Olympiad Test: Number, Ranking & Time Sequence - Free MCQ with solutions

When Pankaj shifts 3 places towards Raju his position is 15th from right and 10th from left.
∴ No. of students = 15 + 10 – 1 = 24 students. 

1st November is Wednesday. 
31st October is Tuesday. 
29th, 22th, 15th, 8th, 1st October was Sundays. 

Manish’s position is 19th from both ends
Total no. of students = 19 + 19 – 1
= 38 – 1
= 37.

Here, Number students behind the nitin in rank = 49 – 18 = 31
Navin’s rank from last = 32nd.

The new number after rearrangement

7th digit from right end = 4 
3rd digit to the right of 4 = 8.

There is no such number that is divisible by 9 but not by 3.

Number of boys to the right of Anish = 12 - 1 = 11 boys
Total number of boys in the row = position of Anish from left + number of boys to the right of Anish = 4 + 11 = 15
Therefore, the number of boys to be added to the line such that there are 28 boys in the line be x
Then,
15 + x = 28
x = 28 - 15
x = 13
Hence, 13 is the correct answer.

25th August is Thursday.
29th August is Monday.
Then 29th, 22th, 15th, 8th, and 1st days are Monday.
So, there are 5 Monday in that month.

Two months will have identical calendars if they start on the same weekday and have the same number of days. In a non-leap year, January has 31 days and begins on the same weekday as October, which also has 31 days, so their calendars match exactly.

Total number of boys = 6 + 10 + 8 = 24.

100 years have 5 odd days, so the last day of the 1st century = Friday. 
200 years have 10 odd days = 3 odd days.
The last date of the 2nd century = Wednesday.
300 years have 5 × 3 = 15 odd days = 1 odd day.
Last day of 3rd century = Monday.
Last day of 4th century = Sunday.
So, Tuesday, Thursday & Saturday cannot be the last day.

A leap year has 366 days
366 days = 52 weeks + 2 days
No. of odd days in a leap year = 2.

Position of Shanti from the other side = (43 – 27) + 1 = 17.

T_r ​= 11,  B_r ​= 31
⇒ no. of students = T_r ​+ B_r ​− 1 = 11 + 31 − 1 = 41
∴ Total no. of students = 41.