them was at one of the corners.

• K and H were born in consecutive years.

• K was twice as that of E's age. K can be 2, 4, 6, 8, 10 or 12 years old. From the figures, E cannot be 1 year old, thus, E cannot be 2 years old.

• D was at one of the sides and was 3rd to the left of the one who was 10 years old.

• D was 6 years elder to G who was to the immediate left of J. D can be 7, 8, 9, 10, 11 or 12 years old. G can be 1, 2, 3, 4, 5 or 6 years old.

• G was not seated beside the child who was aged 10.

Case 1:

Case 2:

3rd situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 3:

1st situation is invalid as J cannot be 10 years old as his age is 4 times as that of A.

Case 4:

In cases where K is 10 years old, H will be 11 years old as they were born in consecutive years. H cannot be 9 years old as B is 9 years old.

• J was aged 4 times as that of A.

• A was seated opposite to D.

• The one who was 7 years old was seated opposite to C who was not the youngest.

• L was seated 3rd to the left of I who was opposite to the one who was 6 years old.

Case 1:

Scenarios 1 and 2 are invalid as K and H cannot be born in consecutive years and scenario 4th is invalid as we cannot place the C.

Case 2:

1st scenario is invalid as B cannot be 2nd to the left of the one who was 3 years old and scenario 2 is invalid as if G is 3 years old then D should have been 9 years old which is not possible.

Case 3:

• K was aged twice as that of E's age.

• J was aged 4 times as that of A.

• D was 6 years elder to G.

• B was 2nd to the left of the one who was 3 years old.

• K and H were born in consecutive years.

• B was 9 years old.

If G is 3 years old then D should have been 9 years old which is not possible, thus, 1st scenario is invalid. In scenario 3, K and H cannot be born in consecutive years, thus it is invalid.

• B was not neighbouring the child who was 8 years old.

Thus, the final arrangement is as follows:

3 persons were younger than J who was seated opposite to H.

MAH-CET MBA Mock Test- 2 - Question 12
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Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

Four of the following bear a similar relationship and hence form a group, who among the following is not a part of that group?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 12

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

Apart from K others are seated at the corner seats.

MAH-CET MBA Mock Test- 2 - Question 13
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Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

On which of the following seats was C seated?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 13

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

C was seated on the silver coloured seat.

MAH-CET MBA Mock Test- 2 - Question 14
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Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

Who among the following was seated on the purple seat?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 14

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

F was seated on the purple seat.

MAH-CET MBA Mock Test- 2 - Question 15
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Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

Who among the following was/were seated on seat number 4?

I. B

II. I

III. K
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 15

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

Among the given persons only I was seated on seat number 4.

MAH-CET MBA Mock Test- 2 - Question 16
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Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

How many persons were seated to the left (same row) of the golden seat?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 16

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

Only one person was to the left of L who was on the golden seat.

MAH-CET MBA Mock Test- 2 - Question 17
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Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

Who among the following was seated exactly behind J?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 17

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

K was seated exactly behind J.

MAH-CET MBA Mock Test- 2 - Question 18
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Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

On which of the following seats was D seated?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 18

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

D was seated on the black seat.

MAH-CET MBA Mock Test- 2 - Question 19
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Comprehension:

Directions: 12 friends A, B, C, D, E, F, G, H, I, J, K and L went to see a movie. They were seated in two different rows each having six seats. They were seated facing the north. The seats were numbered 1-6 from left to right and were of different colour red, green, yellow, white, grey, black, purple, pink, orange, golden, silver and brown not necessarily in the same order.

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• K was seated 2nd to the left of C

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• G's seat number was twice as that of J's seat number. J was on the white seat

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

• F was not seated neighbouring L or H

Question:

Who were the immediate neighbours of the one who was on the purple seat?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 19

• L was seated 3rd to the left of the one on the silver seat, L was not at the extreme end

• D's seat number was twice as that of L's seat number and they were in different rows

• D and H were seated at a gap of 2 seats

• H's neighbour was seated on the yellow seat

• The red and pink seats had the same seat number.

• F was seated neighbouring the one who was on the red seat and the one who was seated exactly in front of I.

• F was not seated neighbouring L.

