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Test Level 2: Table - CAT MCQ


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20 Questions MCQ Test - Test Level 2: Table

Test Level 2: Table for CAT 2024 is part of CAT preparation. The Test Level 2: Table questions and answers have been prepared according to the CAT exam syllabus.The Test Level 2: Table MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test Level 2: Table below.
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Test Level 2: Table - Question 1
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Directions: Study the following information and answer the question that follows.
The table below represents the number of software projects on different domains that were done in different companies in 2006.

There were no other projects done by these companies, except those given above.

How many companies did more projects than Flextronics?

Detailed Solution for Test Level 2: Table - Question 1

Total number of project done by Flextronics = 5 + 12 + 13 + 4 + 1 = 35
Total number of project done by Bamsi = 14 + 12 + 8 + 10 + 4 = 48
Total number of project done by Wipro = 12 + 9 + 17 + 10 + 8 = 56
Total number of project done by Satyam = 3 + 14 + 9 + 7 + 6 = 39
Total number of project done by Infosys = 20 + 18 + 9 + 13 + 3 = 63
Total number of project done by C.T.S. = 4 + 5 + 2 + 12 + 13 = 36
Total number of project done by Perot = 11 + 4 + 7 + 9 + 18 = 49
Total number of project done by T.C.S. = 13 + 4 + 1 + 17 + 11 = 46
Total number of project done by Dell = 7 + 5 + 3 + 5 + 12 = 32
Total number of project done by Birlasoft = 11 + 9 + 0 + 4 + 3 = 27
Hence, total number of companies which did more projects than Flextronics = 7

Test Level 2: Table - Question 2
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Directions: Study the following information and answer the question that follows.
The table below represents the number of software projects on different domains that were done in different companies in 2006.

There were no other projects done by these companies, except those given above.

If each company got 10% more total projects in the next year, i.e. 2007, as compared to 2006, then how many companies would get more than 50 projects in 2007?

Detailed Solution for Test Level 2: Table - Question 2

Bamsi got 48 projects in 2006.
So, in 2007 = 48 + 10% of 48 = 52.8
Wipro got 56 projects in 2006.
So, in 2007 = 56 + 10% of 56 = 61.6
Infosys got 63 projects in 2006.
So, in 2007 = 63 + 10% of 63= 69.3
Perot got 49 projects in 2006.
So, in 2007 = 49 + 10% of 49 = 53.9
T.C.S. got 46 projects in 2006.
So, in 2007 = 46 + 10% of 46 = 50.6
So, total 5 companies would get more than 50 projects in 2007.

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Test Level 2: Table - Question 3
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Directions: Study the following information and answer the question that follows.
The table below represents the number of software projects on different domains that were done in different companies in 2006.

There were no other projects done by these companies, except those given above.

In 2005, the number of projects of each company was 20% less than that in 2006, how many companies got at the most 30 projects in 2005?

Detailed Solution for Test Level 2: Table - Question 3

Flextronics got 35 projects in 2006.
So, in 2006 = 35 - 20% of 35 = 28
CTS got 36 projects in 2006.
So, in 2005 = 36 - 20% of 36 = 28.8
DELL got 32 projects in 2006.
So, in 2005 = 32 - 20% of 32 = 25.6
BIRLASOFT got 27 projects in 2006.
So, in 2005 = 27 - 20% of 27 = 21.6
So, total 4 companies got at the most 30 projects in 2005.

Test Level 2: Table - Question 4
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Directions: Study the following information and answer the question that follows.
The table below represents the number of software projects on different domains that were done in different companies in 2006.

There were no other projects done by these companies, except those given above.

How many companies did less Java projects than Birlasoft in 2006?
Detailed Solution for Test Level 2: Table - Question 4

Four companies did less Java projects than Birlasoft.

Test Level 2: Table - Question 5
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Directions: Refer to the table below and answer the following question.
The table gives the terms of subscriptions for a magazine.

Conditions:
1. If you subscribe for 1–3 years, postage = Rs. 50 per year of subscription.
2. For a subscription of 3 years, you receive a gift worth Rs. 300.
3. For a subscription of 4 years, you receive a special gift worth Rs. 500.
4. For a subscription of 5 years, you get additional 12 issues for the 6th year, as a special gift.
5. Effective cost = Special Offer Price – Cost of gifts + Cost of postage

The % decrease in Special Offer Price per issue from one term to the next is maximum for
Detailed Solution for Test Level 2: Table - Question 5


So, % decrease in Special Offer Price per issue from one term to the next is maximum for 5-year term.

