Quantitative Aptitude - Test 12 - SSC CGL MCQ

# Quantitative Aptitude - Test 12 - SSC CGL MCQ

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## 25 Questions MCQ Test - Quantitative Aptitude - Test 12

Quantitative Aptitude - Test 12 for SSC CGL 2024 is part of SSC CGL preparation. The Quantitative Aptitude - Test 12 questions and answers have been prepared according to the SSC CGL exam syllabus.The Quantitative Aptitude - Test 12 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Quantitative Aptitude - Test 12 below.
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Quantitative Aptitude - Test 12 - Question 1

### The pie-chart given below shows expenditure incurred by a family on various items and their savings. Study the chart and answer the questions based on the pie-chart The ratio of expenditure on food to savings is:

Detailed Solution for Quantitative Aptitude - Test 12 - Question 1

Degree of expenditure on food = 120

Degree of expenditure on savings = 60

=> Required ratio = 120/6 = 2 : 1

Quantitative Aptitude - Test 12 - Question 2

### The graph shows the result of 10th class students of a school for 4 years. Study the graph and answer the questions: The number of students appeared for the 10th class exam in the year 2002 is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 2

In 2002, no. of students who passed in :

1st class = 120

2nd class = 60

3rd class = 15

=> Total no. of students appeared for class 10th exam in 2002 = 120 + 60 + 15 = 195

Quantitative Aptitude - Test 12 - Question 3

### The graph shows Income and Expenditure(Rs. in lakhs) of a company.Study the graph and answer the questions. The expenditure from 2002 to 2003 increased by

Detailed Solution for Quantitative Aptitude - Test 12 - Question 3

Expenditure in 2002 = 30

Expenditure in 2003 = 40

So, the answer is option A.

Quantitative Aptitude - Test 12 - Question 4

In the following questions, the following Bar Diagram shows the percentage of 7 coloured balls sold in 5 shops A, B, C, D and E. All the five shops sold an equal number of balls. Study the graph and answer all the questions.

In shop A, the ratio of percentage of violet balls and yellow balls is:

Detailed Solution for Quantitative Aptitude - Test 12 - Question 4

In shop A, percentage of violet balls sold as a percentage of total number of balls = 35%

Percentage of yellow balls sold as a percentage of total number of balls = 20%

Ratio = 35 : 20 = 7 : 4

Option B is the right answer.

Quantitative Aptitude - Test 12 - Question 5

Directions: The following graph shows the production of cotton bales of 100 kg each in lakhs by different states A, B, C, D and E over the years. Study the graph and answer the following Questions.

In which State(s) is there a steady increase in the production of cotton during the given period?

Detailed Solution for Quantitative Aptitude - Test 12 - Question 5

Only in A and C there is a steady increment in production of cotton as in D and E, It is decreased and in B production is equal for two years. Hence answer will be C.

Quantitative Aptitude - Test 12 - Question 6

Detailed Solution for Quantitative Aptitude - Test 12 - Question 6

Multiplying P inside whole equation will reduced to ((P + 1)3)1/3​ = (p + 1)
hence answer will be 125

Quantitative Aptitude - Test 12 - Question 7

If x = 2 + √3​, y = 2 − √3​, then the value of

Detailed Solution for Quantitative Aptitude - Test 12 - Question 7

as x + y = 4
and xy = 1
Now after putting values of x + y and xy and solving, we will get its value as 7/26.

Quantitative Aptitude - Test 12 - Question 8

If a2 + b2 + 4c2 = 2(a + b − 2c − 3) and a, b, c are real, then the value of (a2 + b2 + c2) is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 8

a2 + b2 + 4c2 = 2(a + b − 2c − 3)
So, (a − 1)2 + (b − 1)2 + (2c + 1)2 = 0
Or, a = 1, b = 1, c = −1​/2
So, a2 + b2 + c2 = 1 + 1 + 1/4 ​= 9/4

Quantitative Aptitude - Test 12 - Question 9

If x2 − 3x + 1, then value of

Detailed Solution for Quantitative Aptitude - Test 12 - Question 9

Given x2 − 3x + 1 = 0
or x2 − 3x = −1
or (x − 3) = −1/x

Now according to given question

After putting value of x + 1/x in above equation, it will get reduced to 10.

