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Position, Path Length & Displacement - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Position, Path Length & Displacement (5 Questions)

You can prepare effectively for NEET Physics Class 11 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Position, Path Length & Displacement". These 5 questions have been designed by the experts with the latest curriculum of NEET 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 5 minutes
  • - Number of Questions: 5

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Test: Position, Path Length & Displacement - Question 1

Which of the following statements is incorrect?

Detailed Solution: Question 1

In one dimensional motion, the path length and magnitude of displacement are equal only if the object does not change its direction during the course of motion. In all other cases, the path length is greater than the magnitude of displacement.

Test: Position, Path Length & Displacement - Question 2

The numerical ratio of distance to displacement is 

Detailed Solution: Question 2

The distance travelled by an object is always equal to or greater than the magnitude of its displacement because:

  • Displacement is the straight-line distance between the initial and final positions.
  • Distance is the total path length taken by the object.

Therefore, the relationship can be expressed as:

Distance ≥ |Displacement|

Test: Position, Path Length & Displacement - Question 3

Which of the following statements is incorrect?

Detailed Solution: Question 3

When a particle returns to it's initial position, Initial and final positions will be same therefore net displacement of the particle is zero. Hence the given statement is false.

Test: Position, Path Length & Displacement - Question 4

If a man goes 10 m toward north and 20 m toward east, then his displacement is

Detailed Solution: Question 4

Test: Position, Path Length & Displacement - Question 5

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:

Detailed Solution: Question 5

Displacement in first eight steps = (5 - 3) m = 2 m

Time taken for first eight steps = 8 s

Time taken by the drunkard to cover first 6 m of journey = 8/2 * 6 = 24 s

If the drunkard takes 5 steps more, he will fall into the pit. So the time taken by the drunkard to cover last five steps = 5 s

Total time taken = 24 s + 5 s = 29 s

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