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Measurement of Mutual Inductance - GATE EE Electrical and Electronic Measurements


MCQ Practice Test & Solutions: Test: Measurement of Mutual Inductance (10 Questions)

You can prepare effectively for Electrical Engineering (EE) Electrical and Electronic Measurements with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Measurement of Mutual Inductance". These 10 questions have been designed by the experts with the latest curriculum of Electrical Engineering (EE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 30 minutes
  • - Number of Questions: 10

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Test: Measurement of Mutual Inductance - Question 1

If the current in one coil becomes steady, the current in neighbouring coil is?

Detailed Solution: Question 1

A current is induced when there is changing magnetic flux. Hence the induced current in neighbouring coil is zero when the current is steady.

Test: Measurement of Mutual Inductance - Question 2

What is the SI unit of mutual inductance?

Detailed Solution: Question 2

Mutual inductance is the inductance between the two neighbouring coils. Since it is a type of inductance, its unit is that of inductance, that is, henry.

Test: Measurement of Mutual Inductance - Question 3

If the flux linkage in coil 1 is 3Wb and it has 500 turns and the current in coil 2 is 2A, calculate the mutual inductance.

Detailed Solution: Question 3

We know that mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil.
M = 3*500/2 = 750H.

Test: Measurement of Mutual Inductance - Question 4

The flux linkage in coil 1 is x and it has 500 turns and the current in coil 2 is 2A, calculate the value of x if the mutual inductance is 750H.

Detailed Solution: Question 4

We know that mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil.
φ = 750*2/500 = 3Wb.

Test: Measurement of Mutual Inductance - Question 5

Practical application of mutual inductance is ____________

Detailed Solution: Question 5

A transformer is a device made of two or more inductors, one of which is powered by AC, inducing an AC voltage across the second inductor.

Test: Measurement of Mutual Inductance - Question 6

The phenomenon due to which there is an induced current in one coil due to the current in a neighbouring coil is?

Detailed Solution: Question 6

When there is a current in a coil, due to the magnetic field caused by the current there is current induced in the neighbouring coil as well. This is known as mutual inductance.

Test: Measurement of Mutual Inductance - Question 7

If the current in one coil is steady, what happens to the mutual inductance?

Detailed Solution: Question 7

A current is induced when there is changing magnetic flux. The induced current in neighbouring coil is zero when the current is steady. So, mutual inductance is zero.

Test: Measurement of Mutual Inductance - Question 8

Which, among the following, is the correct expression for mutual inductance?

Detailed Solution: Question 8

Mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil. Hence M = N2φ2/I1 is the correct expression.

Test: Measurement of Mutual Inductance - Question 9

The flux linkage in coil 1 is 3Wb and it has x turns and the current in coil 2 is 2A, calculate the value of x if the mutual inductance is 750H.

Detailed Solution: Question 9

We know that mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil.
N = 750*2/3 = 500 turns.

Test: Measurement of Mutual Inductance - Question 10

The flux linkage in coil 1 is 3 Wb and it has 500 turns and the current in coil 2 is xA, calculate the value of x if the mutual inductance is 750H.

Detailed Solution: Question 10

We know that mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil.
I=3*500/750 = 2A.

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