Quantitative Aptitude - Test 12 - Question 10

The sum of a non-zero number and thrice its reciprocal is 52/7. Find the number.

Detailed Solution for Quantitative Aptitude - Test 12 - Question 10

Let the number be x

According to ques,

=> 7x2 + 21 = 52x

=> 7x2 − 52x + 21 = 0

=> 7x2 − 49x − 3x + 21 = 0

=> 7x(x - 7) - 3(x - 7) = 0

=> (7x - 3)(x - 7) = 0

=> x = 7, 3/7

=> Ans - (C)

Quantitative Aptitude - Test 12 - Question 11

The product of two numbers is 45 and their difference is 4. The sum of squares of the two numbers is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 11

As we know (a − b)2 = a2 + b2 − 2ab
We assume that first number is a and second number is b hence ab = 45
and a - b = 4
after putting values we will get a2 + b= 106

Quantitative Aptitude - Test 12 - Question 12

In Δ ABC, ∠B = 90° and AB : BC = 2 : 1. The value of sin A + cot C is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 12

Given: ∠B = 90 and AB : BC = 2 : 1

To find: sin A + cot C = ?

Solution: Let AB = 2x and BC = x

In right △ABC

Now, sin A + cot C

Quantitative Aptitude - Test 12 - Question 13

In a rhombus ABCD, ∠A = 60° and AB = 12 cm. Then the diagonal BD is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 13

Given: ∠A = 60° and AB = 12 cm

To find: BD = ?

Solution: Since, all the sides of a rhombus are equal, => AB = AD

=> ∠ABD = ∠ADB

Now, in △ABD

=> ∠ABD + ∠ADB + ∠A = 180°

=> 2∠ABD = 120°

=> ∠ABD = ∠ADB = ∠A = 60°

=> ABD is equilateral triangle.

=> AB = AD = BD = 12 cm

Quantitative Aptitude - Test 12 - Question 14

If there are four lines in a plane, then what cannot be the number of points of intersection of these lines?

Detailed Solution for Quantitative Aptitude - Test 12 - Question 14

Maximum number of intersection points of n lines =

Thus, in a plane of 4 lines, maximum intersection points =

=> 7 is not possible.

=> Ans - (D)

Quantitative Aptitude - Test 12 - Question 15

The square root of 14 + 6√5

Detailed Solution for Quantitative Aptitude - Test 12 - Question 15

Given question can be written as 9 + 5 + 6√5​
or it will be square of 3 + √5​

Quantitative Aptitude - Test 12 - Question 16

The difference between the compound interest and simple interest for the amount Rs. 5,000 in 2 years is Rs.32. The rate of interest is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 16

Difference between compound interest and simple interest for 2 years will be
(where P is principal amount 5000 and r is rate )
after solving above equation we will get r = 8%

Quantitative Aptitude - Test 12 - Question 17

In what time will 8,000, at 3% per annum, produce the same interest as 6, 000 does in 5 years at 4 % simple interest?

Detailed Solution for Quantitative Aptitude - Test 12 - Question 17

It is given that Rs 6000 with interest 4% per annum (SI) produces an interest in 5 years =

= Rs 1200

Now the new principal amount is Rs 8000 and rate of interest is 3 % per annum. Let the time be T years in which same Rs 1200 will be generated as interest.

T = 5 years

Quantitative Aptitude - Test 12 - Question 18

The compound interest on a certain sum of money for 2 years at 5% per annum is 410. The simple interest on the same sum at the same rate and for the same time is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 18

We know that:

1. For first year, compound interest and simple interest is same if the principal amount and rate of interest is same in both cases.

