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CAT Exam  >  CAT Test  >  Level-wise Tests  >  Test Level 2: Speed, Time and Distance - 1 - CAT MCQ

Test Level 2: Speed, Time and Distance - 1 Solved MCQs CAT


MCQ Practice Test & Solutions: Test Level 2: Speed, Time and Distance - 1 (10 Questions)

You can prepare effectively for CAT Level-wise Tests for CAT with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test Level 2: Speed, Time and Distance - 1". These 10 questions have been designed by the experts with the latest curriculum of CAT 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 10

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Test Level 2: Speed, Time and Distance - 1 - Question 1
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A monkey starts climbing a 15 feet tree. Each hour, he climbs 3 feet and rests for 30 minutes. During his rest, he slips back 2 feet. How many hours will the monkey take to reach the top?

Detailed Solution: Question 1

The monkey climbs 3 feet in 1 hour and drops by 2 feet in half an hour.
So, he climbs net 1 foot in (3/2) hours.
This way, he climbs 12 feet in 18 hours.
In the next hour, he will climb 3 more feet i.e. he will climb 15 feet in 19 hours and will reach the top of the tree.

Test Level 2: Speed, Time and Distance - 1 - Question 2
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A man covered a total distance of 1000 km in 16 hours, partly in a taxi at 36 km/hr and partly in a bus at 80 km/hr. The distance covered by the bus is

Detailed Solution: Question 2

Total distance = 1000 km
Total time = 16 hours
Let the time for bus travel be x hours.
Then, time for taxi travel be (16 – x) hours.
Then,
1000 = x × 80 + (16 – x)36
1000 = 80x + 576 – 36x
424 = 44x
x = 424/44 = 106/11 hours
Distance covered by bus = = 770.9 km

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Test Level 2: Speed, Time and Distance - 1 - Question 3
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x, y and z are the three contestants in a kilometre race. If x can give y a start of 50 metres and x can also give z a start of 69 metres, then how many metres start can y give to z, if the race is supposed to end in a dead heat?

Detailed Solution: Question 3

Given, race is to end in a dead heat i.e. they are all supposed to cross the finish line at the same time.
Position of x from finish line = 1000
Position of y from finish line = 1000 - 50 = 950
Position of z from finish line = 1000 - 69 = 931
So, y can give a 19 m start to z for the given scenario to be true.

Test Level 2: Speed, Time and Distance - 1 - Question 4
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A train passes a 60 metres long platform in 20 seconds and passes a man standing on the platform in 16 seconds. The speed of the train is

Detailed Solution: Question 4

Let L = Length of train
Speed = border=0 ........ (1)
Speed = L/16 ........ (2)
From (1) and (2),
L/16 = border=0
⇒ L = 240 m
Speed = L/16 =  240/16 = 15 m/s = border=0 = 54 kmph

Test Level 2: Speed, Time and Distance - 1 - Question 5
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In a flat race of L metres, A beats B by x1 metres and C by x3 metres. C will beat B, if 

Detailed Solution: Question 5

Distance covered by A is L metres to finish the race.
Then, distance covered by B = L - x1 metres
Distance covered by C = L - x3 metres
C beats B, if and only if the distance covered by C at that moment is greater than B.
So, (L - x3) > (L - x1)
Solving, x1 > x3.

Test Level 2: Speed, Time and Distance - 1 - Question 6
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Two trains starting from the same station and travelling in opposite directions are 227.5 km apart in 3 hours 15 min. Had they been travelling in the same direction, they would have been 32.5 km apart in the same time. Find their speeds (in kmph).

Detailed Solution: Question 6

When the trains are travelling in opposite direction, the sum of their speeds (relative speed) = (227.5/3.25) = 70 kmph
If they had been travelling in same directions, the difference of their speeds (relative speed) = (32.5/3.25) = 10 kmph
Hence, the speed of the faster train = (70 + 10)/2 = 40 kmph and the speed of the slower train = (70 - 10)/2 = 30 kmph

Test Level 2: Speed, Time and Distance - 1 - Question 7
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Javed wanted to reach the ground floor of the building. He went down at the rate of 1 stair in 1 minute. 16 minutes after he started, Salma started from the same point, from where Javed stared, to reach the ground floor of the building. She went down at the rate of 2 stairs in 1 minute. In how many minutes did Salma overtake Javed?

Detailed Solution: Question 7

Speed of Javed = 1 stair/min
After sixteen minutes, relative distance between Javed and Salma = 16 stairs
Speed of Salma = 2 stairs/min
Relative speed of Salma w.r.t. Javed = 2 - 1 = 1 stair/min
Time taken by Salma to cross Javed = 16/1 = 16 minutes

Test Level 2: Speed, Time and Distance - 1 - Question 8
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A man standing inside a tunnel notices that Train A is running inside the tunnel with a speed of 45 kmph. Another Train B, which is half the length of Train A and coming from opposite direction, is running at a speed of 81 kmph. Train A passes Train B in 4 seconds. Which of the following is the closest approximation of the length of the tunnel, if Train A passes completely through it in 4 minutes?

Detailed Solution: Question 8

Let the length of Train A be 2L and the length of Train B be L.
Speed of Train A = 45 kmph = 12.5 m/s and speed of Train B = 22.5 m/s
According to the given condition,
4 = $\frac{(L + 2L)}{35}$
L = $\frac{140}{3}$ m
Let length of tunnel be t.
So, 4 × 60 = $\frac{(t + 2L)}{12.5}$
Putting the value of L in the above equation and solving,
t = 2906.67 m = 2.9 km = 3 km (Approx.)

Test Level 2: Speed, Time and Distance - 1 - Question 9
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A train of length 500 m crosses a platform in 50 sec and another train of the same length, moving in the opposite direction with double the speed of the first train, crosses a pole in 20 sec. What is the length of the platform?

Detailed Solution: Question 9

Assume length of platform = L metres
Speed of first train = V m/sec
According to the given condition,
50V = L + 500
Speed of second train = 500/20 = 25 m/sec
Therefore, speed of first train = 12.5 m/sec
Hence, length of platform = 50 × 12.5 - 500 = 625 - 500 = 125 m

Test Level 2: Speed, Time and Distance - 1 - Question 10
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Varun went for a long ride last Sunday. Every hour, he maintained a constant speed of 60 kmph. But after every 1 hour ride, he took rest for 10 minutes. If he starts from a place A at 8 a.m. and reaches a place B at 2 p.m. on the same day, what is the distance between A and B?

Detailed Solution: Question 10

 Total time he travelled = 5 hours 10 minutes (∵ Varun rested for 50 minutes.)
So, d = 60 × 5border=0 = 60 × 31/6 = 310 km

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