Oxidizing and Reducing Reagents - Free MCQ Practice Test with solutions,

C4H8O  2° Alcohol, if we consider only carbonyl isomer.
We Will 2 ismoers as shown below.

Preparation of 3° alcohol from ketone and ester by the action of excess of a suitable Grignard reagent is carried out as shown below:

Here CH₃ will attack at C=O and dehydration will take pass and again water will attack at meta position as a nucleophile at the ring. PCC will covert -OH into = O.

NaBH₄ is mild reducing agent for this conversion. It is very effective for the reduction of aldehydes and ketones to alcohols. By itself, it will generally not reduce esters, carboxylic acids, or amides (although it will reduce acyl chlorides to alcohols).

Na/liq. NH₃ will give an effective reduction for the following case:

m-CPBA can convert ketone into amide and after ester hydrolysis it is reduced into phenol.

LiAlH₄ will reduce double bond into single bond and aldehyde group into alcohol.

Ph₃P = CH₂ will give the most effective transformation of ketone into alkene (Wittig reaction). The Wittig reaction is a popular method for the synthesis of alkene from ketones and aldehydes. The Wittig reagent can generally tolerate carbonyl compounds containing several kinds of functional groups such as OH, OR, aromatic nitro and even ester groups.

BF₃ increases the electrophilicity of carbonyl carbon due to which sulphur attacks on carbonyl carbon.

• Cyclohexene is a simple alkene, and the goal is to convert it into adipic acid, a dicarboxylic acid.


• Ozonolysis of alkenes breaks the double bond, forming carbonyl compounds. In this case, it cleaves the cyclohexene ring into two aldehyde groups.


• Subsequent oxidation with KMnO₄ converts these aldehyde groups into carboxylic acids.


• This two-step process effectively transforms cyclohexene into adipic acid, a 6-carbon diacid.


• Option A is the correct sequence: Ozonolysis followed by oxidation with KMnO₄.