Case 1:

Case 2:

Invalid as I cannot be placed in the arrangement.

Case 3:

Case 4:

• K was seated 2nd to the left of C

• G's seat number was twice as that of J's seat number. J was on the white seat

• E was on the orange seat and was at either of the extreme ends

• K was seated either on the pink or the brown seat

Case 1:

1st scenario is invalid as G and J cannot be placed in those arrangements. 2nd scenario is invalid as E cannot be placed in that arrangement.

Case 2:

Scenario 2nd is invalid as J should be on white seat

Case 3:

• The seat number of the green seat was 3 more than the seat number of the grey seat and they were not in the same row

• A was seated exactly in front of the golden seat

• B was 2nd to the right of the one seated on the black seat

Case 1:

The cases are invalid as A cannot be placed in these arrangements.

Case 2:

2nd scenario is invalid as green and grey seats cannot be placed as per the conditions.

Case 3:

Invalid as E cannot be placed in the arrangements.

Thus, the final arrangement is as follows:

B and D were neighbouring F who was on the purple seat.

MAH-CET MBA Mock Test- 2 - Question 20
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Comprehension:

Directions: Kiran, Sushma, Jaya, Pratik, Sonal and Mayank stay in a six floored apartment (from first floor to sixth floor). Each of them lives at different floor. Due to earthquake, the residents of the apartment panic and decide that for next two days two persons would stay at one floor. None of them stay at a floor in which they were already staying.

i) None of them live at top floor after the earthquake. Sonal lives below Kiran before shifting. Mayank lives exactly between Pratik and Sushma before shifting.

ii) Mayank shifts at a gap of one floor below. Pratik shifts at a gap of three floors below.

iii) Kiran and Sonal stays together after shifting. Jaya shifts at a gap of three floors above.

iv) Pratik lives below Sonal after shifting.

Question:

At which floor does Sonal shifts after earthquake?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 20
Jaya shifts four floors above. No one lives at top floor after the earthquake. That means Jaya lives at first floor before earthquake.

Pratik shifts four floors below. There are two cases possible:

Case 1:

Case 2:

Mayank lives exactly between Pratik and Sushma before shifting. Mayank shifts two floors below.

Case 1a:

Sushma lives below Sonal before shifting. But fifth floor and sixth floor is already occupied. So case 1a will be rejected.

Case 1b:

Kiran and Sonal stays together after shifting. That means Sushma lives with jaya after shifting

Case 2:

Kiran and Sonal stays together after shifting. Jaya, Mayank and Pratik live at different floor. There can be only three floors occupied after earthquake. So case 2 will be rejected.

Case 1b can be modified as follows:

Sonal lives below Kiran before shifting.

Pratik lives below Sonal after shifting. None of them stay at a floor in which they were already staying. So Sonal and Kiran can stay at 4th floor.

Sonal shifts to fourth floor after earthquake.

MAH-CET MBA Mock Test- 2 - Question 21
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Comprehension:

Directions: Kiran, Sushma, Jaya, Pratik, Sonal and Mayank stay in a six floored apartment (from first floor to sixth floor). Each of them lives at different floor. Due to earthquake, the residents of the apartment panic and decide that for next two days two persons would stay at one floor. None of them stay at a floor in which they were already staying.

i) None of them live at top floor after the earthquake. Sonal lives below Kiran before shifting. Mayank lives exactly between Pratik and Sushma before shifting.

ii) Mayank shifts at a gap of one floor below. Pratik shifts at a gap of three floors below.

iii) Kiran and Sonal stays together after shifting. Jaya shifts at a gap of three floors above.

iv) Pratik lives below Sonal after shifting.

Question:

At which floor does Kiran lived before shifting?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 21

Jaya shifts four floors above. No one lives at top floor after the earthquake. That means Jaya lives at first floor before earthquake.

Pratik shifts four floors below. There are two cases possible:

Case 1:

Case 2:

Mayank lives exactly between Pratik and Sushma before shifting. Mayank shifts two floors below.

Case 1a:

Sushma lives below Sonal before shifting. But fifth floor and sixth floor is already occupied. So case 1a will be rejected.

