Practice Test: Mechanical Engineering (ME)- 11 - Mechanical Engineering MCQ

Hence the ratio of time taken on foot/by bicycle is = 2/1.

Now, since total time taken is 15 hrs.

Therefore, journey on foot is for 10hrs.

Hence, distance covered on foot = 10×5 = 50 km.

A = P(1+R/100)^t; Cl= A-p

Given, compound interest compounded half yearly on a certain sum of money at 10% per annum for 1 year is Rs. 246.

∴ R = 10/2 = 5%

t = 1 year = 2 half years

CI = Rs. 246

P=?

A = CI + P

⇒ A = P + 246

∴ P + 246 = P (1+(5/100))²

⇒ P + 246 = P × 1.05²

⇒ 246 = 1.1025P – P

⇒ 246 = 0.1025P

⇒ P = 2400

Now, SI on the same sum for 3 years at 6% per annum.

∴ R = 7%

t = 2.5 years

SI = (2400 x 7 x 2.5)/100

⇒ SI = Rs. 420

M A J O R I T Y and each part is rewritten in reverse sequence

O J A M Y T I R.

Position of letters in the alphabet is 15/10/1/13 and 25/20/9/18 and position of letters in the given code PKBN/XSHQ is 16/11/2/14 and 24/19/8/17. HVBEQDSG

On comparison, you notice, the first half is obtained by adding ‘1’ and second half is obtained by subtraction ‘1’.

The number which represents lion, cow and goat but not tiger has been shown in blue shaded part which is 9.

According to question (x+y)/2 = 2z

x + y = 4z

Given, x+y+z = 15 × 3 = 45 lakh

4z + z = 45 ⇒ 5z = 45

z = 9 Lakh

Accommodate is the correctly spelt word. It means to provide lodging or sufficient space to someone. Alterd is the incorrect spelling of the word Altered. It means to change in character or composition, typically in a comparatively small but significant way.

Aquire is the incorrect spelling of the word Acquire. It means to buy or obtain an asset for oneself. Hence, option B is the correct answer.

We can show the given data in the following figure :

From the figure, E is in north-west direction of C.

Using Pythagoras theorem,

distance between E and C =

'pains' in place of 'pain' because the meaning of pain is suffering. Some nouns change their meaning if they are used in plural.

E.g. Pain (physical) Pains (sufferings/tension)

Colour (hue) Colours (hues/ flag)

3. Climax, 2. Conclusion, 1. Culmination, 4. Cultivation.

So the correct sequence is 3, 2, 1, 4.

Let x be the number of days required by Gaviria to finish the project alone

Gustavo’s speed = W/2

Pablo’s speed = W/3

Gaviria’s speed = W/x

Combined speed = W/6

Gaviria will take 6 days to finish alone.

Λ₁ + λ₂ + λ₃ = 13

Λ₁⋅λ₂⋅λ₃ = 32 and det⁡(A−I) = 0

∴ (λ₁−1) (λ₂−1) (λ₃−1) = 0

From (i), (ii) and (iii), we get

From (i), (ii) and (iii), we

w = weight of filled water = 500 KN

W = weight of cargo ships + weight of filled water = 50000 + 500 = 50500 KN

θ = tilted angle = 5^∘

x = mean distance of water from the centre of the ships = 12 m

Ship’s boat after filled water

The metacentric height,

Where, ρ = Density of water = 103kg/m³

A = Area of upstream face of dam = H×1= 5m²x¯= Centroid of the surface at a vertical depth below free surface of liquid = H/2 = 2.5m Total pressure = 10³ × 10 × 5 × 2.5 = 125000N = 125KN

Centre of pressure, h = x¯+1G/AR IC = area moment of inertia about axis passing through the centroid of area and parallel to water surface level

T₁ = 15 +273 = 288

T₂ = 90 + 273 = 363

So, change in enthalpy is dH = mCP(T₂ – T₁)

dH = 3 x 0.909 x (363- 288)

dH = 204.525KJ

Stress-strain curve for perfectly plastic of non-strain hardening materials is shown below

As the longitudinal stress is less than the hoop stress, the cracks will develop along the longitudinal axis firstly.

f₂ = longitudinal stress = pd/4t

f₁ = circumferential stress = pd/2t

First cracks will develop along the longitudinal axis as f₁ = 2× f₂

When GrL/Re²L = 1, the effect of both free and forced convection should be considered.

When GrL/Re²L ≫ 1, effect of forced convection neglected

When GrL/Re²L ≪ 1, effect of free convection neglected

Area OABC is the area of feasible solution.

So value of objective function on feasible area points

At O(0,0), X = 0

At A(0,6), X = 2(6)=12

At B(2,6), X = 3(2)+2(6)=18

At C(3,0), X =3(3)=9

So the optimal value of X = 18

Waiting time in queue, W_q = 2.5min = 1/24hr

W_q = p²(1−ρ)λ = 1/24

ρ = traffic intensity or the proportion of time that a server actually spends with customers

2p² + p − 1 = 0

2p² + 2p − p − 1 = 0

ρ = −1(not possible) ρ = 1/2 = 0.5 = 50%

Step I. Construction of S-N diagram

log₁₀ ⁡(0.9Sut) = 2.73

log₁₀ ⁡(Se) = 2

log_10⁡ (N) = 4.4

The S-N curve for the rotating bar is shown.

Step II. Fatigue strength (Sf)

The equation of line AB

log₁₀ ⁡Sf − 2.73 =

Sf = 245.094MPa

Double point cutting tool = drilling

Multi point cutting tool = broaching, milling etc.

Δh_max = .1² × 150 = 1.5mm

Minimum no of passes n = Δhrequired/Δhmax = 3/1.5

Minimum no of passes n = 2

P = 15394.804 × 350 × 2 × 10

d₀/d_f

P = 15394.804 × 350 × 2 × 1n

140/70

P = 7.46 MN

W_net = W_T – W_P

W_T = h₁ – h₂

As, s₁ = s₂ = s₃ + xs_fg = 0.5926 + 7.6361 x

x = 0.838

h₂ = h₃ + x hfg = 173.88 + 0.838 × 2403.1 = 2187.68 kJ/kg

W_T = h₁ – h₂ = 3159.3 – 2187.68 = 971.62 kJ/kg

W_P = v_f (p₁−p₂) = 0.001008 × (20 – 0.08) × 10² = 2 kJ/kg

h₄ – h₃ = 2

h₄ = 175.88 kJ/kg

W_net = 971.62 – 2 = 969.62 kJ/kg

Heat added, Q₁ = h₁ – h₄ = 2983.42 kJ/kg

?cycle = 969.62/2983.42 = 0.325 = 32.5 %

= 2 × 2πN/60 × V

= 2×2×3.14×150×15/60

= 471m/s²

The EOQ in shortage model is given by

Q* = EQQ QUANTITY

D = DEMAND PER YEAR

C₀ = ORDERING COST PER YEAR

C_C = CARRYING COST PER UNIT PER YEAR

C_S = SHORTAGE COST PER UNIT PER YEAR

= 516.39

= MAXIMUM INVENTORY = Q*- S* = 258.193

Applying L-Hospital Rule

maximum bending moment will be at x = L

ML = wL²/3

total load is given which is W = wL/2 (area of triangular distributed load)

So

Bending moment at fixed end = wl²/3

given total load 21 kN

Total load ⇒ wl/2 = 21

wl = 42

= 42 × 5 × 10³/3

= 70,000 Nmm