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NEET Part Test - 2 - NEET MCQ


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30 Questions MCQ Test - NEET Part Test - 2

NEET Part Test - 2 for NEET 2024 is part of NEET preparation. The NEET Part Test - 2 questions and answers have been prepared according to the NEET exam syllabus.The NEET Part Test - 2 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NEET Part Test - 2 below.
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NEET Part Test - 2 - Question 1

The time taken by a particle performing SHM on a straight line to pass from point A to B where it's velocities are same is 2 seconds. After another 2 seconds it returns to B. The time period of oscillation is (in seconds):

Detailed Solution for NEET Part Test - 2 - Question 1

From the given information it can be concluded that points A and B are equidistant from mean position.Hence from diagram it is clear that time period of oscillation is= 2 + 2 x 2 + 2 = 8 second.

NEET Part Test - 2 - Question 2

For a particle in S.H.M., if the amplitude of displacement is ‘a’ and the amplitude of velocity is ‘v’ the amplitude of acceleration is :

Detailed Solution for NEET Part Test - 2 - Question 2

Maximum velocity v = ω a
Maximum acceleeration f = ω2 a ⇒ 

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NEET Part Test - 2 - Question 3

A body performs SHM along the straight line segment  ABCDE with C as the mid point of segment AE (A and E are the extreme position for the SHM). Its kinetic energies at B and D are each one fourth of its maximum value. If length of segment AE is 2R, then the distance between B and D is : 

  

Detailed Solution for NEET Part Test - 2 - Question 3

When the particle crosses D, its speed is half the maximum speed.


or  or 

NEET Part Test - 2 - Question 4

A system is shown in the figure. The time period for small oscillations of the two blocks will be :

Detailed Solution for NEET Part Test - 2 - Question 4

Both the spring are in series
∴ 

Time period 
  
Method II

∴ 
mx1 = mx2 ⇒ x1 = x2
force equation for first block ;

Put x1 = x2 ⇒ 

∴  

NEET Part Test - 2 - Question 5

Two light strings, each of length l, are fixed at points A and B on a fixed horizontal rod xy. A small bob is tied by both strings and in equilibrium, the strings are making angle 45° with the rod. If the bob is slightly displaced normal to the plane of the strings and released then period of the resulting small oscillation will be :  

              

Detailed Solution for NEET Part Test - 2 - Question 5


Resulting torque on the bob = 
MI of bob about axis 
For small angle θ

NEET Part Test - 2 - Question 6

A metre stick swinging in vertical plane about a fixed horizontal axis passing through its one end undergoes small oscillation  of  frequency f0 as shown in figure. If the bottom half of the stick were cut off, then its new  frequency of  small oscillation would become:

Detailed Solution for NEET Part Test - 2 - Question 6


where, ℓ is distance between point of suspension and centre of mass of the body. Thus, for the stick of length L and mass m : 

when bottom half of the stick is cut off
 

NEET Part Test - 2 - Question 7

A 25 kg uniform solid sphere with a 20 cm radius is suspended by a vertical wire such that the point of suspension is vertically above the centre of the sphere. A torque of 0.10 N-m is required to rotate the sphere through an angle of 1.0 rad and then maintain the orientation. If the sphere is then released, its time period of the oscillation will be:

Detailed Solution for NEET Part Test - 2 - Question 7

τ = -kθ
0.1 = -k(1.0), where k is torsional constant of the wire.
k = 1/10
  = 4π second

NEET Part Test - 2 - Question 8

A rod of length l is in motion such that its ends A and B are moving along x-axis and y-axis respectively. It is given that  rad/s always. P is a fixed point on the rod as shown in figure. Let M be the projection of P on x-axis. For the time interval in which q changes from 0 to π/2 ,

choose the correct statement :

Detailed Solution for NEET Part Test - 2 - Question 8


 ∴ θ = 2t
Let BP = a ∴ x = OM = a sin θ = a sin (2t)
Hence M executes SHM with in the given time period and its acceleration is opposite to 'x' that means towards left 

NEET Part Test - 2 - Question 9

Which of the following is greatest in SHM ? (assuming potential energy = 0 at mean position)

Detailed Solution for NEET Part Test - 2 - Question 9

Average kinetic energy with respect to position
Average potential energy with respect to position  
Average kinetic energy with respect to time  
Average potential energy with respect to time