Case 1b:

Kiran and Sonal stays together after shifting. That means Sushma lives with jaya after shifting

Case 2:

Kiran and Sonal stays together after shifting. Jaya, Mayank and Pratik live at different floor. There can be only three floors occupied after earthquake. So case 2 will be rejected.

Case 1b can be modified as follows:

Sonal lives below Kiran before shifting.

Pratik lives below Sonal after shifting. None of them stay at a floor in which they were already staying. So Sonal and Kiran can stay at 4th floor.

Kiran lived at fifth floor before shifting.

MAH-CET MBA Mock Test- 2 - Question 22
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Comprehension:

Directions: Kiran, Sushma, Jaya, Pratik, Sonal and Mayank stay in a six floored apartment (from first floor to sixth floor). Each of them lives at different floor. Due to earthquake, the residents of the apartment panic and decide that for next two days two persons would stay at one floor. None of them stay at a floor in which they were already staying.

i) None of them live at top floor after the earthquake. Sonal lives below Kiran before shifting. Mayank lives exactly between Pratik and Sushma before shifting.

ii) Mayank shifts at a gap of one floor below. Pratik shifts at a gap of three floors below.

iii) Kiran and Sonal stays together after shifting. Jaya shifts at a gap of three floors above.

iv) Pratik lives below Sonal after shifting.

Question:

Who lives at 4th floor after earthquake?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 22

Jaya shifts four floors above. No one lives at top floor after the earthquake. That means Jaya lives at first floor before earthquake.

Pratik shifts four floors below. There are two cases possible:

Case 1:

Case 2:

Mayank lives exactly between Pratik and Sushma before shifting. Mayank shifts two floors below.

Case 1a:

Sushma lives below Sonal before shifting. But fifth floor and sixth floor is already occupied. So case 1a will be rejected.

Case 1b:

Kiran and Sonal stays together after shifting. That means Sushma lives with jaya after shifting

Case 2:

Kiran and Sonal stays together after shifting. Jaya, Mayank and Pratik live at different floor. There can be only three floors occupied after earthquake. So case 2 will be rejected.

Case 1b can be modified as follows:

Sonal lives below Kiran before shifting.

Pratik lives below Sonal after shifting. None of them stay at a floor in which they were already staying. So Sonal and Kiran can stay at 4th floor.

Kiran lived at 4th floor after earth quake.

MAH-CET MBA Mock Test- 2 - Question 23
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Comprehension:

Directions: Kiran, Sushma, Jaya, Pratik, Sonal and Mayank stay in a six floored apartment (from first floor to sixth floor). Each of them lives at different floor. Due to earthquake, the residents of the apartment panic and decide that for next two days two persons would stay at one floor. None of them stay at a floor in which they were already staying.

i) None of them live at top floor after the earthquake. Sonal lives below Kiran before shifting. Mayank lives exactly between Pratik and Sushma before shifting.

ii) Mayank shifts at a gap of one floor below. Pratik shifts at a gap of three floors below.

iii) Kiran and Sonal stays together after shifting. Jaya shifts at a gap of three floors above.

iv) Pratik lives below Sonal after shifting.

Question:

How many floors does Kiran shift?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 23

Jaya shifts four floors above. No one lives at top floor after the earthquake. That means Jaya lives at first floor before earthquake.

Pratik shifts four floors below. There are two cases possible:

Case 1:

Case 2:

Mayank lives exactly between Pratik and Sushma before shifting. Mayank shifts two floors below.

Case 1a:

Sushma lives below Sonal before shifting. But fifth floor and sixth floor is already occupied. So case 1a will be rejected.

Case 1b:

Kiran and Sonal stays together after shifting. That means Sushma lives with jaya after shifting

Case 2:

Kiran and Sonal stays together after shifting. Jaya, Mayank and Pratik live at different floor. There can be only three floors occupied after earthquake. So case 2 will be rejected.

Case 1b can be modified as follows:

Sonal lives below Kiran before shifting.

Pratik lives below Sonal after shifting. None of them stay at a floor in which they were already staying. So Sonal and Kiran can stay at 4th floor.

Kiran shifts one floor.

