CAT Test: Logical Reasoning & Data Interpretation- 2 Free Online Test 2026

Total CP of magazines of week 1 = 54 × 7.5 + 88 × 8 = 1,109
Total CP of magazines of week 2 = 34 × 8 + 88 × 6.75 + 2 × 6.5 = 879
Total CP of magazines of week 3 = 72 × 6.5 + 36 × 7.75 = 747
Total CP of magazines of week 4 = 84 × 7.75 + 30 × 6 = 831
Total CP of magazines of week 5 = 66 × 6 + 42 × 6.52 = 669
Total CP of magazines of week 6 = 22 × 6.52 + 82 × 8.50 = 840

In week 3, Mr. Brown made the third highest percent of profit.

Hence, answer = 3

Since G₁ has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G₂ could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G₂ must have won 1 round and drew 2 rounds. Since G₃ has two losses, it must have won the remaining 3 rounds for 9 points. G₄ must have won 4 rounds and lost 1 round, and G₅ must have won 1 round and lost 4 rounds.

In Zed Academy. K₁ could have 2 wins or 1 win and 3 draws. K₂ could have 2 wins and 1 draw or 1 win and 4 draws. K₃ must have 2 wins and 2 draws. K₄ and K₅ each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K₃ already has 2 draws, the only possibility is K₂ having 2 wins and 1 draw.

Therefore, K₁, K₄ and K₅ each has 2 wins and 3 losses.

The table below presents this information:


Since G₁ and G₂ drew 3 rounds and K₂ and K₃ also drew three rounds, G₂ must have drawn against both K₂ and K₃ while G₁ must have drawn against K₃. Since G₄ lost against K₁, it must have won all the remaining rounds. Since G₁ lost against K₅, it must have won against K₁, K₂ and K₄.

K₂ lost to G₁ and G₄. Hence, it must have won against G₃ and G₅. K₃ lost to G₄. Hence, it must have won against G₃ and G₅. Since G₃ lost two rounds, it must have won the rounds against K₁, K₄ and K₅. K₄ must have won against G₂ and G₅. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).

K₃ drew the most number of rounds.

Hence, option B is correct.

Since G₁ has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G₂ could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G₂ must have won 1 round and drew 2 rounds. Since G₃ has two losses, it must have won the remaining 3 rounds for 9 points. G₄ must have won 4 rounds and lost 1 round, and G₅ must have won 1 round and lost 4 rounds.

In Zed Academy. K₁ could have 2 wins or 1 win and 3 draws. K₂ could have 2 wins and 1 draw or 1 win and 4 draws. K₃ must have 2 wins and 2 draws. K₄ and K₅ each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K₃ already has 2 draws, the only possibility is K₂ having 2 wins and 1 draw.

Therefore, K₁, K₄ and K₅ each has 2 wins and 3 losses.

The table below presents this information:


Since G₁ and G₂ drew 3 rounds and K₂ and K₃ also drew three rounds, G₂ must have drawn against both K₂ and K₃ while G₁ must have drawn against K₃. Since G₄ lost against K₁, it must have won all the remaining rounds. Since G₁ lost against K₅, it must have won against K₁, K₂ and K₄.

K₂ lost to G₁ and G₄. Hence, it must have won against G₃ and G₅. K₃ lost to G₄. Hence, it must have won against G₃ and G₅. Since G₃ lost two rounds, it must have won the rounds against K₁, K₄ and K₅. K₄ must have won against G₂ and G₅. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).

K₂ lost the rounds against G₁ and G₄.

Hence option A is correct.

Since G₁ has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G₂ could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G₂ must have won 1 round and drew 2 rounds. Since G₃ has two losses, it must have won the remaining 3 rounds for 9 points. G₄ must have won 4 rounds and lost 1 round, and G₅ must have won 1 round and lost 4 rounds.

In Zed Academy. K₁ could have 2 wins or 1 win and 3 draws. K₂ could have 2 wins and 1 draw or 1 win and 4 draws. K₃ must have 2 wins and 2 draws. K₄ and K₅ each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K₃ already has 2 draws, the only possibility is K₂ having 2 wins and 1 draw.

Therefore, K₁, K₄ and K₅ each has 2 wins and 3 losses.

The table below presents this information:


Since G₁ and G₂ drew 3 rounds and K₂ and K₃ also drew three rounds, G₂ must have drawn against both K₂ and K₃ while G₁ must have drawn against K₃. Since G₄ lost against K₁, it must have won all the remaining rounds. Since G₁ lost against K₅, it must have won against K₁, K₂ and K₄.

K₂ lost to G₁ and G₄. Hence, it must have won against G₃ and G₅. K₃ lost to G₄. Hence, it must have won against G₃ and G₅. Since G₃ lost two rounds, it must have won the rounds against K₁, K₄ and K₅. K₄ must have won against G₂ and G₅. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).