NEET Part Test - 2 - Question 10

m1 & m2 are connected with a light inextensible string with m1 lying on smooth table and m2 hanging as shown in figure. m1 is also connected to a light spring which is initially unstretched and the system is released from rest :

Detailed Solution for NEET Part Test - 2 - Question 10

After the system is released, m2 moves down.
The extention in the spring becomes : 
 which is the new equilibrium position of the system.
For small 'x' : restoring force on the system is F = kx 
⇒  (For (m1 + m2 + spring) systeem)
⇒  
⇒ Angular frequency  
F.B.D. of m1 and m2 just after the system is released : 


mmoves towards right till the total kinetic energy acquired does not converted to potential energy.Hence  (D) is also incorrect.Hence (B) is the answer

NEET Part Test - 2 - Question 11

The potential energy of a particle executing SHM changes from maximum to minimum in 5 sec. Then the time period of SHM is : 

Detailed Solution for NEET Part Test - 2 - Question 11

P.E. is maximum at extreme position and minimum at mean position. 
Time to go from extreme position to mean position is, t = T/4 ; where T is time period of SHM 
5 s = T/4 ⇒ T = 20 s.

NEET Part Test - 2 - Question 12

A body is executing simple harmonic motion. At a displacement x from mean position, its potential energy is E1 and at a displacement y from mean position, its potential energy is E2. The potential energy E at a displacement (x + y) from mean position is (the potential energy is zero at mean position) :

Detailed Solution for NEET Part Test - 2 - Question 12


Therefore 

NEET Part Test - 2 - Question 13

In the figure shown a block of mass m is attached at ends of two springs. The other ends of the spring are fixed. The mass m is released in the vertical plane when the spring are relaxed. The velocity of the block is maximum when:

Detailed Solution for NEET Part Test - 2 - Question 13

Speed of block is maximum at mean position. At mean position upper string is extended and lower spring is compressed.

NEET Part Test - 2 - Question 14

Figure shows the kinetic energy K of a simple pendulum versus its angle θ from the vertical. The pendulum bob has mass 0.2 kg. The length of the pendulum is equal to (g = 10 m/s2) :  

Detailed Solution for NEET Part Test - 2 - Question 14

NEET Part Test - 2 - Question 15

The equation of a wave is given by (all quantity expressed in S.I. units) Y = 5 sin10π (t – 0.01x) along the x-axis. The magnitude of phase difference between the points separated by a distance of 10 m along x- axis is     :

Detailed Solution for NEET Part Test - 2 - Question 15

The magnitude of phase difference between the points separated by distance 10 metres.
= k x 10 = [10π x 0.01] x 10 
= π 

NEET Part Test - 2 - Question 16

A certain transverse sinusoidal wave of wavelength 20 cm is moving in the positive x direction. The transverse velocity of the particle at x = 0 as a function of time is shown. The amplitude of the motion is:

Detailed Solution for NEET Part Test - 2 - Question 16



⇒ 

NEET Part Test - 2 - Question 17

Two vibrating strings of same material stretched under same tension and vibrating with same frequency in the same overtone have radii 2r and r. Then the ratio of their lengths is :

Detailed Solution for NEET Part Test - 2 - Question 17

 and  
v1 = v2

 

NEET Part Test - 2 - Question 18

A chord attached about an end to a vibrating fork divides it into 6 loops, when its tension is 36 N. The tension at which it will vibrate in 4 loops is:

Detailed Solution for NEET Part Test - 2 - Question 18

For waves along a string
⇒ 
Now, for 6 loops : 3λ1 = L ⇒ λ1 = L/3
& for 4 loops : 2λ2 = L ⇒ λ2 = L/2 
⇒  ⇒ 

NEET Part Test - 2 - Question 19

Sinusoidal waves 5.00 cm in amplitude are to be transmitted along a string having a linear mass density equal to 4.00 × 10–2 kg/m. If the source can deliver a maximum power of 90 W and the string is under a tension of 100 N, then the highest frequency at which the source can operate is  (take π2 = 10) :

Detailed Solution for NEET Part Test - 2 - Question 19


⇒ 
 ⇒ 
using data f = 30 Hz.

