Test: Decimals - Grade 10 MCQ

Hence, required sum is 5118.28215 .

(0.009 ÷ ?) + (0.007 ÷ 0.07) + (0.04 ÷ 0.4) = 0.3

⇒ ? = 0.009 × 10
⇒ ? = 0.09
∴ The value of "?" is 0.09

Calculation:
7.2491 divided by 0.071

⇒ 102.1
∴ 7.2491 divided by 0.071 gives 102.1

Calculation:

933.58 - 317.31 = 864.84 - ?

⇒ 616.27 = 864.84 - ?

⇒ ? = 864.84 - 616.27

⇒ ? = 248.57

∴ The value of ? is 248.57

Calculation:

0.126 × 0.0232

⇒ 126 × 10^-3 × 232 × 10^-4

⇒ 126 × 232 × 10^{-3 - 4}

⇒ 29232 × 10^-7

⇒ 0.0029232

Since,
a² - b² = (a - b) ( a + b)

⇒ 0.9 × 0.7 = 0.63

Given expression,

(81.84 + 118.16) ÷ 5³ = 1.2 × 2 + ?

⇒ 200 ÷ 5³ = 1.2 × 2 + ?

⇒ 200 ÷ 125 = 1.2 × 2 +?

⇒ 1.6 = 2.4 + ?

⇒ ? = -0.8

1132.757 – 2315.996 – 1753.829 + 2 × 2846.639

= 1133 – 2316 – 1754 + 5694

= (1133 + 5694) – (2316 + 1754 )

= 6827 – 4070

= 2757

Calculations:

0.36 of 52.5 + ? of 35 = 57.4

⇒ 18.9 + ? of 35 = 57.4

⇒ ? of 35 = (57.4 − 18.9)

⇒ ? = 38.5/35 

⇒ ? = 1.1

Given:

 {(.98)³ + (0.02)³ + 3 × 0.98 × 0.02 – 1}

Concept used:

(a + b)³ = a³ + b³ + 3ab(a + b)

Calculation:

{(.98)³ + (0.02)³ + 3 × 0.98 × 0.02 – 1

⇒ [(.98)³ + (0.02)³ + 3 × 0.98 × 0.02(0.98 + 0.02)} – 1]

Now, first term is of the form (a + b)³ where a = .98 and b = 0.02

⇒ (0.98 + 0.02)³ – 1 = 1 – 1 = 0

∴ The value is 0.