2. From 2nd year onwards, the compound interest is normal interest plus the interest on accumulated amount due to interest until last cycle.

3. Every year simple interest remains same if Rate of Interest and principal amount remains same.

Let the compound interest for 1st year be Rs y

For two years, CI = Rs 410

y = 200

So for two years , Simple Interest = 200 + 200 = Rs 400

Quantitative Aptitude - Test 12 - Question 19

The compound interest on a certain sum of money at a certain rate per annum for two years is 2,050, and the simple interest on the same amount of money at the same rate for 3 years is 3, 000. Then the sum of money is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 19

let the sum of money be Rs P

And rate of interest = R %

It is given that for two years the Compound Interest = Rs 2050

As it is given that for 3 years the Simple Interest = Rs 3000 and we know that SI for every year is same so for 1st year

Simple interest = Rs 1000

For 1st year SI and CI are same if rate of interest and Principal amount is same and hence for 1st year CI = 1000

For 2 years the CI = 2050 = 1000 + 1000 + R/100 x 1000)

R = 5%

P = Rs 20000

Quantitative Aptitude - Test 12 - Question 20

The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 18% per annum is Rs 81. The sum is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 20

Let the given sum = Rs. 100x

Rate of interest = 18% and time period = 2 years

=> Difference between simple and compound interests =

∴ Value of given sum = 100 × 25 = Rs.2500

Quantitative Aptitude - Test 12 - Question 21

The H.C.F. and L.C.M. of, two numbers are 8 and 48 respectively. If one of the numbers is 24, then the other number is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 21

Given:
Numbers: First = 24
Second = x (suppose)
H.C.F. of numbers = 8
L.C.M. of numbers = 48
As we know:
H.C.F. * L.C.M. = Product of numbers
Hence
48 * 8 = 24 * x
x = 16

Quantitative Aptitude - Test 12 - Question 22

L.C.M. of two numbers is 120 and their H.C.F. is 10. Which of the following can be the sum of those two numbers?

Detailed Solution for Quantitative Aptitude - Test 12 - Question 22

We assume that numbers are hr1​ and hr2​ (where h = H.C.F. of numbers and r1​ and r2​ are prime factors)
So L.C.M. will be = hr1​r2​ = 120
or r1​r2​ = 12
So r1​ = 4 and r2​ = 3; numbers will be 40 and 30, sum is 70
or r1​ = 12 and r2​ = 1; numbers will be 120 and 10, sum is 130
Hence only option D justifies.

Quantitative Aptitude - Test 12 - Question 23

Two numbers are in the ratio 3 : 4. Their L.C.M. is 84. The greater number is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 23

Let the numbers be 3x, 4x
LCM of 3x and 4x is = 12x
So the number 84 is divisible by 12
84/12​ = 7
The numbers are 7x3 = 21 , 7x 4 = 28
The greatest number is 28

Quantitative Aptitude - Test 12 - Question 24

What is the HCF (highest common factor) of 57 and 513?

Detailed Solution for Quantitative Aptitude - Test 12 - Question 24

Factors of 57 = 1, 3, 19, 57

Factors of 513 = 1, 3, 9, 19, 27, 57, 171, 513

The common factors are = 1, 3, 19, 57

=> Highest common factor = 57

=> Ans - (B)

Quantitative Aptitude - Test 12 - Question 25

The sum of two numbers is 36 and their H.C.F and L.C.M. are 3 and 105 respectively. The sum of the reciprocals of two numbers is

Detailed Solution for Quantitative Aptitude - Test 12 - Question 25

Let's say numbers are x and y
hence sum of the reciprocals will be 1/x​ + 1/y​
or
as x + y = 36 (given)
and xy = HCF × LCM
= 3 × 105 = 315
after putting the values we will get summation of reciprocals equals to 4/35

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