Test Level 2: Table - Question 6
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Directions: Refer to the table below and answer the following question.
The table gives the terms of subscriptions for a magazine.

Conditions:
1. If you subscribe for 1–3 years, postage = Rs. 50 per year of subscription.
2. For a subscription of 3 years, you receive a gift worth Rs. 300.
3. For a subscription of 4 years, you receive a special gift worth Rs. 500.
4. For a subscription of 5 years, you get additional 12 issues for the 6th year, as a special gift.
5. Effective cost = Special Offer Price – Cost of gifts + Cost of postage

What is the approximate difference in the effective cost per issue between a subscription for 2 years and subscription for 5 years?
Detailed Solution for Test Level 2: Table - Question 6


Effective cost per issue for 2-year subscription = 79.17
Effective cost per issue for 5-year subscription = 50
Difference = 79.17 - 50 = 29.17 ≈ 30 (approx.)

Test Level 2: Table - Question 7
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Directions: Refer to the table below and answer the following question.
The table gives the terms of subscriptions for a magazine.

Conditions:
1. If you subscribe for 1–3 years, postage = Rs. 50 per year of subscription.
2. For a subscription of 3 years, you receive a gift worth Rs. 300.
3. For a subscription of 4 years, you receive a special gift worth Rs. 500.
4. For a subscription of 5 years, you get additional 12 issues for the 6th year, as a special gift.
5. Effective cost = Special Offer Price – Cost of gifts + Cost of postage

The Special Offer Price as a percentage of News Stand Price is minimum for which subscription?
Detailed Solution for Test Level 2: Table - Question 7

Special Offer Price as a percentage of News Stand Price for 2-year term = (1800/2400) x 100 = 75%
Special Offer Price as a percentage of News Stand Price for 3-year term = (2520/3600) x 100 = 70%
Special Offer Price as a percentage of News Stand Price for 4-year term = (2880/4800) x 100 = 60%
Special Offer Price as a percentage of News Stand Price for 5-year term = (3000/6000) x 100  = 50%
So, the Special Offer Price as a percentage of News Stand Price is minimum for the 5-year term

Test Level 2: Table - Question 8
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Directions: Refer to the table below and answer the following question.
The table gives the terms of subscriptions for a magazine.

Conditions:
1. If you subscribe for 1–3 years, postage = Rs. 50 per year of subscription.
2. For a subscription of 3 years, you receive a gift worth Rs. 300.
3. For a subscription of 4 years, you receive a special gift worth Rs. 500.
4. For a subscription of 5 years, you get additional 12 issues for the 6th year, as a special gift.
5. Effective cost = Special Offer Price – Cost of gifts + Cost of postage

What is the ratio of Effective Price to News Stand Price per issue, for a subscription of 4 years?
Detailed Solution for Test Level 2: Table - Question 8


Effective Price for a subscription of 4 years = 49.58
News Stand Price for a subscription of 4 years = 100
Ratio = 49.58 : 100 = 2479:5000

Test Level 2: Table - Question 9
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Directions: Answer the question based on the data provided in the table given below:

Asset Utilisation Factor (AUF) = Sales value/Assets
Worker productivity = Production of units/Number of workers
Assume that whatever was produced in a given year was sold in the same year.
All sales were of produced units only.

In which year was worker productivity the highest?
Detailed Solution for Test Level 2: Table - Question 9

Worker productivity = (Production of units)/(Number of workers)
In 1996, worker productivity = $\frac{12,00,000}{80}$  = 15,000
In 1997, worker productivity = $\frac{14,00,000}{85}$ ~ 16,471
In 1998, worker productivity = $\frac{13,50,000}{90}$ = 15,000
In 1999, worker productivity = $\frac{15,00,000}{102}$ ~ 14,706
In 2000, worker productivity = $\frac{17,50,000}{120}$ ~ 14,583
From above calculations, it is clear that in 1997, worker productivity was the highest.

Test Level 2: Table - Question 10
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Directions: Answer the question based on the data provided in the table given below:

Asset Utilisation Factor (AUF) = Sales value/Assets
Worker productivity = Production of units/Number of workers
Assume that whatever was produced in a given year was sold in the same year.
All sales were of produced units only.

