CBSE Class 10  >  Class 10 Test  >  The Complete SAT Course  >  Test: Linear Equations in One Variable - 1 - Class 10 MCQ

Linear Equations in One Variable - 1 - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Linear Equations in One Variable - 1 (10 Questions)

You can prepare effectively for Class 10 The Complete SAT Course with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Linear Equations in One Variable - 1". These 10 questions have been designed by the experts with the latest curriculum of Class 10 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 10

Sign up on EduRev for free to attempt this test and track your preparation progress.

Test: Linear Equations in One Variable - 1 - Question 1

If 50 is subtracted from two-third of a number, the result is equal to sum of 40 and one-fourth of that number. What is the number?

Detailed Solution: Question 1

Let the number be x.

According to Question,

2x/3 - 50 = x/4 + 40

⇒ 5x/12 = 90

⇒ x = (90 x 12)/5

⇒ x = 216

∴ The number is 216.

Test: Linear Equations in One Variable - 1 - Question 2

A man has equal number of five, ten and twenty rupee notes amounting to Rs. 385. Find the total number of notes?

Detailed Solution: Question 2

Given:

Number of Five rupee note = Number of Ten rupee note = Number of Twenty rupee note

Calculation:

Let the equal number of five, ten and twenty rupee notes be x

⇒ 5x + 10x + 20x = 385

⇒ 35x = 385

⇒ x = 385/35 = 11

Total number of notes = 11 notes of Rs 5 + 11 notes of Rs 10 + 11 Rs of 20 =  33 notes

Check:

11 notes of Rs 5 + 11 notes of Rs 10 + 11 Rs of 20 = 11 × 5 + 11 × 10 + 11 × 20 = 55 + 110 + 220 = Rs. 385

Total number of notes = 11 × 3 = 33 

Therefore the correct answer is 33.
Alternate Method:

Since the number of Rs 5, Rs 10, and Rs 20 notes are equal, the ratio of the number of notes is = 1 ∶ 1 ∶ 1

Or, we can say, the total number of notes must be multiple of 3.

 Only two options are multiple of 3, others can be eliminated.

option 2 : 33. That means the number of notes of each dimension is 33/3 = 11.

5 × 11 + 11 × 10 + 11 × 20 = 385

∴ The total number of notes is 33.

Test: Linear Equations in One Variable - 1 - Question 3

If the sum and product of two numbers is 34 and 288 respectively, find the sum of their cubes.

Detailed Solution: Question 3

Let the numbers be ‘x’ and ‘y’

Given, sum = x + y = 34

Product = xy = 288

we need to find   x3 + y3

As we know, x3 + y3 = (x + y)3 – 3xy(x + y) = (x + y)[(x + y)2 – 3xy]

put the values of x + y and xy in to the equation

∴ Sum of their cubes = 34 × [(34)2 – 3 × 288] = 34 × (1156 – 864) = 34 × 292 = 9928

Test: Linear Equations in One Variable - 1 - Question 4

If x6 + x5 + x4 + x3 + x2 + x + 1 = 0, then find the value of x5054 + x6055 - 7

Detailed Solution: Question 4

Given:

x6 + x5 + x4 + x3 + x2 + x + 1 = 0

Calculation:

Considering the given equation

x6 + x5 + x4 + x3 + x2 + x + 1 = 0      -----(1)

In equation (1) multiplying by x

x7 + x6 + x5 + x4 + x3 + x2 + x = 0      -----(2)

Equation (2) – (1)

⇒ x7 - 1 = 0

⇒ x7 = 1

x5054 + x6055 - 7

⇒ (x7)722 + (x7)865 – 7

⇒ (1)722 + (1)865 – 7

⇒ 1 + 1 – 7

⇒ - 5

∴ Required value is – 5

Test: Linear Equations in One Variable - 1 - Question 5

Lata makes 20 kg paneer at home and sells it every morning. From one litre of milk, she makes 200 gms of paneer. The cost of a litre of milk is Rs. 40. How much money does she spend in procuring milk every day?

Detailed Solution: Question 5

⇒ Milk used to make 200 gms of panner = 1 litre

⇒ Milk used to make 20 kgs paneer = (20 × 1000/200) × 1 = 100 litre

⇒ Cost of 1 litre milk = Rs. 40

⇒ Cost of 100 litre Milk = 100 × 40 = Rs. 4000

Test: Linear Equations in One Variable - 1 - Question 6

In a group of 1300 students, every student reads 5 subjects and every subject is read by 65 students. The number of subjects are:

Detailed Solution: Question 6

Each of the 1300 students reads 5 subjects, so the total number of student-subject enrollments is 1300 × 5 = 6500.

Each subject is read by 65 students, so the number of different subjects equals 6500 ÷ 65 = 100

Therefore the number of subjects is exactly 100

So, Correct Option: A

Test: Linear Equations in One Variable - 1 - Question 7

When you reverse the digits of the number 13, the number increases by 18. How many other two‐digit numbers increase by 18 when their digits are reversed?

Detailed Solution: Question 7

Calculation:

Let the unit digit be x and tens digit be y

According to the question,

⇒ 10y + x - (10x + y) = 18

⇒ 9y - 9x = 18

⇒ y - x = 2

It means that difference of digits of two-digit numbers is 2.

∴ Six cases other than (13, 31) are possible

(24, 42) (35, 53) (46, 64) (57, 75) (68, 86) (79, 97)
Mistake Points:
Here we cannot take (20, 2)
Because 2 is not a two-digit number. Normally we do not write numbers from 1 - 9  as 01, 02, 03, 04, 05, 06, 07, 08, and 09.

Test: Linear Equations in One Variable - 1 - Question 8

The solution of equation 10x + 26 = 0 is a / an________.

Detailed Solution: Question 8

Given:

The given equation is 10x + 26 = 0

Concept:

Rational numbers are the numbers that can be written in the form of p/q, where q is not equal to zero. 

Calculation:

10x + 26 = 0

⇒ 10x = -26

⇒ x = (-26)/10

⇒ x = -13/5

∴ 10x + 26 = 0 is a rational number.

Test: Linear Equations in One Variable - 1 - Question 9

Difference of two numbers is 50% of the smaller number. If greater number is 120, then find sum of both numbers is:

Detailed Solution: Question 9

Given:

Greater number = 120

Calculation:

Let smaller number be x

According to the question

120 – x = x × (50/100)

⇒ 120 – x = x/2

⇒ 240 – 2x = x

⇒ x + 2x = 240

⇒ 3x = 240

⇒ x = 240/3

⇒ x = 80

∴ Sum of both numbers = 120 + 80 = 200

Test: Linear Equations in One Variable - 1 - Question 10

If x2 - 7x + 1 = 0 then find the value of (x + 1/x).

Detailed Solution: Question 10

Given:

x2 - 7x + 1 = 0

Calculation:

x2 - 7x + 1 = 0

Dividing by x:

⇒ x - 7 + 1/x = 0

⇒ x + 1/x = 7

∴ Value of x + 1/x = 7 

405 videos|220 docs|164 tests
Information about Test: Linear Equations in One Variable - 1 Page
In this test you can find the Exam questions for Test: Linear Equations in One Variable - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Linear Equations in One Variable - 1, EduRev gives you an ample number of Online tests for practice
405 videos|220 docs|164 tests
Download as PDF