The group that scored the least number of points is G₅. G₅ could have won against either K₁ or K₅.

Hence, option D is correct.

Since G₁ has 10 points, it must have won 3 rounds and drew 1 round (winning 2 and drawing 4 is not possible). G₂ could have won 1 round and drew 2 rounds or drew all 5 rounds. From A, G₂ must have won 1 round and drew 2 rounds. Since G₃ has two losses, it must have won the remaining 3 rounds for 9 points. G₄ must have won 4 rounds and lost 1 round, and G₅ must have won 1 round and lost 4 rounds.

In Zed Academy. K₁ could have 2 wins or 1 win and 3 draws. K₂ could have 2 wins and 1 draw or 1 win and 4 draws. K₃ must have 2 wins and 2 draws. K₄ and K₅ each can have 2 wins or 1 win and 3 draws.

The total number of draws that the groups in Zed Academy can have is 3 (since the total number of draws in Alex Academy is 3). Since K₃ already has 2 draws, the only possibility is K₂ having 2 wins and 1 draw.

Therefore, K₁, K₄ and K₅ each has 2 wins and 3 losses.

The table below presents this information:


Since G₁ and G₂ drew 3 rounds and K₂ and K₃ also drew three rounds, G₂ must have drawn against both K₂ and K₃ while G₁ must have drawn against K₃. Since G₄ lost against K₁, it must have won all the remaining rounds. Since G₁ lost against K₅, it must have won against K₁, K₂ and K₄.

K₂ lost to G₁ and G₄. Hence, it must have won against G₃ and G₅. K₃ lost to G₄. Hence, it must have won against G₃ and G₅. Since G₃ lost two rounds, it must have won the rounds against K₁, K₄ and K₅. K₄ must have won against G₂ and G₅. The table below gives the results of the rounds (with the group that won the round in each cell and '-' representing a draw).

K₄ lost three rounds.

Hence answer = 3

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.
Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.
If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.
Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.
Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.
The following table represents the team.

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.
Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.
If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.
Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.
Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.
The following table represents the team.

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.
Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.
If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.
Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.
Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.
The following table represents the team.

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.
Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.
If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.
Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.
Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.

The following table represents the team.

Hence option D

The total number of goals scored by all the players combined is 19. From (i), the winning team (Fierce Werewolves) must have scored 10 goals and the losing team must have scored 9 goals. From (ii), the winning team had the ball for 40 minutes and the losing team had the ball for 50 minutes.
Sean cannot be in Fierce Werewolves because Fierce Werewolves (winning team) had the ball for 40 minutes and Bonnie (possession time: 20 minutes) is in Fierce Werewolves.
If Sean and Casey were in Deadly Sharks with 9 goals and 38 minutes between them, the other three players in the team must have scored 1 goal and a possession time of 12 minutes. In this case, for any combination of three players, the possession time cannot be 50 minutes. Hence, Sean and Casey must be in different teams.
Therefore, Bonnie and Casey must be in Fierce Werewolves and Sean in Deadly Sharks. Bonnie and Casey together scored 8 goals and have a possession time of 33 minutes. The remaining players must have scored 2 goals and a possession time of 7 minutes. The 2 goals must have been scored by a single player (Alex, William or Rjay) since two players could not have scored 1 goal each. Between Alex, William and Rjay, only William can be a part of Fierce Werewolves because the other two have a higher possession time. The remaining two players must not have scored any goals and have a possession time of 5 minutes. From the table we can see that Charlie must be a part of Fierce Werewolves. One among Michael and Harry must be a player of Fierce Werewolves.
Deadly Sharks must comprise Sean, Alex, Rjay, Jamie, and one among Michael and Harry.
The following table represents the team.

The second least possession time, i.e. 3 minutes, is that of Charlie in "Fierce Werewolves", the winning team.
The second least possession time is that of Rjay, i.e. 10 minutes, in "Deadly Sharks", the losing team.
Thus, the possession time of Charlie in the winning team is less by 7 minutes.