MAH-CET MBA Mock Test- 2 - Question 24
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Comprehension:

Directions: Kiran, Sushma, Jaya, Pratik, Sonal and Mayank stay in a six floored apartment (from first floor to sixth floor). Each of them lives at different floor. Due to earthquake, the residents of the apartment panic and decide that for next two days two persons would stay at one floor. None of them stay at a floor in which they were already staying.

i) None of them live at top floor after the earthquake. Sonal lives below Kiran before shifting. Mayank lives exactly between Pratik and Sushma before shifting.

ii) Mayank shifts at a gap of one floor below. Pratik shifts at a gap of three floors below.

iii) Kiran and Sonal stays together after shifting. Jaya shifts at a gap of three floors above.

iv) Pratik lives below Sonal after shifting.

Question:

Who lives at 3rd floor(before shifting)?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 24

Jaya shifts four floors above. No one lives at top floor after the earthquake. That means Jaya lives at first floor before earthquake.

Pratik shifts four floors below. There are two cases possible:

Case 1:

Case 2:

Mayank lives exactly between Pratik and Sushma before shifting. Mayank shifts two floors below.

Case 1a:

Sushma lives below Sonal before shifting. But fifth floor and sixth floor is already occupied. So case 1a will be rejected.

Case 1b:

Kiran and Sonal stays together after shifting. That means Sushma lives with jaya after shifting

Case 2:

Kiran and Sonal stays together after shifting. Jaya, Mayank and Pratik live at different floor. There can be only three floors occupied after earthquake. So case 2 will be rejected.

Case 1b can be modified as follows:

Sonal lives below Kiran before shifting.

Pratik lives below Sonal after shifting. None of them stay at a floor in which they were already staying. So Sonal and Kiran can stay at 4th floor.

Sonal lived at third floor before shifting.

MAH-CET MBA Mock Test- 2 - Question 25
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Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

Check-up of __ is done on 27th November?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 25
On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

C, who is brother of A is checked on every 27th of March/July/November.

MAH-CET MBA Mock Test- 2 - Question 26
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Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

Find the odd one out.
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 26
On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

F is the male member of the family. Rest are female members of the family.

MAH-CET MBA Mock Test- 2 - Question 27
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Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

How H is related to B?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 27
On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

H is the nephew of B.

MAH-CET MBA Mock Test- 2 - Question 28
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Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

How many persons are checked after third check-up of D and before 31st December of the same year?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 28
On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

B, C and F are checked after D and before 31st December of the same year.

MAH-CET MBA Mock Test- 2 - Question 29
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Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

B is married to __.
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 29
On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

B is unmarried.

MAH-CET MBA Mock Test- 2 - Question 30
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Comprehension:

Directions: In a family of 8 persons, every child has either none or both parents alive. Family doctor visits every month twice i.e. on 8th and 27th of the month. On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

• Check-up of C is done immediately after his wife D and immediately before his son F.

• Check-up of both, F and his sister is done in April.

• G is daughter-in-law of C and she is checked in May.

• Every couple in the family has only one son and only one daughter.

• Sister-in-law of D is checked on 27th June.

• A is aunt of B, who is aunt of H.

• Check-up of E is done in in October. E is not the male member of the family.

Question:

How C is related to H?
Detailed Solution for MAH-CET MBA Mock Test- 2 - Question 30
On every visit, doctor does routine check-up of only 1 person. Check-up of every person is repeated after every 4 months.

Since there are only 8 persons in the family, the person checked on 8th of January will again be checked on 8th of May and thereafter again on 8th of September and cycle will keep repeating.

Now,

Check-up of C is done immediately after his wife D and immediately before his son F.

Check-up of F and his sister is done in April.

G is daughter-in-law of C and she is checked in May.

And,

Every couple in the family has only one son and only one daughter.

Sister-in-law of D is checked on 27th June. The sister-in-law of D has to be the sister of C otherwise the number of persons in the family will become more than 8.

And,

A is aunt of B, who is aunt of H.

So, A is the sister of C and B is the sister of F.

Check-up of E is done in October. E is female.

So, E is the daughter of F and H is the son of F.

And,

C is the grandfather of H.

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