Math Olympiad Test: Statistics- 1 - Class 10 MCQ

# Math Olympiad Test: Statistics- 1 - Class 10 MCQ

Test Description

## 10 Questions MCQ Test - Math Olympiad Test: Statistics- 1

Math Olympiad Test: Statistics- 1 for Class 10 2024 is part of Class 10 preparation. The Math Olympiad Test: Statistics- 1 questions and answers have been prepared according to the Class 10 exam syllabus.The Math Olympiad Test: Statistics- 1 MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Math Olympiad Test: Statistics- 1 below.
Solutions of Math Olympiad Test: Statistics- 1 questions in English are available as part of our course for Class 10 & Math Olympiad Test: Statistics- 1 solutions in Hindi for Class 10 course. Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free. Attempt Math Olympiad Test: Statistics- 1 | 10 questions in 10 minutes | Mock test for Class 10 preparation | Free important questions MCQ to study for Class 10 Exam | Download free PDF with solutions
 1 Crore+ students have signed up on EduRev. Have you?
Math Olympiad Test: Statistics- 1 - Question 1

### If the mean of following distribution is 25, then what is the value of x?

Detailed Solution for Math Olympiad Test: Statistics- 1 - Question 1

⇒ 325 + 25x = 285 + 45x
⇒ 20x = 40 ⇒ x = 40/20 = 2

Math Olympiad Test: Statistics- 1 - Question 2

### The median of first 10 Prime numbers is

Detailed Solution for Math Olympiad Test: Statistics- 1 - Question 2

The first 10 Prime numbers are
2, 3, 5, 7, 11, 13, 17, 19, 23, 29
∴ n = 10, which is even

Math Olympiad Test: Statistics- 1 - Question 3

### The arithmetic mean of a data is 48 and mode is 24 then the median is

Detailed Solution for Math Olympiad Test: Statistics- 1 - Question 3

Here Mean = 48; Mode = 24
∴ Mode =  3 Median - 2 Mean
∴ 24 =  3 Median - 2 × 48
⇒ 3 Median = 24 + 96
⇒ Median = 120/3
= 40

Math Olympiad Test: Statistics- 1 - Question 4

If the arithmetic mean of x, x + 3, x + 6, x + 9, x + 12 is 10 then what is the value of x.

Detailed Solution for Math Olympiad Test: Statistics- 1 - Question 4

Given
⇒ 5x + 30 = 50
⇒ 5x = 20 ⇒ x = 4

Math Olympiad Test: Statistics- 1 - Question 5

In the given distribution, which is the modal class?

Detailed Solution for Math Olympiad Test: Statistics- 1 - Question 5

The class having maximum frequency is called modal class i.e. 30–40.

Math Olympiad Test: Statistics- 1 - Question 6

What is the value of P, if the mean of the following distribution is 7.5?

Detailed Solution for Math Olympiad Test: Statistics- 1 - Question 6

⇒ 307.5 + 7.5P = 303 + 9P
⇒ 1.5 P = 4.5 ⇒ P = 4.5/1.5 = 3

Math Olympiad Test: Statistics- 1 - Question 7

The median of the given data 41, 43, 127, 99, 61, 71, 92, 58, 57, is 61. If 58 is replaced by 85, then what is difference of the new median and the given median?

Detailed Solution for Math Olympiad Test: Statistics- 1 - Question 7

The given data in ascending order is 41, 43, 57, 61, 71, 85, 92, 99, 127
n = 9 (odd)

Required Difference = 71 - 61 = 10

Math Olympiad Test: Statistics- 1 - Question 8

What is the interquartile range for the data 2, 1, 0, 3, 1, 2, 3, 4, 3, 5?

Detailed Solution for Math Olympiad Test: Statistics- 1 - Question 8

The given data in ascending order is 0, 1, 1, 2, 2, 3, 3, 3, 4, 5
n = 10 (even)
Lower quartile = n/4 th = 10/4th = 2.5th
= 3rd term
= 1

Math Olympiad Test: Statistics- 1 - Question 9

If the mean of first n natural number is 15, what is the value of n?

Detailed Solution for Math Olympiad Test: Statistics- 1 - Question 9

Math Olympiad Test: Statistics- 1 - Question 10

The arithmetic mean and mode of a data are 24 and 12 respectively. What is the median of that data?

Detailed Solution for Math Olympiad Test: Statistics- 1 - Question 10

∵ Mode = 3 Median - 2 Mean
∴ 12 =  3 Median - 2 × 24
⇒ Median = 60/3 = 20