Given,
Richard earned a total of 22.5 points and he was not the first in any level. The only way he can win 22.5 points without being first in any level is if he earned 7.5 in two levels, 5 in one level and 2.5 in another level.
From (2), Connor and Poppy did not win the highest points in the game.
From (6), Sarah also did not win the highest points in the game.
From (4), one of the persons was the first in two levels and this person did not win the highest points. This person must have earned a minimum of 10 + 10 + 2.5 + 2.5 = 25 points in the game. The person who earned the highest points must have earned more than this. From this, we can infer that Richard also cannot be the person who earned the highest points.
Hence, only Mason can be the person who earned the highest points.
From (5), Mason was the first in one level. He is not the third in any level. Also, Richard was the second in two levels (since he earned 7.5 in two levels). Hence, the maximum points that Mason can win = 10 + 7.5 + 7.5 + 2.5 = 27.5 points.
Since Mason has to win more than 25 points, he must have earned 27.5 points. The person who was first in two levels must have earned 25 points (this is the only way for him to have earned less points than Mason).
From (2) and (6), Poppy and Sarah cannot be the person who earned 25 points.
Hence, Connor must be the person who earned 25 points. This is possible if he was the first in two levels and fourth/fifth in two other levels.
From (2), Poppy must have earned 20 points. This is possible only if Poppy was the first in one level, the third in another level and fourth/fifth in two levels (Poppy cannot be the second in any level because Richard and Mason are second in two levels each). The points that Poppy wins in this case = 10 + 5 + 2.5 + 2.5 = 20 points.
Sarah must have been the third in two levels and fourth/fifth in two levels. The total points that Sarah earned = 5 + 5 + 2.5 + 2.5 = 15 points.
The following table presents the positions of the five persons in the four levels and the total points earned by them in the game.

The highest points earned by any person are 27.5 points.

Given,
Richard earned a total of 22.5 points and he was not the first in any level. The only way he can win 22.5 points without being first in any level is if he earned 7.5 in two levels, 5 in one level and 2.5 in another level.
From (2), Connor and Poppy did not win the highest points in the game.
From (6), Sarah also did not win the highest points in the game.
From (4), one of the persons was the first in two levels and this person did not win the highest points. This person must have earned a minimum of 10 + 10 + 2.5 + 2.5 = 25 points in the game. The person who earned the highest points must have earned more than this. From this, we can infer that Richard also cannot be the person who earned the highest points.
Hence, only Mason can be the person who earned the highest points.
From (5), Mason was the first in one level. He is not the third in any level. Also, Richard was the second in two levels (since he earned 7.5 in two levels). Hence, the maximum points that Mason can win = 10 + 7.5 + 7.5 + 2.5 = 27.5 points.
Since Mason has to win more than 25 points, he must have earned 27.5 points. The person who was first in two levels must have earned 25 points (this is the only way for him to have earned less points than Mason).
From (2) and (6), Poppy and Sarah cannot be the person who earned 25 points.
Hence, Connor must be the person who earned 25 points. This is possible if he was the first in two levels and fourth/fifth in two other levels.
From (2), Poppy must have earned 20 points. This is possible only if Poppy was the first in one level, the third in another level and fourth/fifth in two levels (Poppy cannot be the second in any level because Richard and Mason are second in two levels each). The points that Poppy wins in this case = 10 + 5 + 2.5 + 2.5 = 20 points.
Sarah must have been the third in two levels and fourth/fifth in two levels. The total points that Sarah earned = 5 + 5 + 2.5 + 2.5 = 15 points.
The following table presents the positions of the five persons in the four levels and the total points earned by them in the game.

Connor earned 2.5 points in two levels. In these two levels, Sarah could have got 2.5 points. Hence, we cannot say that Connor definitely earned more than Sarah in at least three levels.
Richard could have earned 2.5 points in the same level that Sarah earned 2.5 points. In the level that Richard earned 5 points, Sarah could have earned only 2.5 points (since two persons could not have earned 5 points). In the other two levels that Richard earned 7.5 points, Sarah would have got less points than Richard. Hence, Richard would have definitely earned higher points than Sarah in three levels. Poppy earned 2.5 points in two levels. In these two levels, Sarah could have earned 2.5 points. Hence, we cannot say that Poppy definitely earned more than Sarah in at least three levels. Mason earned 10 points in one level and 7.5 points in two levels. In all the three levels, Mason would have earned higher points than Sarah. Hence, the given condition is satisfied for two persons, Richard and Mason.

Given,
Richard earned a total of 22.5 points and he was not the first in any level. The only way he can win 22.5 points without being first in any level is if he earned 7.5 in two levels, 5 in one level and 2.5 in another level.
From (2), Connor and Poppy did not win the highest points in the game.
From (6), Sarah also did not win the highest points in the game.
From (4), one of the persons was the first in two levels and this person did not win the highest points. This person must have earned a minimum of 10 + 10 + 2.5 + 2.5 = 25 points in the game. The person who earned the highest points must have earned more than this. From this, we can infer that Richard also cannot be the person who earned the highest points.
Hence, only Mason can be the person who earned the highest points.
From (5), Mason was the first in one level. He is not the third in any level. Also, Richard was the second in two levels (since he earned 7.5 in two levels). Hence, the maximum points that Mason can win = 10 + 7.5 + 7.5 + 2.5 = 27.5 points.
Since Mason has to win more than 25 points, he must have earned 27.5 points. The person who was first in two levels must have earned 25 points (this is the only way for him to have earned less points than Mason).
From (2) and (6), Poppy and Sarah cannot be the person who earned 25 points.
Hence, Connor must be the person who earned 25 points. This is possible if he was the first in two levels and fourth/fifth in two other levels.
From (2), Poppy must have earned 20 points. This is possible only if Poppy was the first in one level, the third in another level and fourth/fifth in two levels (Poppy cannot be the second in any level because Richard and Mason are second in two levels each). The points that Poppy wins in this case = 10 + 5 + 2.5 + 2.5 = 20 points.
Sarah must have been the third in two levels and fourth/fifth in two levels. The total points that Sarah earned = 5 + 5 + 2.5 + 2.5 = 15 points.
The following table presents the positions of the five persons in the four levels and the total points earned by them in the game.

