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Olympiad Test Level 1: Computing Operations - Class 3 MCQ


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20 Questions MCQ Test - Olympiad Test Level 1: Computing Operations

Olympiad Test Level 1: Computing Operations for Class 3 2024 is part of Class 3 preparation. The Olympiad Test Level 1: Computing Operations questions and answers have been prepared according to the Class 3 exam syllabus.The Olympiad Test Level 1: Computing Operations MCQs are made for Class 3 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test Level 1: Computing Operations below.
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Olympiad Test Level 1: Computing Operations - Question 1

Find the missing number 165 + 52 + 10 = 52 + ? + 10

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 1

According to order

property of addition, the numbers can be added in any order. So,

165 + 52 + 10 = 52 + 165 + 10

Olympiad Test Level 1: Computing Operations - Question 2

If A = 25 + 7,825 and B = 4,525 + 75, find the difference between A and B.

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 2
- To find A, add 25 and 7,825:
A = 25 + 7,825
A = 7,850
- To find B, add 4,525 and 75:
B = 4,525 + 75
B = 4,600
- Now, subtract B from A to find the difference:
A – B = 7,850 – 4,600
A – B = 3,250
- The correct answer is option 3: 3,250.
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Olympiad Test Level 1: Computing Operations - Question 3

Look at the two number sentences shown below :

8 × _ = 40, 40 ÷ 8 = _

Which number goes in both blank spaces to make each number sentence true ?

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 3

8 × 5 = 40 and 40 ÷ 8 = 5

Olympiad Test Level 1: Computing Operations - Question 4

Simplify : 100 – 10 – (100 – 10)

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 4
  • Start with the expression: 100 – 10 – (100 – 10).
  • First, simplify the parentheses: (100 – 10) equals 90.
  • Now the expression looks like: 100 – 10 – 90.
  • Simplify further: 100 – 10 equals 90.
  • Finally, 90 – 90 equals 0.


Correct Answer: 0
Olympiad Test Level 1: Computing Operations - Question 5

The sum of 1,727 and 6,475 is ________.

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 5

1,727 + 6,475 = 8,202

Olympiad Test Level 1: Computing Operations - Question 6

347 × 23 = ____________

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 6

The product of one’s digits, that is, 3×7 = 21. So, the one digit of the product will be 1. The

product of 347 and 23 is 7,981.

Olympiad Test Level 1: Computing Operations - Question 7

112 is divisible by which one of the following numbers ?

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 7

Last digit is 2, so it is an even number. Thus 112 is divisible by 2. The factors of 112 are 1, 2, 4, 7, 8, 14, 16, 28, 56, and 112.

Olympiad Test Level 1: Computing Operations - Question 8

Simplify: 4 + 14 + 1

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 8

4 + 14 + 1 = 18 + 1 = 19

Olympiad Test Level 1: Computing Operations - Question 9

How many numbers given in the figure come in the table of 7 ?

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 9
The numbers divisible by 7 are 14, 7, 49, 7, 56, 21, 49, 63, 7, 21 and 28.
Olympiad Test Level 1: Computing Operations - Question 10

Which of the following represents the additive identity property of 0 ?

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 10

It means that additive identity is “0” as adding 0 to any number, gives the sum as the number itself. For any set of numbers, that is, all integers, rational numbers, complex numbers, the additive identity is 0.

So here, 14 + 0 = 14 is the correct answer.

Olympiad Test Level 1: Computing Operations - Question 11

Difference between the two numbers is 400. If one of the numbers is 300 greater than 600, find the other number.

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 11

One number is 300 greater than 600 = 600 + 300 = 900
Difference = 400
Other number = 900 – 400 = 500

Olympiad Test Level 1: Computing Operations - Question 12

Find the missing number to fill in the blank box

111 + 9 = ⌧+ 7

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 12

111 + 9 = 120 = 113 +7

Olympiad Test Level 1: Computing Operations - Question 13

How many times 7 are there in 63 ?

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 13
  • Start by dividing 63 by 7.
  • 63 ÷ 7 equals 9.
  • So, there are nine 7s in 63.
Olympiad Test Level 1: Computing Operations - Question 14

Find the value of A, B and C respectively.

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 14

Olympiad Test Level 1: Computing Operations - Question 15

In an examination hall, 500 chairs were arranged equally in 10 rows. How many chairs are there in each row ?

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 15

Number of chairs in each row = 500 ÷ 10 = 50

Olympiad Test Level 1: Computing Operations - Question 16

Which of the following is true ?

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 16

43 is more than 33.

Olympiad Test Level 1: Computing Operations - Question 17

Add the 6,523 + 2,364. Which one of the following numbers is in the hundreds place of the resulting addition ?

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 17

6523 + 2364 = 8887

So, digit 8 is hundreds of places.

Olympiad Test Level 1: Computing Operations - Question 18

When we divide 0 by 3, we get _______.

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 18

0 divided by any number gives 0.

So, 0 ÷ 3 = 0.

Olympiad Test Level 1: Computing Operations - Question 19

I am the smallest odd number that comes after 4,386. Add 632 to me. What number am I now ?

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 19

Smallest odd number after 4,386 is 4,387.

4,387 + 632 = 5,019

Olympiad Test Level 1: Computing Operations - Question 20

Sandhya cycled from Tree B to Tree C. She then cycled from Tree C to Tree A. How far did she cycle altogether ?

Detailed Solution for Olympiad Test Level 1: Computing Operations - Question 20

Sandhya Travelled B to C is 379 m , then she travelled C to A which is 379 + 262 = 641 m
Total she travelled = 1,020 m

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