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SSC Exam  >  SSC Tests  >  Test: Trigonometry ((त्रिकोणमिति) - 1 - SSC MCQ

Test: Trigonometry ((त्रिकोणमिति) - 1 - SSC MCQ


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10 Questions MCQ Test - Test: Trigonometry ((त्रिकोणमिति) - 1

Test: Trigonometry ((त्रिकोणमिति) - 1 for SSC 2024 is part of SSC preparation. The Test: Trigonometry ((त्रिकोणमिति) - 1 questions and answers have been prepared according to the SSC exam syllabus.The Test: Trigonometry ((त्रिकोणमिति) - 1 MCQs are made for SSC 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Trigonometry ((त्रिकोणमिति) - 1 below.
Solutions of Test: Trigonometry ((त्रिकोणमिति) - 1 questions in English are available as part of our course for SSC & Test: Trigonometry ((त्रिकोणमिति) - 1 solutions in Hindi for SSC course. Download more important topics, notes, lectures and mock test series for SSC Exam by signing up for free. Attempt Test: Trigonometry ((त्रिकोणमिति) - 1 | 10 questions in 10 minutes | Mock test for SSC preparation | Free important questions MCQ to study for SSC Exam | Download free PDF with solutions
Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 1
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यदि चक्रीय चतुर्भुज के कोण A, B, C तथा D हों, तब cos A + cos B + cos C + cos D का मान होगा

Detailed Solution for Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 1

cos A + cos B + cos C + cos D
= (cos A + cos C) + (cos B + cos D)
= 2 cos A + C / 2 cos A – C/ 2 + 2 cos B + D / 2 cos B + D / 2
= 0
(∴0 तथा 0 चक्रीय चतुर्भुज के आमने सामने के कोण हैं।)

Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 2
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यदि sin 54’0 = √5 + 1 / 4, तो sin 120 × sin 480 × sin 540 का मान होगा

Detailed Solution for Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 2

1/2⨯2 sin 12/0 sin 480 sin 540
= ½ [cos (480 – 120) – cos (480 + 120)] sin 540
= ½ (cos 360 – cos 600) sin 540
= 1 / 2 (√5 + 1 / 4 – 1 / 2) ⨯√5 + 1 / 4
= 1 / 2 ⨯√5 – 1 / 4 ⨯√5 + 1 / 4 = 1 / 8

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Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 3
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sin θ + sin 2θ / 1 + cos θ + cos 2 θ का मान बराबर है

Detailed Solution for Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 3

sin θ + sin 2θ / 1 + cos θ + cos 2 θ = sin θ + 2 sin θ cos θ / 1 + cos θ + 2 cos2 θ – 1
= sin θ (1 + 2 cos θ) / cos θ (1 + 2 cos θ) = tan θ

Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 4
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sin 75º – sin 15º/ cos 75º + cos 15º का मान होगा
Detailed Solution for Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 4

sin 75º – sin 15º / cos 75º + cos 15º
= 2 cos (75º + 150/2) sin (75º – 150/2) / 2 cos (75º + 150/2) cos (75º – 150 / 2)

Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 5
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cos 40° + cos 80° + cos 160° बराबर है
Detailed Solution for Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 5

2 cos 80° + 40° / 2 cos 80° – 400 / 2 + cos (180° – 200)
= 2 cos 60° cos 20° – cos 20°
= 2 ⨯1 / 2 cos 20° – cos 20° = 0

Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 6
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2 sin 105° sin 75° का मान है
Detailed Solution for Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 6

2 sin 105° sin 75°
= cos (105° sin 75° – cos (105° + 75°)
= cos 30° – cos 180°
= √3 / 2 – (-1) = √3 + 2 / 2

Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 7
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sin A + sin 3A + sin 5A / cos A + cos 3A + cos 5A का मान होगा
Detailed Solution for Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 7

sin A + sin 3A + sin 5A / cos A + cos 3A + cos 5A
= 2 sin 3A cos 2A + sin 3A / 2 cos 3A cos 2A + cos 3A
= sin 3A (2 cos 2 A + 1) / cos 3A (2 cos 2 A + 1)

Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 8
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cot A – tan A / cot A + tan A का मान बराबर होगा
Detailed Solution for Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 8

cos A + tan / cot A + tan A = cos A / sin A – sin A / cos A / cos A / sin A + sin A / cos A
= cos2 A – sin2 A / cos2 A + sin2 A = cos 2A

Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 9
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cos A = ½, तो tan 2 A का मान होगा
Detailed Solution for Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 9

दिया है, cos A = ½ = cos 60°
⟹A = 60°
tan 2A + tan (2 ⨯ 60°)
= tan 120°
= – √3

Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 10
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cos 20° + cos 100° + cos 140° + cos 90° का मान बराबर है
Detailed Solution for Test: Trigonometry ((त्रिकोणमिति) - 1 - Question 10

cos 20° + cos 100° + cos 140° + cos 90°
= 2 cos 60° cos 40° + cos 140° + 0
= cos 40° + cos 140°
= 2 cos 90° cos 50° = 0

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