What should be the selling price per unit in 2001 for 15 lakh units produced in 2001, such that the average selling price/unit of the sold units from 1996 to 2001 was 13.55% more than their average selling price/unit from 1996 to 2000?
Detailed Solution for Test Level 2: Table - Question 10

Total sales = 16 + 18 + 21 + 22 + 25 = Rs. 102 crore
Total units produced = 12 + 14 + 13.5 + 15 + 17.5 = 72 lakh
Average selling price per unit from 1999 to 2000 =  = Rs. 141.66 per unit
Let Rs. x crore be the selling price of sold units in 2001.
According to the given condition,  = 
102 + x = 139.94
x = Rs. 37.94 crore
Selling price per unit in 2001 =  = Rs. 253/unit (approx.)

Test Level 2: Table - Question 11
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Directions: Answer the question based on the data provided in the table given below:

Asset Utilisation Factor (AUF) = Sales value/Assets
Worker productivity = Production of units/Number of workers
Assume that whatever was produced in a given year was sold in the same year.
All sales were of produced units only.

Worker turnover is defined as the average sales (value) per worker in a given year. The worker turnover from 1996 to 1998 was what percent of the that from 1997 to 1999?
Detailed Solution for Test Level 2: Table - Question 11

Worker turnover from 1996 to 1998 =  crore per worker
Worker turnover from 1997 to 1999 =  crore per worker
Required percentage =  97.96%

Test Level 2: Table - Question 12
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Directions: Study the following information carefully and answer the given question.
Below are given percentages of marks in different subjects for different persons.

What are the overall marks of A in all of the examinations?
Detailed Solution for Test Level 2: Table - Question 12

Percentage of marks = [marks obtained/total marks] x 100
Marks obtained = percentage of marks x total marks/100
Marks obtained by A in Power Electronics = 67 x 100/100 = 67
Marks obtained by A in Machines = 84 x 125/100 = 105
Marks obtained by A in Network Theory = 80 x 150/100 = 120
Marks obtained by A in IT = 54 x 75/100 = 40.5
Marks obtained by A in mechanics = 90 x 50/100 = 45
So, overall marks of A = 67 + 105 + 120 + 40.5 + 45 = 377.5

Test Level 2: Table - Question 13
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Directions: Study the following information and answer the question.

Success Rate  = (Number of seats won/ Number of seats contested) x 100

What is the difference between the number of votes polled for AAP and RSS if 50 crore people were eligible to vote and 27% of them cast their votes?
Detailed Solution for Test Level 2: Table - Question 13

Number of people eligible to vote = 50 crore
Number of people who cast their votes = 50 x 0.27 = 13.5 crore
∴ displaystyle \therefore$ Difference between the number of votes polled for RSS and APP = (34 - 9)% of 13.5
= 25% of 13.5 crore
= 3.375 crore 
= 3.38 crore (approx.)

Test Level 2: Table - Question 14
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Directions: Study the following information and answer the question.

Success Rate  = (Number of seats won/ Number of seats contested) x 100

RSS and AAP had fought against each other for 135 seats and no third party could win any of them. If they had entered into a pre-poll alliance, what would have been the combined success rate of RSS and AAP?
Detailed Solution for Test Level 2: Table - Question 14

If RSS and AAP had entered into an alliance before polls,
Total number of seats contested = 380 + 185 - 135 = 430
Total number of seats won = 230 + 7 = 237
∴ Success rate = (237/430) x 100 = 55.12%.

Test Level 2: Table - Question 15
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Directions: Study the following information and answer the question.

Success Rate  = (Number of seats won/ Number of seats contested) x 100

If a total of 45.6 crore people were eligible to vote and 63% of them cast their vote in the year 2018, then in the next general elections which are held in 2022, the number of eligible voters increases by 12%, and 65% of voters cast their votes. If the vote share of Congress increases to 18.5%, what is the percentage increase in the number of votes polled for Congress?
Detailed Solution for Test Level 2: Table - Question 15

In the next general elections in 2022, number of people who cast their vote = 45.6 x 1.12 x 0.65 = 33.20 crore
Number of votes polled for Congress = 33.20 x 18.5% = 6.14 crore
Number of votes polled for Congress in 2018 = 16% of 45.6 x 0.63 = 4.60 crore
∴ % increase in the number of votes polled for Congress = $\displaystyle \frac{6.14-4.6}{4.6}$ x 100 = 33.48% = 34% (approx.)

Test Level 2: Table - Question 16
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Directions: Study the following information and answer the question.

