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CAT Exam  >  CAT Test  >  Level-wise Tests  >  Test Level 1: Averages - 2 - CAT MCQ

Test Level 1: Averages - 2 Solved MCQs CAT


MCQ Practice Test & Solutions: Test Level 1: Averages - 2 (20 Questions)

You can prepare effectively for CAT Level-wise Tests for CAT with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test Level 1: Averages - 2". These 20 questions have been designed by the experts with the latest curriculum of CAT 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 40 minutes
  • - Number of Questions: 20

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Test Level 1: Averages - 2 - Question 1
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The average of the first ten prime numbers, which are odd, is

Detailed Solution: Question 1

Required average = (3 + 5 + 7 + 11 + 13 + 17 + 19
+ 23 + 29 + 31)/10 = 158/10 = 15.8.

Test Level 1: Averages - 2 - Question 2
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The average weight of 3 boys A, B and C is 74 kg. Another boy D joins the group and the average now becomes 70 kg. If another boy E, whose weight is 3 kg more than that of D, replaces A then the average weight of B, C, D and E becomes 75 kg. The weight of A is

Detailed Solution: Question 2

D’s weight = 4 x 70 – 3 x 74 = 280 – 222 = 58.
E’s weight = 58 + 3 = 61.
Now, we know that A + B + C + D = 4 x 70 = 280
and B + C + D + E = 75 x 4 = 300. Hence, A’s
weight is 20 kg less than E ’s weight. A = 61 - 20
= 41 kg.

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Test Level 1: Averages - 2 - Question 3
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The average of the first ten whole numbers is

Detailed Solution: Question 3

Required average = (0 + 1 + 2 + … + 9)/10 = 45/10
= 4.5

Test Level 1: Averages - 2 - Question 4
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The average of the first ten odd numbers is

Detailed Solution: Question 4

The sum of the first n odd numbers = n2. In this case n = 10 → Sum = 102 = 100.
Required average = 100/10 = 10.

Test Level 1: Averages - 2 - Question 5
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The average of the first ten composite numbers is

Detailed Solution: Question 5

Required average = (4 + 6 + 8 + 9 + 10 + 12 + 14 + 15 + 16 + 18)/10 = 112/10 = 11.2.

Test Level 1: Averages - 2 - Question 6
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The average age of 13 boys and the principal is 10 years. When the principal’s age is excluded, the average age decreases by 2 year. What is the age of the principal?

Detailed Solution: Question 6

P = 14 x 10 – 13 x 8 = 140 –104 = 36

Test Level 1: Averages - 2 - Question 7
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The mean temperature of Monday to Wednesday was 35 °C and of Tuesday to Thursday was 30 °C. If the temperature on Thursday was ½ that of Monday, the temperature on Thursday was

Detailed Solution: Question 7

Monday + Tuesday + Wednesday = 3 x 35 = 105;
Tuesday + Wednesday + Thursday = 3 x 30 = 90.
Thus, Monday – Thursday = 15 and
Thursday = Monday/2 → Monday = 30 and Thursday = 15

Test Level 1: Averages - 2 - Question 8
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Ganguly has a certain average for 4 innings. In the 5th inning, he scores 40 runs thereby increasing his average by 4 runs. His new average is

Detailed Solution: Question 8

4x + 40 = 5(x + 4) → x = 20 (average after 4 innings).

Hence, new average = 20 + 4 = 24.

Test Level 1: Averages - 2 - Question 9
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There are three fractions A, B and C. If A = 1/5 and B = 1/8 and the average of A, B and C is 1/10. What is the value of C?

Detailed Solution: Question 9

1/5 + 1/8 + C = 3 x 1/10 → C = –1/40.

Test Level 1: Averages - 2 - Question 10
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The average monthly expenditure of a family was 2250 for the first 3 months, ₹ 2150 for the next three months and ₹ 5750 for the next three months. Find the average income of the family for the 9 months, if they save ₹ 500 per month.