The only persons who were second in any level were Richard and Mason. In the level that Mason was first, Richard must be second. Hence, the statement given in option (1) is definitely true. The other statements need not necessarily be true.

Given,
Richard earned a total of 22.5 points and he was not the first in any level. The only way he can win 22.5 points without being first in any level is if he earned 7.5 in two levels, 5 in one level and 2.5 in another level.
From (2), Connor and Poppy did not win the highest points in the game.
From (6), Sarah also did not win the highest points in the game.
From (4), one of the persons was the first in two levels and this person did not win the highest points. This person must have earned a minimum of 10 + 10 + 2.5 + 2.5 = 25 points in the game. The person who earned the highest points must have earned more than this. From this, we can infer that Richard also cannot be the person who earned the highest points.
Hence, only Mason can be the person who earned the highest points.
From (5), Mason was the first in one level. He is not the third in any level. Also, Richard was the second in two levels (since he earned 7.5 in two levels). Hence, the maximum points that Mason can win = 10 + 7.5 + 7.5 + 2.5 = 27.5 points.
Since Mason has to win more than 25 points, he must have earned 27.5 points. The person who was first in two levels must have earned 25 points (this is the only way for him to have earned less points than Mason).
From (2) and (6), Poppy and Sarah cannot be the person who earned 25 points.
Hence, Connor must be the person who earned 25 points. This is possible if he was the first in two levels and fourth/fifth in two other levels.
From (2), Poppy must have earned 20 points. This is possible only if Poppy was the first in one level, the third in another level and fourth/fifth in two levels (Poppy cannot be the second in any level because Richard and Mason are second in two levels each). The points that Poppy wins in this case = 10 + 5 + 2.5 + 2.5 = 20 points.
Sarah must have been the third in two levels and fourth/fifth in two levels. The total points that Sarah earned = 5 + 5 + 2.5 + 2.5 = 15 points.
The following table presents the positions of the five persons in the four levels and the total points earned by them in the game.

Connor scored the first position in levels twice.

Given,
Richard earned a total of 22.5 points and he was not the first in any level. The only way he can win 22.5 points without being first in any level is if he earned 7.5 in two levels, 5 in one level and 2.5 in another level.
From (2), Connor and Poppy did not win the highest points in the game.
From (6), Sarah also did not win the highest points in the game.
From (4), one of the persons was the first in two levels and this person did not win the highest points. This person must have earned a minimum of 10 + 10 + 2.5 + 2.5 = 25 points in the game. The person who earned the highest points must have earned more than this. From this, we can infer that Richard also cannot be the person who earned the highest points.
Hence, only Mason can be the person who earned the highest points.
From (5), Mason was the first in one level. He is not the third in any level. Also, Richard was the second in two levels (since he earned 7.5 in two levels). Hence, the maximum points that Mason can win = 10 + 7.5 + 7.5 + 2.5 = 27.5 points.
Since Mason has to win more than 25 points, he must have earned 27.5 points. The person who was first in two levels must have earned 25 points (this is the only way for him to have earned less points than Mason).
From (2) and (6), Poppy and Sarah cannot be the person who earned 25 points.
Hence, Connor must be the person who earned 25 points. This is possible if he was the first in two levels and fourth/fifth in two other levels.
From (2), Poppy must have earned 20 points. This is possible only if Poppy was the first in one level, the third in another level and fourth/fifth in two levels (Poppy cannot be the second in any level because Richard and Mason are second in two levels each). The points that Poppy wins in this case = 10 + 5 + 2.5 + 2.5 = 20 points.
Sarah must have been the third in two levels and fourth/fifth in two levels. The total points that Sarah earned = 5 + 5 + 2.5 + 2.5 = 15 points.
The following table presents the positions of the five persons in the four levels and the total points earned by them in the game.

Sum of the points earned by Connor, Mason and Sarah = 25 + 27.5 + 15 = 67.5