Success Rate  = (Number of seats won/ Number of seats contested) x 100

If a total of 45.6 crore people were eligible to vote and 63% of them cast their vote, what was the difference between the number of votes polled for BJP and Congress?
Detailed Solution for Test Level 2: Table - Question 16

Number of people eligible to vote = 45.6 crore
Number of people who cast their vote = 45.6 x 0.63 = 28.73 crore
∴ Difference between the number of votes polled for BJP and Congress = (28 - 16)% of 28.73 crore
= 12% of 28.73 = 3.45 crore

Test Level 2: Table - Question 17
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Directions: Study the following information carefully and answer the given question.
Below are given percentages of marks in different subjects for different persons.

What are the average marks obtained by all the students in Fluid Mechanics?
Detailed Solution for Test Level 2: Table - Question 17

Percentage of marks = [Marks obtained/total marks] x 100 .
Marks obtained = (Percentage of marks) x total marks/100
Marks obtained by A in Fluid Mechanics = (90 x 50)/100 = 45
Marks obtained by B in Fluid Mechanics = (84 x50)/100 = 42
Marks obtained by C in Fluid Mechanics = (76 x 50)/100 = 38
Marks obtained by D in Fluid Mechanics = (86 x 50)/100 = 43
Marks obtained by E in Fluid Mechanics = (72 x 50)/100 = 36
Average marks = Total marks/5 = [45 + 42 + 38 + 43 + 36 ]/5 = 40.8

Test Level 2: Table - Question 18
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Directions: Study the following information carefully and answer the given question.
Below are given percentages of marks in different subjects for different persons.

In order to pass in subject Machines, a minimum of 85 marks has to be obtained. How many students passed in this subject?
Detailed Solution for Test Level 2: Table - Question 18

Percentage of marks = [marks obtained/total marks] x 100
Marks obtained = percentage of marks x total marks/100
Marks obtained by A in machines = 84 x 125/100 = 105.
Marks obtained by B in machines = 72 x 5/4 = 90
Marks obtained by C in machines = 90 x 5/4 =112.5
Marks obtained by D in machines = 66 x 5/4 = 82.5
Marks obtained by E in machines = 76 x 5/4 = 95
A student should get 85 marks to pass in the subject.
Except D, all are pass in subject Machines.
So, 4 members passed in the subject Machines.

Test Level 2: Table - Question 19
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Directions: Study the following table carefully and answer the given question.
The number of participants who participated and got selected in a TV reality show screening, conducted in 5 different cities of Pakistan over the years is given below in the table:
Participants Participated (PAR) and Selected (SEL) Each Year

If the total number of participants from all the cities in 2013 increased by approximately 25% from that in 2012, and the total number of selected participants decreased by approximately 5% from that in 2012, then what would be the approximate percentage change in the number of participants not selected in 2013 with respect to 2012?
Detailed Solution for Test Level 2: Table - Question 19

From the above table, we have
Total number of participants in 2012 = 78 + 80 + 76 + 66 + 68 = 368
Therefore, total number of participants in 2013 = 368 x (125/100) = 460
Also, we have
Total number of selected participants in 2012 = 54 + 76 + 68 + 62 + 56 = 316
Therefore, total number of selected participants in 2013 = 316 x (95/100) = 300.2 ≈ 300
Therefore, total number of participants not selected in 2012 = 368 - 316 = 52
Total number of participants not selected in 2013 = 460 - 300 = 160
Therefore, required percentage = x 100 = x 100 = 207.69 ≈ 208%

Test Level 2: Table - Question 20
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Directions: Study the following table carefully and answer the given question.
The number of participants who participated and got selected in a TV reality show screening, conducted in 5 different cities of Pakistan over the years is given below in the table:
Participants Participated (PAR) and Selected (SEL) Each Year

The percentage of participants selected from Multan was highest in which of the given years?
Detailed Solution for Test Level 2: Table - Question 20

From the above table, calculate the percentage of selected participants from Multan.
In the year 2006 = (54/64)× 100 = 84.38%
In the year 2007 = (51/56) × 100 = 91.07%
In the year 2008 = (63/74) × 100 = 85.14%
In the year 2009 = (66/69) × 100 = 95.65%
In the year 2010 = (78/88) × 100 = 88.64%
In the year 2011 = (40/52) × 100 = 76.92%
In the year 2012 = (62/66) × 100 = 93.94%
Thus, the percentage of participants selected from Multan was highest in the year 2009. Hence, it is the required result.

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