Detailed Solution: Question 10

Average income over 9 months = [3 x (2250 + 500) + 3 x (2150 + 500) + 3 x (5750+500)]/9 = 3883.33

Test Level 1: Averages - 2 - Question 11
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The average age of 5 persons in a group is increased by 10 years when two men aged 30 years and 40 years are substituted by two women. Find the average age (in years) of the two women.

Detailed Solution: Question 11

If the average age of 5 persons has gone up by 10 years it means the total age has gone up by 50 years.

Thus the total age of the two women would be: 30 + 40 + 50 = 120. Hence, their average age = 60 years.

Test Level 1: Averages - 2 - Question 12
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The speed of the train in going from Kanpur to Lucknow is 60 km/hr while when coming back from Lucknow to Kanpur, its speed is 40 km/hr. Find the average speed (in km/hr) during the whole journey.

Detailed Solution: Question 12

Test Level 1: Averages - 2 - Question 13
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Five years ago, the average age of A, B and C was 25 years and that of B and C 10 years ago was 20 years. A’s present age is

Detailed Solution: Question 13

Total present age of A, B and C = 25 x 3 + 15 = 75 + 15 = 90.

Total present age of B and C = 20 x 2 + 20 = 60.

A ’s age = 90 – 60 = 30.

Test Level 1: Averages - 2 - Question 14
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The average of the first six multiples of 5 is

Detailed Solution: Question 14

(5+10+15+20+25+30)/6 = 105/6 = 17.5

Test Level 1: Averages - 2 - Question 15
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The marks obtained by Alan in Mathematics, English and Biology are respectively 90 out of 100, 70 out of 150 and 150 out of 200. Find his average score in percent.

Detailed Solution: Question 15

His total score is 90 + 70 + 150 = 310 out of 450.

This works out to a percentage score of = 68.88%

Test Level 1: Averages - 2 - Question 16
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The average age of a family of 5 members is 20 years. If the age of the youngest member be 5 years, what was the average age of the family at the birth of the youngest member?

Detailed Solution: Question 16

Total age (at present) = 5 ¥ 20 = 100 years. Total age of the family excluding the youngest member (for the remaining 5 people) = 100 –5 = 95. Average age
of the other 4 people in the family = 95/4 years.

5 years ago their average age = 95/4 – 5 = 75/4 = 18.75 years.

Test Level 1: Averages - 2 - Question 17
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The average temperature for Wednesday, Thursday and Friday was 20°C. The average for Thursday, Friday and Saturday was 21 °C. If the temperature on Saturday was 22°C, what was the temperature on Wednesday?

Detailed Solution: Question 17

W + T + F = 60; T + F + S = 63 → S – W = 3.

Hence temperature on Wednesday = 22 – 3 = 19.

Test Level 1: Averages - 2 - Question 18
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The average weight of a class of 19 students is 20 kg. If the weight of the teacher be included, the average rises by 1 kg. What is the weight of the teacher?

Detailed Solution: Question 18

Teacher’s weight = 21 x 20 – 20 x 19 = 420– 380 = 40.

Test Level 1: Averages - 2 - Question 19
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The average weight of 29 men in a ship is increased by 5 kg when one of the men, who weighs 120 kg, is replaced by a new man. Find the weight of the new man (In kg)

Detailed Solution: Question 19

The weight of the new man would be 29 x 5 kgs more than the weight of the man he replaces. New man’s weight = 120 + 29 x 5 = 265 kgs.

Test Level 1: Averages - 2 - Question 20
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Find the average of the first 100 natural numbers.

Detailed Solution: Question 20

The average would be given by the average of the first and last numbers (since the series 1, 2, 3, 4…100 is an Arithmetic Progression).

Hence, the average = (1 + 100)/2 = 50.50

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This test contains 20 MCQs on Test Level 1: Averages - 2 with detailed solutions for each question. It is part of the Level-wise Tests for CAT course on EduRev, designed to align with the current CAT syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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