NEET Part Test - 2 - Question 20

What is the percentage change in the tension necessary in a sonometer of fixed length to produce a note one octave lower (half of original frequency) than before :`

Detailed Solution for NEET Part Test - 2 - Question 20

In Sonometer 
 (Wave length constant for fixed length)
 ∴  ⇒  
∴ %

NEET Part Test - 2 - Question 21

Figure shown is a graph, at a certain time t, of the displacement function S(x,t) of three sound waves 1,2 and 3 as marked on the curves that travel along x–axis through air. If P1,P2 and P3 represent their pressure amplitudes respectively, then correct relation between them is :    

Detailed Solution for NEET Part Test - 2 - Question 21

NEET Part Test - 2 - Question 22

Under similar conditions of temperature and pressure, In which of the following gases the velocity of sound will be largest : 

Detailed Solution for NEET Part Test - 2 - Question 22

The speed of sound in air is 
 of H2 is maximum, hence speed of sound in H2 shall be maximum.

NEET Part Test - 2 - Question 23

In a sound wave, to increase the intensity by a factor of 10, pressure amplitude must be changed by a factor of :

Detailed Solution for NEET Part Test - 2 - Question 23


 ⇒  
⇒ 

NEET Part Test - 2 - Question 24

The two pipes are submerged in sea water, arranged as shown in figure. Pipe A with length LA = 1.5 m and one open end, contains a small sound source that sets up the standing wave with the second lowest resonant frequency of that pipe. Sound from pipe A sets up resonance in pipe B, which has both ends open. The resonance is at the second lowest resonant frequency of pipe B. The length of  the pipe B is :

Detailed Solution for NEET Part Test - 2 - Question 24

For pipe A, second resonant frequency is third harmonic thus
For pipe B, second resonant frequency is second harmonic thus 

⇒  

NEET Part Test - 2 - Question 25

A source of sound of frequency 256 Hz is moving rapidly towards a wall with a velocity of 5 m/sec. If sound travels at a speed of 330 m/sec, then number of beats per second heard by an observer between the wall and the source is:

Detailed Solution for NEET Part Test - 2 - Question 25

For a stationary observer between wall and source, frequency from direct source 
frequency from reflected sound 
So no beats will be heard. 

NEET Part Test - 2 - Question 26

A stationary observer receives sonic oscillations from two tuning forks, one of which approaches and the other recedes with same speed. As this takes place the observer hears the beat frequency of 2 Hz. Find the speed of each tuning fork, if their oscillation frequency is 680 Hz and the velocity of sound in air is 340 m/s:

Detailed Solution for NEET Part Test - 2 - Question 26

 ⇒ 

NEET Part Test - 2 - Question 27

A source of frequency f is stationary and an observer starts moving towards it at t = 0 with constant small acceleration. Then the variation of observed frequency f ' registered by the observer with time is best represented as :

Detailed Solution for NEET Part Test - 2 - Question 27

After a time t, velocity of observer V0 = at
∴ 

Which is a straight line graph of positive slope.

NEET Part Test - 2 - Question 28

Two persons A and B each carrying a source of frequency 596 Hz and 600 Hz respectively are standing at rest a few metres apart. A starts moving towards B with a velocity of 2 m/s. If the speed of sound is 300 m/s. Which of the following statement is true?

Detailed Solution for NEET Part Test - 2 - Question 28

Beats heard per second by A is 8 and B is zero.

NEET Part Test - 2 - Question 29

In a horizontal spring–mass system, mass m is released after being displaced towards right by some distance at t = 0 on a frictionless surface. The phase angle of the motion in radian when it is first time passing through the equilibrium position is equal to :

Detailed Solution for NEET Part Test - 2 - Question 29

Using x = A sin (ωt + φ) and V = Aω cos(ωt + φ) for conditions at t = 0 → x = A and V = 0 then φ = π/2 
When it passes equilibrium position for the first time  t = T/4

NEET Part Test - 2 - Question 30

A 75 cm string fixed at both ends produces resonant frequencies 384 Hz and 288 Hz without there being any other resonant frequency between these two. Wave speed for the string is :

Detailed Solution for NEET Part Test - 2 - Question 30

Δv = 384 - 288 = 96
Thus 288 and 384 (96 x 3; 96 x 4) are third and fourth harmonics.
For fundamental mode: 
λ/2 = 0.75 λ = 1.5 m
η = 96
⇒ v = 96 x 1.5 = 144 m/s.

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